@pavi.k from where you got this questions?? SSC generally do not ask for 15 degree in Height and distance question.
@anticipator.lad
i got it in some model paper.. i also got 24m.. but it says 24 rt 2 .. so jus wanted to check out with yo puys..
@pavi.k Please keep posting questions. As this thread is not that much active, post questions in bulk. So that once in a day we can check and solve all queries.
1.Two pillars of equal height are on the either side of a 100 m wide road. The angle of elevation of top of the pillars are 60 deg and 30 deg at a point on the road between the pillars. The position of the point between the pillars is...
a) 75 m from first pillar
b) 50 m from first pillar
c) 25 m from ist pillar
d) none of these
2) A water melon weighs 2500 gm. 99% of its weight is water. it is kept in a drying room and after some time it turns out that it is only 98% water by weight. now the weight in grams is..
a) 1250
b) 2450
c) 2000
d) 1200
post the steps for this question
3) A reduction of 25% in the price of bananas enables a customer to buy 2 dozen more for rs 60. The original price per dozen is...
1) 25 m from first pillar
2) 2500 gm ----> 99% water and 1% flesh===> 1% of 2500= 25gm
After drying 98% water & 2% flesh;
Whatever weight in grams is changing, it is changing in water portion. No change in flesh weigh in grams i.e. 25gms is constant
so 2% of required weight = 25 gms
required weight = 25 * 100/2 = 1250 gms is the current weight after drying process.
3) Original Price = Rs 10
Any shortcut method? please explain.
FCI-2012 Tier-2
@anticipator.lad said:Any shortcut method? please explain.FCI-2012 Tier-2substitute dese values n getSin^6 x+ cos^6 x=(sin^2 x)^3 +(cos^2 x)^3 =(sin^4 x+ cos^4 x +sin^2 x.cos^2 x)Sin^4 x+ cos^4 x=(sin^2 x+cos^2 x)^2 -2sin^2 x . cos^2 x=1-2sin^2 x . cos^2 x(Sinx-cosx)^4 =(sinx+cosx)^2 . (sinx+cox)^2
sorry from my side for not being here actually mistake a big one will try to be here from now on thanx
@watsnew24 said:Dear all starting this new thread for CHSL & FCI preparation.......Hope all of us will conquer the Respective exams & will come out as generation X of this Government jobPost any query & discussion & we all will be more than happy to help you require suggestion & helps from all fellow puys....CHEERS & ATB
great bhai... old one was getting messy for those who dint qualified.. like me..
Puys wat is CHSL xam about? I hv filled FCI but not CSHL.. Is the last date over for filling the form?
@nehatakkar said:Puys wat is CHSL xam about? I hv filled FCI but not CSHL.. Is the last date over for filling the form?
Combined higher secondary exam (12 level) & yes last date gone
@anticipator.lad said:Any shortcut method? please explain.FCI-2012 Tier-2
hi bro.. got an easiest way to solve this question..
let x=0 or 90.
i m assuming x=0
sin0=0
cos0=1
(sin0-cos0)= -1
sin0 + cos0= 1
(sin^6 0) = (sin0)^6
thus (sin^0)6 + (cos0)^6= 1
now put the value in equation.
3(-1)^4 + 6(1) + 4(1)
3+6+4=13
was i able to explain properly?
and i hope this is the easiest possible way to solve these kind of questions in exam.
If i m wrong please let me know.
let x=0 or 90.
i m assuming x=0
sin0=0
cos0=1
(sin0-cos0)= -1
sin0 + cos0= 1
(sin^6 0) = (sin0)^6
thus (sin^0)6 + (cos0)^6= 1
now put the value in equation.
3(-1)^4 + 6(1) + 4(1)
3+6+4=13
was i able to explain properly?
and i hope this is the easiest possible way to solve these kind of questions in exam.
If i m wrong please let me know.
@coolparul007 said:
parul please have a look at my solution.. you might find it more easy .. well your solution is also ok but you need to solve as soon as possible in exams.
@surajpandey well when it is not mentioned in question that anles are not equal to 90 or 0 it is easiest method