@gudda1122 said: A jar contained a mixture of two liquids A and B in the ratio 4:1. When 10 litres of the mixture was taken out and 10 litres of liquid of B was poured into the jar. this ratio became 2:3 The quantity of liquid A contained in the jar initially wasa 4 ltb 8l tc 16 ltd 40 lt
@gudda1122 secA + root(sec2A - 1) = 2
(2-secA)^2 = sec2A -1
4 - 4secA = -1
4secA = 5
secA = 5/4
[ sec2A = (secA)^2 ]
@sampras said:-1/2 ????
@gudda1122 said: In a fleet of a certain car-renting agency the ratio of the number of sedans to the number of hatchbacks was 9:8. If after the addition of 3 sedans and 1 hatchback, this ratio rose to 6:5, how many more sedans than hatchbacks does the agency have now?(A) 2(B) 3(C) 5(D) 7(E) 9 ans-5
@gudda1122 said: In a fleet of a certain car-renting agency the ratio of the number of sedans to the number of hatchbacks was 9:8. If after the addition of 3 sedans and 1 hatchback, this ratio rose to 6:5, how many more sedans than hatchbacks does the agency have now?(A) 2(B) 3(C) 5(D) 7(E) 9
(2Y+1)^2 + 8
min value of sq is 0.
hence, 0+8=8
Q. two houses are collinear with the base of a tower and are at dist 3m and 12 m from the base of tower. The ang of elevation from these two houses of the top of the tower are complimentary. What is the height of the tower?
@alkoszzz said: @watsnew24 dont waste time on formula...apne hi method se kar...my suggestion...
@gudda1122 said: €Ž4^1/3, 3^1/2, 25^1/6, 289^12 ...Arrange in Descending Orderyeh question type aa sakta hai paper mein
Unit digit 6