JEE Main 2015 cutoffs, rank predictor
The JEE Main 2015 offline Paper I was held
on 4th April, 2015. Nearly 11 lakh candidates appeared for this paper (out of
the 13 lakh applicants who registered for JEE Main 2015). Now, you must be
wondering about the likely cutoff score in JEE Main 2015 for being eligible to
appear in the JEE Advanced 2015 exam. In this article, let us discuss the
cutoff score in JEE Main 2015 and let us look at the rank prediction for JEE
Main 2015.
JEE
Main 2015 cutoffs:
We at PaGaLGuY spoke to a lot of students
to understand their experience and also analysed the paper ourselves. Based on
this analysis, we have come out with a precise estimate of the cutoff in JEE
Main 2015. As per our analysis of JEE
Main 2015, the cutoff score for eligibility to appear in JEE Advanced 2015
should be around 118-120 for General category candidates, 75-77 for OBC, 55-57
for SC and 50 to 53 for ST category candidates. Do note that this is our
estimate of the cutoff. The actual cutoffs may vary from the predicted cutoffs
by +/- 5 marks.
JEE
Main 2015 Rank Predictor:
Based on our analysis of students’ expected
scores, we have also created a list of scores that a student needs to get in
order to have a good chance of getting a high All India Rank in JEE Main 2015.
This list is presented here:
Score in JEE Main 2015 Likely Rank in JEE Main 2015
320 + in
top 100
300 – 320 101
– 200
290 – 300 201
– 500
270 – 290 501
– 1000
250 – 270 1001
– 2000
230 – 250 2001
– 5000
210 – 230 5001
– 10000
190 – 210 10001
– 20000
170 – 190 20001
– 35000
140 – 170 35001
– 50000
120 – 140 50001
– 75000
less than 120 > 75000
Do note that this list assumes that a
student’s performance in his board exams is proportional to his performance in
the JEE Main exam. Since a student’s All India Rank is dependent on his
performance in the board exams as well, hence, better performance in the board
exams would push up the student’s All India Rank and vice versa.
The All India Rank of each student is
calculated on the basis of the student’s performance in the JEE Main and his
performance in his board exams. In order to calculate a student’s rank, first
of all, his composite score is calculated using the formula:
C = 0.6 * JEE Main score + 0.4 * Normalized
board performance, where C is the composite score.
Each student’s rank is then calculated on
the basis of this composite score.
Now that you know the expected cutoffs and
your expected ranks, you can plan and prepare better for the future.
To get answers to all your queries, concerns, doubts regarding JEE Main 2015 and other exams, click here!
All the Best!