CHSL & FCI PREPARATION

Jobs & Careers
204
@watsnew24 said:
check q again ye Y kaha se aa gaya q me kahi nhi hai aur z bhi

@vikyrims said:
1. xz/(x+z)
2. xz/2(x-z)
3. xz/2(z-x)
4. 2xz/(x+z)
sorry miss ho gaya...
a^x=b^y=c^z and b^2=ac then y=?
205
@vikyrims .......its 4
206
@vikyrims said: @watsnew24 said:
check q again ye Y kaha se aa gaya q me kahi nhi hai aur z bhi
sorry miss ho gaya...
a^x=b^y=c^z and b^2=ac then y=?
4th option

2xz/(x+z)
207
@watsnew24 said:
4th option2xz/(x+z)
explain it please...
208
@vikyrims said:
explain it please...


take all options equal to k a costant & then solve

a^x = k

b^y = k

c^z = k........ now solve
209
@watsnew24 said:
take all options equal to k a costant & then solvea^x = kb^y = kc^z = k........ now solve
solved it...thnx
210
@vikyrims said: @watsnew24 said:
check q again ye Y kaha se aa gaya q me kahi nhi hai aur z bhi
sorry miss ho gaya...
a^x=b^y=c^z and b^2=ac then y=?
my take 4...........
211
@watsnew24 koi ni dost..koi na koi palanhaar aayenge apne... :)
212
@lalit6600 yes..n its behen
213
@vikyrims said:
it is 115
yes
214
@vikyrims said:
it is 2
it is 2 & -1
215
@coolparul007 said:
is it -1 and 2 ??
yes
216
@coolparul007 yes
217
@watsnew24 can u please elaborate d explaination

i m not abld to understand this
218
@watsnew24 said:
take all options equal to k a costant & then solvea^x = kb^y = kc^z = k........ now solve
Can you explain how to solve it .
219
@custom said:
@watsnew24 can u please elaborate d explaination
i m not abld to understand this

kaun sa bhai
220

hello

221
@lalitrana said: hello
@watsnew24 said:
check q again ye Y kaha se aa gaya q me kahi nhi hai aur z bhiyeh vaa bhai jisme aapne query ki thi
222
@watsnew24
@vikyrims said: @watsnew24 said:
check q again ye Y kaha se aa gaya q me kahi nhi hai aur z bhi
sorry miss ho gaya...
a^x=b^y=c^z and b^2=ac then y=?
yeh vala bhai
223
@custom said:
@watsnew24
yeh vala bha




a^x=b^y=c^z=k(say)
now, a= k^1/x, b= k^1/y, c=k^1/z

b^2=ac
=> k^2/y= (k^1/x)(k^1/z)
=> 2/y=1/x+1/z
=> 2/y=(z+x)/zx
=> y= 2xz/(z+x)...