Soln please
Solution is 2. Why can't it be 1?
A sum of Rs. P is to be repaid in two equal annual installments of Rs. 14520 each at 10% p.a with interest being compounded annually. Another sum of Rs. Q is to be repaid at the same rate of simple interest in two equal annual installments of Rs. 14520. What is the difference between P and Q (in Rs. ) ? __________
41 Solution
Imagine that a family has two children, one of whom we know to be a boy. What then is the probability that the other child is a boy?
Three numbers are selected from first 9 natural numbers. What is the probability that the product of the numbers is divisible by 10?
a+b+c+d=25 if a>b>c>d how many non negative solution exist
the lines y=3x and x+y+40 and the x axis bound a triangluar region. find the total number of points on or inside this triangle with integral co-ordinates.
a,b,c,d.... till k are points, spaced on the circumference of a circle in that order. what is the sum of all the corner angles of the star formed by joining the points aeibfjcgkdha- in that order?
Q) Consider four digit numbers for which the first two digits are equal and the last two digits are also equal. How many such numbers are perfect squares?
(a) 4 (b) 0 (c) 1 (d) 3 (e) 2
Thought process:A number of students got stuck on this question for over five to seven minutes in the exam, since they tried to find out the squares of all two-digit numbers starting from 32. However, if one is well aware of the logic of finding squares of two digit numbers, one would realise that only three two-digit numbers after 32 have the last two digits in their squares equal (38, 62 and 88). Hence, there is no need to check any other numbers apart from these three. After checking these one would get the square of 88 as 7744. And hence, there is only one such number.
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now could somebody pleasae explain the logic of finding the squares mentioned in line 3 ?
thanks...
Chotu, the little maths genius found out that for every 'n' digit number (n > 2), there is atleast one number which when multiplied by 4 gives the number with the same digits in the reverse order. He has found one such five-digit number with distinct digits. What is the sum of the digits of that five-digit number? A) 18 B) 27 C) 36 D) No such number exists
exactly three of the interior anlges of a convex polygon are obtuse. what is the maximumnumber of sidesof such a polygon?
Please help with this question -
http://www.clipular.com/c/4644784778248192.png?k=llsAUXReiO34R2gasRhiRazePNQ
How I was appraoching this question is -
Sa / Sp = 10 / 6.4 (When d is constant, speed is inversely proportional to time)
Also Sa * 6.4 = d
Now relative speed of both Amy and Pamy is 1.64*Sa
Therefore 1.64*Sa* t = Sa*6.4 = > t = 6.4/1.64 = 3.9 which is the wrong answer.
What's wrong with my approach ?
How many obtuse-angled triangles can be formed such that the sum of the lengths of the sides of the triangle is 12 cm and the length of each side is an integer value (when expressed in cm)?
|x|+|y|+|z|=15..find no. Of solutions
All natural numbers from 1 to 125 (in decimal system) are written in base 7. How many of these numbers will contain the digit 1?
Directions for questions 5 to 7: Answer the questions on the basis of the information given below:
The annual sugarcane production (in million tonnes) in Meethagaon for the period 2000-2006 is shown in the bar graph given below.
Q.6
The sugarcane production in Meethagaon in the year 2007 increases by 15% over the year 2006. What is the approximate compounded annual growth rate of sugarcane production in Meethagaon over the period 2004-2007?a 19%b 17%c 16%d 18%
Solution:
Can anybody please help me with this question of CAT 2003,please explain how will I calculate length of B1B2
In a circle, the height of an arc is 21 cm and the diameter is 84 cm. Find the chord of half of the arc ?
OA:42CM
a cat on seeing a dog 100 m away turns around and start running away at 24 kmph. the dog spots him one minute later and start chasing the cat at a speed of 33 kmph. after how much time from the start of the cat's run will the chase end