CHSL & FCI PREPARATION

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yeh @surajpandey ji ka fb mein post kara Q/A hai

X and Y are centres of circles of radii 9 cm and 2 cm respectively , XY =17 cm . Z is the centre of a circle of radious r cm which touches the above circles externally. given that angle XYZ = 90 degree . the value of r is.,,,,,,,,,,,,,,......options are:- (A) 13
(B) 6 cm (C) 9cm (D) 8cm

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yeh@rahulpandey ji ka fb mein post kara ques hai

two circles touches each othe externally at P. AB is direct common tangent to the two circles, A and B are the point of contacts and angl PAB = 35 then angl ABP = ?
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@bhanuRawat ji ka
mein post kara ques hai
suppose abc is a tiangle right angled at A where angle A = 90 degree. and AD perpendicular to BC . if triangle ABC = 40 cm^2 , triangle ACD = 10 cm^2 and AC= 9 cm .then the length of BC is .....................options are (A) 12 (B) 8 (C) 4 and (D) 6....................
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@coolparul007 said:
@bhanuRawat ji ka
mein post kara ques hai
suppose abc is a tiangle right angled at A where angle A = 90 degree. and AD perpendicular to BC . if triangle ABC = 40 cm^2 , triangle ACD = 10 cm^2 and AC= 9 cm .then the length of BC is .....................options are (A) 12 (B) 8 (C) 4 and (D) 6....................
As AC = 9 cm and BC= Hypoteneus. BC will always be greater than AC. IN options there is only value i.ie. 12cm.
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@coolparul007 said:
yeh@rahulpandey ji ka fb mein post kara ques hai
two circles touches each othe externally at P. AB is direct common tangent to the two circles, A and B are the point of contacts and angl PAB = 35 then angl ABP = ?
My take 55 degree.... ye log option kyu nahi dete
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@anticipator.lad said:
As AC = 9 cm and BC= Hypoteneus. BC will always be greater than AC. IN options there is only value i.ie. 12cm.
wow...........meien socha hi nhi .........
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@anticipator.lad said:
My take 55 degree.... ye log option kyu nahi dete
plz explain aapne kaise solve kara

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@anticipator.lad said:
My take 55 degree.... ye log option kyu nahi dete
got it.......ek quadrilateral bana ke solve ho jayega
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@coolparul007 said:
plz explain aapne kaise solve kara
Property :- two circles touches each other externally at P. AB is direct common tangent to the two circles, A and B are the point of contacts then angle APB is always 90 degree.

APB + ABP + PAB= 180

90+ ABP + 35 = 180

ABP= 55
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@anticipator.lad said:
Property :- two circles touches each other externally at P. AB is direct common tangent to the two circles, A and B are the point of contacts then angle APB is always 90 degree.
APB + ABP + PAB= 180
90+ ABP + 35 = 180
ABP= 55
yeh bhi theek hai meine quadrilateral bana ke solve kr liya
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@coolparul007 Please share the quad way...
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take O n O' as centres of 2 circles.......suppose O centre of having A as a point of contact u will get LAOP = 70( alternate segment theorem n central angle theorem) similarly LBO'P=2x
in quadrilatertal AOO'B u will get the answer

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@anticipator.lad meine suna hai ki next yr CGL subjective hoga.......
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gotta go puys..........i ll be back

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@coolparul007 said:
@anticipator.lad meine suna hai ki next yr CGL subjective hoga.......
Its a rumor. Dont go with it.

Fact denies its probability of happening:- 12 lakhs + students were appeared in CGL-12, out of which 1.21 Lakhs + got selected for Tier-2

UPSC- Prelims is objective because of many applicants. and followed by Subjective Mains of only 12000 candidates which takes them 2-3 months to out the final result.

By this scenario you should consider the fact that its never gonna happen with SSC. Please do not go with such rumours.
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@anticipator.lad said:
Its a rumor. Dont go with it.
Fact denies its probability of happening:- 12 lakhs + students were appeared in CGL-12, out of which 1.21 Lakhs + got selected for Tier-2
UPSC- Prelims is objective because of many applicants. and followed by Subjective Mains of only 12000 candidates which takes them 2-3 months to out the final result.
By this scenario you should consider the fact that its never gonna happen with SSC. Please do not go with such rumours.
thanx...........i was shocked
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@anticipator.lad said:
As AC = 9 cm and BC= Hypoteneus. BC will always be greater than AC. IN options there is only value i.ie. 12cm.
Hahahaa...this question bhanu asked for getting sure of representations. Answer given by SSC is 6 and ...moreover answer which this question gives is not at all in the options.

Correct Answer is 18.

Solution:- ABC and ACD are similar triangle by A-S-A rule.

So, AB/CD = BC/ AC

As are of triangles are given we have to use property that :- If triangle are similar then the ratios of their areas are equal to ratios of squares of sides.

i.e. Ar. ABC/ Ar. ACD = BC^2 / AC^2

So 40/10 = BC^2/ 81 which gives BC = 18 cm.


Sorry for misguiding you about 12 cm concept.
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@surajpandey bhai chhota-cut bata.

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@anticipator.lad said:
1. 1 rad= (180/ pi) degrees
gives 1/2 rad= 90/pi
1/3 rad= 60/pi
so by law of triangle; 90/pi+60pi+x=180
x= 132.272727
0.090909 = 1/11
0.181818 = 2/11
0.272727 = 3/11
sp x= 132 3/11
2. Make right angle triangle with degree x by using 2 given equations
so sides will be rt3, 1 and, p will become hypotenuse.
Apply Pythagoras theorem on these 3 sides, p^2 = 1^2 + rt3^2 which gives p=2
3. sec x = cosecx...by given equation
hence x=45 degree
Put value of x in secx+cosecx = rt2 +rt2= 2rt2
ab batao tum apna shortcut...specially for Question.1
namste bhaiya...
kya baat ! kya baat ! kya baat!
bahut badhia ... aapka 1st wala sahi hai, 2nd bhi and 3rd liked most.
q3.
anycan can blindly trust on 3rd cos that was the shortest method.


Q2
I think yeh question sabse chota tha paper mein it took only 10 seconds for me to crack and mark answer.
psinx=rt3
pcosx=1

only watch sinx=rt3/p if you are rembered the tble than you know that we get only one value in which rt is used. rght? i.e rt3/2

so p could be none other than 2.

incase you have doubt same could be seen with cos=1/p [sin60= rt3/2]
cos60= 1/2


woah again satisfying the equation.

Q1
yar yeh toh aapka hi thik hai in anyway it willtake 1 mins atleast.

nice attempts. mein aajkal trigo hi kar raha hu..so ache question aaj bhi post karunga.



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@surajpandey holy-poly-roly-moly.... second wala tune gajab dha diya bhai....

respect!!