CHSL & FCI PREPARATION

Jobs & Careers
590
@surajpandey said:
q 4, 5 and 6i dont think any question need to be translated.
Ques 4 => option b
series is given (1*1 + 2*2 +..... 10*10)
multiply 4 to series it becomes (2*2 + 4*4 + ..... 20*20) multiply both sides
therefore value = 385*4 = 1540

Ques 5 => option 4
(64^2 - 36^2)= 20*z
(100)(64-36) = 20*z
z= 5*28 = 140

Ques 6 => option 4
see for this u need to have a fair idea about powers of 2
now 320 lies near to 256 which is 2^8 and we also need some lower power of 2 ending in 4 which is 64 or 2^6
so x=7 can be infered from it
other way of doing this is lengthy involves letting 2^x= as a variable its better u should have idea of upto 10 powers of 2 and 6 powers of 3

591
@mukul1988 said:
Ques 4 => option b
series is given (1*1 + 2*2 +..... 10*10)
multiply 4 to series it becomes (2*2 + 4*4 + ..... 20*20) multiply both sides
therefore value = 385*4 = 1540Ques 5 => option 4
(64^2 - 36^2)= 20*z
(100)(64-36) = 20*z
z= 5*28 = 140Ques 6 => option
see for this u need to have a fair idea about powers of 2
now 320 lies near to 256 which is 2^8
4th and 5th as expected sahi hai...
6th - answer is 2^7
your answer is not true
here is the explanation

2^x * 2^(-1) + 2^x * 2^1 (aise likh sakte hai na?

now take 2^x common. ( 1/2 +2) = 320
2^x= (320*2)/5
2^x= 2^7
thus x=7
592

Q7: by dividing any number by 32 remainder is 29. dividing the same number by 8 will give you the remainder?
a 3
b 5
c 7
d none of these

593
@surajpandey said:
4th and 5th as expected sahi hai... 6th - answer is 2^7 your answer is not true here is the explanation2^x * 2^(-1) + 2^x * 2^1 (aise likh sakte hai na?now take 2^x common. ( 1/2 +2) = 320 2^x= (320*2)/5 2^x= 2^7 thus x=7
abe tab aadha hi reply kar diya tha poora check kar
594
@surajpandey said:
Q7: by dividing any number by 32 remainder is 29. dividing the same number by 8 will give you the remainder?
a 3
b 5
c 7
d none of these
option b
any number divisible by 32 will be divisble by 8 also we have to check for remainder only as 24 is multiple of 8. 5 will be left as remainder
595
@mukul1988 said:
option b any number divisible by 32 will be divisble by 8 also we have to check for remainder only as 24 is multiple of 8. 5 will be left as remainder
shabash yar... great... you havce great knowledge in number system.
incase you have some good question bhai... why dont you try to post?

596
@surajpandey said:
shabash yar... great... you havce great knowledge in number system. incase you have some good question bhai... why dont you try to post?
bhai bataya tha khud ki padhayi chalu karne ki himat nahi ho pa rahi hai abhi 15 ka wait kar raha hun kya pata kuch ho chamatkar ho jaaye jab chalu karunga tab pakka dalunga
597
@surajpandey said:
Q7: by dividing any number by 32 remainder is 29. dividing the same number by 8 will give you the remainder?
a 3
b 5
c 7
d none of these
b. 5

same remainder case- so 29/8

will give u 5 as remainder.
598
@mukul1988 said:Ques 6 => option 4
see for this u need to have a fair idea about powers of 2
now 320 lies near to 256 which is 2^8 and we also need some lower power of 2 ending in 4 which is 64 or 2^6
so x=7 can be infered from it
bhai yar yeah samjh nahi aaya... sahi se samjhao apna method?
599

Q8
dividing any number by 3 and 5 respectively we get 2 and 1 as a remainder. if we divide the same number by 15 then the reaminder is?
a 1
b 2
c 5
d 7

600
@surajpandey said:
bhai yar yeah samjh nahi aaya... sahi se samjhao apna method?
dhek 320 sum hai toh sabse pehle mere ko aise do power of 2 chahiye jo 320 se chote ho aur last digits 10 banati ho toh 320 ke pass chote 2 ke powers hai 256,128,64,32 baaki bahut chote ho gaye. ab dhek bas 256 aur 64 hi 300 ke aas pass hai
toh bas inki power check kar le ek ki 8 hai dusre ki 6
601
@surajpandey said:
Q8
dividing any number by 3 and 5 respectively we get 2 and 1 as a remainder. if we divide the same number by 15 then the reaminder is?
a 1
b 2
c 5
d 7
ye succesive division toh nahi hai ?

602
@mukul1988 said:
ye succesive division toh nahi hai ?
yes man... wahi hai..isme meri bhi fatti hai hamesha...:P
603
@surajpandey
@surajpandey said:
Q8
dividing any number by 3 and 5 respectively we get 2 and 1 as a remainder. if we divide the same number by 15 then the reaminder is?
a 1
b 2
c 5
d 7
604
@mukul1988 said:
dhek 320 sum hai toh sabse pehle mere ko aise do power of 2 chahiye jo 320 se chote ho aur last digits 10 banati ho toh 320 ke pass chote 2 ke powers hai 256,128,64,32 baaki bahut chote ho gaye. ab dhek bas 256 aur 64 hi 300 ke aas pass hai toh bas inki power check kar le ek ki 8 hai dusre ki 6
64 kaise hai 300 ke pass? and last digit 10 banati hai? yar you are vague in this question. @anticipator.lad bhai aapko samjh mein aa raha hai?
605
@surajpandey said:
Q8
dividing any number by 3 and 5 respectively we get 2 and 1 as a remainder. if we divide the same number by 15 then the reaminder is?
a 1
b 2
c 5
d 7
Iska answer hai c

606
@mukul1988 said:
Iska answer hai c
bhai is bar explanation kyun nahi dia? isme toh chaiye tha...
607
@surajpandey said:
64 kaise hai 300 ke pass? and last digit 10 banati hai? yar you are vague in this question. @anticipator.lad bhai aapko samjh mein aa raha hai?
abe dhek mere ko sum chahiye 320 haina ab agar tu 256 + 64 karega toh tere ko answer milega na ?
tu kewal 64 pe concentrate kar raha hai its a sum ek no 256 dusra 64
608
@lalit6600 said:
@surajpandey ............answer is 2
bhai jiska bhi answer likho please usko quote kar dia karo..isse confusion nahi hogi..
btw answer is not 2. 😞 try again and try to solve your methods here.
609
@surajpandey said:
bhai is bar explanation kyun nahi dia? isme toh chaiye tha...
bhai iska explanation bahut mast wala hai bana hi raha hun ruk successive division se kabhi nahi fategi