4^61 se divisible nai hai
are u getting my point sir
@custom bhai baat samajhne ki koshish karo me mana nahi kar raha ki 3 se divisible nahi hai me ye keh raha hoon ki aap ye kaise keh sakte ho ki baki ke teen option me se koi bhi option
@anticipator.lad bhai kitabo se matha phod phod ke pehle to almost sari sense khatam ho gai hai dusra jo bachi hai wo common ni reh gai abnormal ho gai hai 
let n be the greatest no that will divide 1305 4665 and 6905 leaving the same remainder in each case then sum of the digits of n ???
(4 (5
(6 (8
@minus said:let n be the greatest no that will divide 1305 4665 and 6905 leaving the same remainder in each case then sum of the digits of n ???(4 (5(6 (8
answer is 4...
x=1305
y=4665 and
z=6905
HCF of |(x-y), (y-z) and (z-x)| is 1120.... 1+1+2+0=4
care to elaborate friend i didnt relly understand that
i mean the (x-y), (y-z) and (z-x)| is 1120.
@minus
@minus said:(4^61 + 4^62 + 4^63) is divisible by(3 (11 (13 (17approach plz
bhaiya approach yeh hai ki x*y mai tumne no. divide kar liya
from previous post
x= 4^61
y = 21
as from the option we check only part 2 nd
3 as 21 is divisible 3
so it will be3
@minus said:@anticipator.lad is that some kind of formula ?
Yes, it is the formula. You have to memorise it.
This formula is applicable only in case of "greatest no that will divide 1305 4665 and 6905 leaving the same remainder in each case".
Mod values of (x-y), (y-z) and (z-x) will be 3360. 2240 & 5500....so we have to find HCF of these numbers now...and that will be 1120....
@custom bhai baat samajhne ki koshish karo me mana nahi kar raha ki 3 se divisible nahi hai ye 3 se divisible hai par me ye keh raha hoon ki aap ye kaise keh sakte ho ki baki ke teen option me se koi bhi option4^61 ko divide nahi karega
ek bar dhyan se pado jo me keh raha hoon
are u getting my point sir
ek bar dhyan se pado jo me keh raha hoon
are u getting my point sir
@anticipator.lad thanx for clearing it up bro
any other imp questians from this topic u could think of ?
@minus please check the previous posts in the same CHSL thread...puys have discussed many questions on similar topic.
(x-y), (y-z) and (z-x) agar inme se koi negative nikle to to uska mod lena hai right ?
@minus said:(x-y), (y-z) and (z-x) agar inme se koi negative nikle to to uska mod lena hai right ?
yes...
cool aur koi questian that might be imp ?
@minus said:(x-y), (y-z) and (z-x) agar inme se koi negative nikle to to uska mod lena hai right ?
Question am asking you, is out of no where but still i want to ask , which book you referring?
cbse and online forums
how's bout ureself man
oh and past papers ofcourse
@anticipator.lad i still need ure opinion on today's and 4th nov's paper do u think it would be of the same level as the one from 21'st
considering that ssc has adopted the scaling system
@minus said:@anticipator.lad i still need ure opinion on today's and 4th nov's paper do u think it would be of the same level as the one from 21'st considering that ssc has adopted the scaling system
You should buy RS Aggarwal or M.Tyra for Maths....and solve it twice or thrice.
Level of difficulty always increases in such scenario.
Same All India exam-both shifts-3 different dates...