CHSL & FCI PREPARATION

@eJ. said:
Hello, will anybody share last yr's FCI assistant-III level-1 exam ques paper??I just want to see the format. Help me, friends.
http://epaper.jagranjosh.com/57528/Josh-Magazine/SSC-FCI-Assistant-Grade-3-Exam-2012-Solved-Question-Paper#page/1/1
@minus said:
hi id relly appreciate it if i could get your consensus on this. this questian's for every1 who might have appeared for the chsl exam on 21st oct did u guys think that paper was easier comparitively speaking or was it of the same standard as before or was it much tougher this time ???and what about the math section how did that fair in comparison previous ssc paperswhat acc to u guys should be the cutoff??thanks every1
Please wait for 2 more days, as few of our friends are having paper tomorrow, they will share it by tomorrow eve or positively by day after tomorrow...then we will get the best scenario (analysis) out of it.....
@srinivasdonkada said:
Last year FCI ka dead easy bro..lets see any idea how many are writing
is baar vacancies bhi zyaada hai...level to last yr se high hi hoga..........sry no idea about candidates.............
@anticipator.lad said:
haan ji, aisa hi kuch scenario ban gaya hai, bcoz of exponential raise in number of candidates.
ok...........posts bhi jyaada hain is baar..........

@coolparul007 said:
is baar vacancies bhi zyaada hai...level to last yr se high hi hoga..........sry no idea about candidates.............
 Bhai hope the paper is not upto CGL level tougher this time around
@srinivasdonkada said:
Bhai hope the paper is not upto CGL level tougher this time around
Please expect the CGL T-1 paper and FCI T-1 paper of same level, then only you will be able to solve.


@anticipator.lad said:
Please expect the CGL T-1 paper and FCI T-1 paper of same level, then only you will be able to solve.
 Ya u r right bro have to expect the same level paper of sure...

(4^61 + 4^62 + 4^63) is divisible by

(3 (11 (13 (17
approach plz

@minus said:
(4^61 + 4^62 + 4^63) is divisible by(3 (11 (13 (17approach plz
 Please say wether answer is 3 or not
@anticipator.lad alright friend fair enough althou i do feel that whenever it is that we do begin to discuss the level of this years paper we should bear in mind that calling a paper easy or difficult is an obsolete idea when because this is quite subjective we should prolly try and figure out if the time required by this years paper was more than the other ones
@srinivasdonkada yeah it is 3
can u tell me how u solved this friend


@minus said:
@srinivasdonkada yeah it is 3 can u tell me how u solved this friend
 Bro i added 4^1+4^2+4^3=84 which is only divisible be 3 from the given options

@minus said:
@srinivasdonkada yeah it is 3 can u tell me how u solved this friend
 i dont know wether my procedure is correct or not
@srinivasdonkada but what about the remaining 4^60
@srinivasdonkada alrite well i understand that if you tale 4^60 AS common ure left with 84 within the braces but and this has to be divisible by 3 but why can't that be also divisible by other options

bhai where is 4^60 in the question?

@minus said:
@srinivasdonkada alrite well i understand that if you tale 4^60 AS common ure left with 84 within the braces but and this has to be divisible by 3 but why can't that be also divisible by other options
 
@srinivasdonkada are dude you take that common na 4^60 and within the braces u're left with 4 4 + 4^2 + 4^3
4^60 (4 + 4^2 + 4^3)
do u get my point

see 4^1=4, 4^2=16, 4^3=64, 4^4=256....see bhai for every 2 squares the last digits repeat ....so for 4^60  60 is divisible by 2 and for 4^61 again start with 4 as last digit so i did as 4^1+4^2+4^3 bro...hope u understand..

that i know but i dont feel that this suffices as proof for this ans