@surajpandey said:bhaiyoowhat do you think what will the paper level this time in CHSL.like CGL mein maths mein CAT KI barabari karli...kya CHSL mein bhi yahi ummeed kare?
CHSL- "Umeed se saje zindagi" heahahhaa!!!
Let A and B be two solid spheres such that the surface area of B is 300% higher than the surface area of A. The volume of A is found to be k% lower than the volume of B. The value of k must be
1. 85.5
2. 92.5
3. 90.5
4. 87.5
@pavi.k said:Let A and B be two solid spheres such that the surface area of B is 300% higher than the surface area of A. The volume of A is found to be k% lower than the volume of B. The value of k must be1. 85.52. 92.53. 90.54. 87.5
yar main toh usko solve nahi karunga.
lekin answer sirf 87.5 ho sakta hai..
kyunki yeh standard hai
7/8 bolte hai isse.
baki ka kuch nahi ban raha..batao thik hai ya nahi?
lekin answer sirf 87.5 ho sakta hai..
kyunki yeh standard hai
7/8 bolte hai isse.
baki ka kuch nahi ban raha..batao thik hai ya nahi?
any link for previous years question papers of FCI.........????
@pavi.k said:@gautam7821Rajiv housing loan scheme is soon to be launched as said by PM in independence day speech..
thanks for info ..
Why is the thread dead ??
A group of man decided to do a job in 8 days . But since 10 men dropped out every day , the job got completed at the end of 12th day. How many men were there at the beginning ?
a.165
b.175
c.80
d.90
@pavi.k said:Let A and B be two solid spheres such that the surface area of B is 300% higher than the surface area of A. The volume of A is found to be k% lower than the volume of B. The value of k must be1. 85.52. 92.53. 90.54. 87.5
Let a be the radius of the Sphere A and let b be the radius of the Sphere B
Then, (4*pi*b^2 - 4*pi*a^2)/(4*pi*a^2)*100 = 300, or, b=2a..(i)
Again, (4/3*pi*b^3 - 4*pi*a^3)/(4/3*pi*b^3)*100 = k, or, 7/8*100 = k
Thus, K=87.5
@gautam7821 said:Why is the thread dead ??A group of man decided to do a job in 8 days . But since 10 men dropped out every day , the job got completed at the end of 12th day. How many men were there at the beginning ?a.165b.175c.80d.90
Let there be n number of man, each having r unit/day as the rate of work
Then, Total work=8*n*r units.
Now, Amount of work done in 1st day=n*r units
Amount of work done in 2nd day=(n-10)*r units
.
.
.
Amount of work done in 12th day=(n-110)*r units
Thus, nr + nr - 10r + nr -20r +......+nr - 110r = 8nr
=> 12n - 660 = 8n
=>4n = 660
=>n=165..
@pyashraj said:Let a be the radius of the Sphere A and let b be the radius of the Sphere BThen, (4*pi*b^2 - 4*pi*a^2)/(4*pi*a^2)*100 = 300, or, b=2a..(i)Again, (4/3*pi*b^3 - 4*pi*a^3)/(4/3*pi*b^3)*100 = k, or, 7/8*100 = kThus, K=87.5Let there be n number of man, each having r unit/day as the rate of workThen, Total work=8*n*r units.Now, Amount of work done in 1st day=n*r unitsAmount of work done in 2nd day=(n-10)*r units...Amount of work done in 12th day=(n-110)*r unitsThus, nr + nr - 10r + nr -20r +......+nr - 110r = 8nr=> 12n - 660 = 8n=>4n = 660=>n=175..
165!
@pyashraj said:Let there be n number of man, each having r unit/day as the rate of workThen, Total work=8*n*r units.Now, Amount of work done in 1st day=n*r unitsAmount of work done in 2nd day=(n-10)*r units...Amount of work done in 12th day=(n-110)*r unitsThus, nr + nr - 10r + nr -20r +......+nr - 110r = 8nr=> 12n - 660 = 8n=>4n = 660=>n=165..
Thanks .. Any short cut method ??
@gautam7821 said:Thanks .. Any short cut method ??
Another way is using follwing formula :-
(M*D*H)/W = (M1*D1*H1)/W1 + (M2*D2*H2)/W2 + (M3*D3*H3)/W3 + ....
Applying it to our case:-
8x=x*1 + (x-10)*1 + (x-20)*1 + ..... + (x-110)*1
8x=12x - 660
x=165
Cheers!
@harshsingal27 said:Another way is using follwing formula :-(M*D*H)/W = (M1*D1*H1)/W1 + (M2*D2*H2)/W2 + (M3*D3*H3)/W3 + ....Applying it to our case:-8x=x*1 + (x-10)*1 + (x-20)*1 + ..... + (x-110)*18x=12x - 660x=165Cheers!
Thank you ..
Please post your date and centre of CHSL. So that help and suggestions can reach you, if its on later dates.
Mine is 21/10/2012... Centre- Raipur
@anticipator.lad said:Please post your date and centre of CHSL. So that help and suggestions can reach you, if its on later dates.Mine is 21/10/2012... Centre- Raipur
my exam date is 28/10/2012........ centre - kanpur
@anuragtomar said:my exam date is 28/10/2012........ centre - kanpur
Bhai, you have been selected in CGL-TA, atleast ye post to chhod deta hum logo ke liye :P
and as u were asking-300 marks-UR-Pref all states- mein possibility after clearing DEST... South side-states is waiting for u, and that is for sure. just clear the DEST!
@anticipator.lad said:Bhai, you have been selected in CGL-TA, atleast ye post to chhod deta hum logo ke liyeand as u were asking-300 marks-UR-Pref all states- mein possibility after clearing DEST... South side-states is waiting for u, and that is for sure. just clear the DEST!
thanks anticipator bhai apke sabdo ko sun kar bada accha laga kyuki abhi tak sabhi ne yahi kaha ki nahi hoga sirf tumne hi kaha ho jayega thanks again
@anuragtomar said:thanks anticipator bhai apke sabdo ko sun kar bada accha laga kyuki abhi tak sabhi ne yahi kaha ki nahi hoga sirf tumne hi kaha ho jayega thanks again
Do not listen to all. You have to do, what you need to do. Clear DEST first. And as you have filled all states, you will get one seat out of 1500+