@brixcel said:One question.
options plz ??
join AC...............
@lalit6600 said:join AC...............now area of triangle ADC=1/2 x AE x DC (AB = DC)thrfore area = 1/2 x AE x ABalso area of triangle ADC= 1/2 x AD x FCequate both and put the value of AE,AB and FC.....u will get the answer
yaar FCI ka xam 10 ko hai ya 11 ko ??
yahaan koi aisa b hai kya jiske admit card me date 10 novembr likhi ho ?
@Meenaamit.iiitm said:yaar FCI ka xam 10 ko hai ya 11 ko ??yahaan koi aisa b hai kya jiske admit card me date 10 novembr likhi ho ?
@lalit6600 said:join AC...............now area of triangle ADC=1/2 x AE x DC (AB = DC)thrfore area = 1/2 x AE x ABalso area of triangle ADC= 1/2 x AD x FCequate both and put the value of AE,AB and FC.....u will get the answer
@Meenaamit.iiitm said:yaar FCI ka xam 10 ko hai ya 11 ko ??yahaan koi aisa b hai kya jiske admit card me date 10 novembr likhi ho ?
@brixcel said:One question.
@minus said:really ???whicj region ?
@lalit6600 said:@brixcel .....u hv exam on tenth............gr8 then do us a favour............give the exam review on 10th night pls
@brixcel said:North region. Sure buddy. #thinking-what-would-it-be-all-like-if-I-return-disappointed-from-the-centre.
fci me pipes and cisterns zaroor aega
@Meenaamit.iiitm said:10 ko hi jana padega fir to , btw u r from which region ??
@minus said:i think i speak for every1 when i say i know how you feel hehe
and You all will not be here by then If I happen to post it the same day.
@anticipator.lad said:CD/CF = AD/AE (Similar triangle concept)CD=ABSo, 16/10= AD/8 => AD=12.8
@brixcel said:One question.
@anuragtomar said:pallelogram's area is hight*base.so ab*ae = ad* cf 16*8 = ad*10ad = 12.8 try this one