CHSL & FCI PREPARATION

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650
@surajpandey said:
Q107 answer is 597 99 *6 and add the rest [1/7 +2/7+--------6/7] 594 + [21/7] 594+3=597Q108 answer is 16 solt. 1st no. 33k +21 2nd no. 33k +28add them both i.e 66k +49 when you will divide 49/33 remainder is 16Q109 answer is c i.e 3 12x+12y = 84 [ as 12 is hcf so it will include in both the numbers] now x+y=7 1 and 6 2and 5 3 and 4so these 3 pairs could be the possiblity. remember the relationship between number should be as like co-primes. id any pair is 4 and 6 .. it wonbt work and wilnot be considered.
mast ho gaaya aaj tho
651
@mukul1988 said:
waise 2010 ke asaan the 2011 ke thode time consuming so on that trend 2012 main ......
aisa na bol bhai mar jayenge
652

CHSL 2011 + 2010 :- CORRECT ANSWERS.



102- C

103-B

104-D

105- D

107- D

108-D

109-B
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@custom said:
mast ho gaaya aaj tho
Bas aise hi mast ho jayenge bhai.. agar 3-4 jane roj question late rahe toh... :)
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@mukul1988 said:
waise 2010 ke asaan the 2011 ke thode time consuming so on that trend 2012 main ......
is it so.. i had no idea abt the trend... ;)
655
@anticipator.lad said:
To all those who say CHSL is easy. Please see the pattern and time you take to solve these questions. I guess this should be the eye-opener to you all guys that, level is not that much easy, as you were thinking. That is the only reason i posted the question paper questions.
They all are doable but are they doable 50 questions in 45 minutes. That's Matter!
My speed is very low. And we should be thankful to guys like @mukul1988 @custom to let us know the shortcut tricks
@surajpandey is putting an extra effort just for this forum. to scan and putting questions from the books, he doesnt have to do it, but still doing.
Silent readers , please wake up at least post questions for us. Dont just come, see and go.
NVM for those who has no guts to comeup ...
656
@custom said:
$ol is 5, 5k +1 as when divided by 5 ,1 is remainder . now 3(5k + 1 ) + 2 = 15 k + 5.
so when divided by 15 , 5 is remainder . puys hws d explaination.
i am confused ... you are dividing different no by 3 and 5 .

if I take k =1 , you are diving 6/5 to get R=1 and then 20/3 to get R=2 and 20/15 to get R=5 [ 3(k+1)+2 does not give R=1 diving by 3 ]


my ans is 11
657
@anticipator.lad said:
Sorry bhai galti ho gayi...answer is 10 rt3..... B option hai.. 17.32
Maine tera question update hi nahi dekha..
cos 30= BD/AB
=> AB= 30/ rt 3 = 10 rt3 = 17.32
right bro

658
If in certain code "BIND" is coded as "CLGB" & "HELD" is coded as "FDJB" based on the series given above how "FORK" will be coded ?
1- HGKU
2- UPKR
3- KPSR
4- UPSR
5- UGSR
Give reason..
659
Q- what will come in place of ? in the following alphabetical series:
N PO BDE ?
1- UKR 2- SRKU 3- RKUF 4- QSRK 5- FUK
plz giv the reason...
660
HC" is related to "KQ" in a certain way. Similarly "OG" is related to "AB" in the same way. How "RK" is related following the same pattern.
1- TJ
2- SI
3- TL
4- HD
5- IM
Give reason..
661
@gautam7821 said:
i am confused ... you are dividing different no by 3 and 5 .
if I take k =1 , you are diving 6/5 to get R=1 and then 20/3 to get R=2 and 20/15 to get R=5 [ 3(k+1)+2 does not give R=1 diving by 3 ]
my ans is 11
hi friend.
11 is not in the answer.

we are not dividing the different number.think of it

what is dividend?
dividend= divisor*quotient +reaminder.................................. rght?
so on the first number . we wrote

number (3*k + 2)

well number is still the same but divisor is different now

number (5*k +1)

so its like that,... structring may be different but that number is same..difference is due to divisor.
662
@bumper said:
Q- what will come in place of ? in the following alphabetical series:
N PO BDE ?
1- UKR 2- SRKU 3- RKUF 4- QSRK 5- FUK
plz giv the reason...
yar bahut complicated haii.. exact logic toh nahi ban pa raha hai..but my take will ve RKUF option 3
663
1. solve this !!!
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
A. 12 days B. 15 days
C. 16 days D. 18 days
664
2. solve this!!!
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
A. 20 days B. 22 (1/2) days
C. 25 days D. 30 days

665
@surya003 ............bro it is 22(1/2)
666

its correct 22(1/2) days

667
@surya003 said:
1. solve this !!!
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
A. 12 days B. 15 days
C. 16 days D. 18 days
15 days


concept of time and work

b and c do work in 20 days

in three days A,B&C; do 1/5th of work

so total work takes 15 days

668
@lalit6600 can u xplain hw it is
669
@surya003 said:
1. solve this !!!
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
A. 12 days B. 15 days
C. 16 days D. 18 days
answer is B
i.e 15days..


it would be easy to solve this question with lcm method.. it took me 30 second to solve this.

LCM(TOTAL WORK) = 60
a's work per day= 3
b's work per day =2
c's work per day =1

first day= 3 work os done
2nd day= 3 work again
3rd day = 6 work is done [3(a) +2(b) + 1(c)]


in 3 days 12 work is done. now total work is 60
so it will take 3*5 times= 15 days in total to complete all the 60 work.