If, on a coordinate plane, point A has the coordinates (-3,4), how far is point A from point E?
1) Point E is on the Y axis four units from the origin.
2) If point A were twice as far from point E, it would be the distance from point E as point C is at coordinates (0,-2)
1. E is (0, 4) or (0, -4) . Insuff on its own
2. 2AE = CE, where C(0,-2) (this gives an equation of a circle) Insuff on its own.
Combined together, sufficient
Is X greater than Y?
1. X - Y > X - |Y
2. X|>X AND |Y=Y
2. x > x only when x is -ve = y when y is non-negative. Therefore y > x, sufficient.
1. y - y > x - x
Consider 4 possible cases.
(+ve, +ve) Invalid
(-ve, -ve) y (-ve, +ve) 0 > -2x or x is +ve, Invalid
(+ve, -ve) -2y > 0 or y
In other words, the above inequality holds true when y
Sufficient on its own.
D
If k is a positive constant and y = x - k - |x + k, what is the maximum value of y?
(1) x
(2) k = 3
==-k=====0=====k==
y is max, when it is +ve. iow, the point x should be on the negative side. Then, y becomes the distance between -k and k, which is 2k.
---x===-k===0===k---
(1) is not required; and useless as well.
(2) k = 3; sufficient on its own.
B is the answer
x is an integer and x raised to any odd integer is greater than zero; is w - z greater than 5 times the quantity 7^x-1 - 5^x?
- z
- x = 4
Let A = 5* 7^(x-1) - 5*5^x + z - w, fine whether A > 0 or 0 or
1. A = 7^(x-1) - 5^x - 7^x - (25 - epsilon)
A = -2.7^(x-1) - 25.5^(x-1) - (25-epsilon)
When x >=1, A Since x^odd > 0, it means x is a positive integer.
Sufficient on its own.
A is the answer.
What is the remainder of a positive integer N when it is divided by 2?
- N contains odd numbers as factors
- N is a multiple of 15
N contains odd numbers as factors. In which case, N is odd. Sufficient.
A is the answer.
Or if (1) is restated as N contains odd number of factors. In which case, N is a perfect square. Insufficient. In this case, E is the answer.
Q2: On the number line shown, is 0 halfway between r and s ?
1) s is to the right of 0.
2) The distance between t and r is the same as the distance between t and -s.
(This is a number line with r, s and t placed on it)
2. t-r = t+s, find whether r+s = 0
square it, t^2 + r^2 - 2rt = t^2 + s^2 + 2ts
(r+s)(r-s-2t) = 0
either r+s = 0 or r - s = 2t
r-s = 2t --> r-t = t -s. In other words, t gotta be in between r and s.
The diagram shows that t is not in between and r and s.
Therefore r - s ??????>?>?>?> 2t. therefore, r +s = 0. Sufficient.
Answer is B
Q2: On the number line shown, is 0 halfway between r and s ?
1) s is to the right of 0.
2) The distance between t and r is the same as the distance between t and -s.
(This is a number line with r, s and t placed on it)
2. t-r = t+s, find whether r+s = 0
square it, t^2 + r^2 - 2rt = t^2 + s^2 + 2ts
(r+s)(r-s-2t) = 0
either r+s = 0 or r - s = 2t
r-s = 2t --> r-t = t -s. In other words, t gotta be in between r and s.
The diagram shows that t is not in between and r and s.
Therefore r - s 2t. therefore, r +s = 0. Sufficient.
Answer is B
Hey Statement in bold is incorrect ...
Check the solution here :
http://www.pagalguy.com/forum/gmat-and-related-discussions/20702-gmat-data-sufficiency-discussions-203.html#post1698626
Hope that helps !
Hey Statement in bold is incorrect ...
Check the solution here :
http://www.pagalguy.com/forum/gmat-and-related-discussions/20702-gmat-data-sufficiency-discussions-203.html#post1698626
Hope that helps !
Thanks, I know where I made a mistake.
I can't conclude "t has to be in between s and t" when r - s = 2t, unless r, s, and t have same signs. This assumption is not given in (2).
Q. Is x^4 + y^4 > z^4 ?
a) x^2 + y^2 > z^2
b) x+ y > z
let x/z =a, y/z =b
Is a^4 + b^4 > 1
1. a^2 + b^2 > 1
2. a + b > 1
1. a^2 + b^2 > 1 ==> a^4 + b^4 > 1 - 2 a^2 b^2.
There are cases where a^4 + b^4
2. a + b > 1, a^2 + b^2 > 1 - 2ab, a^4 + b^4 > 1 + 2a^2 b^2 - 4ab
Insufficient because of "-4ab"
Combining together gives a^2 + b^2 > 1 - 2ab. Insuff.
E
I found this question in OG 12th edition.
My question is:
what is the perimeter of an isosceles triangle MNP?
1. MN = 16
2. NP = 20
now the answer given for this question is E. But now the perimeter is
P = MN + MP + NP = 2MN + NP
with 1 alone we cannot get the answer, but with 1 & 2 we can easily get the answer by applying the basic theorem "The sum of the lengths of any two sides of a triangle must be greater than the third side." So aint the answer C?
Am I making sense?
P.S:I am new to this site and this is my first post. If am not followign any conventional rules of this forum, kindly excuse.
My question is:
what is the perimeter of an isosceles triangle MNP?
1. MN = 16
2. NP = 20
now the answer given for this question is E. But now the perimeter is
P = MN + MP + NP = 2MN + NP
with 1 alone we cannot get the answer, but with 1 & 2 we can easily get the answer by applying the basic theorem "The sum of the lengths of any two sides of a triangle must be greater than the third side." So aint the answer C?
Am I making sense?
P.S:I am new to this site and this is my first post. If am not followign any conventional rules of this forum, kindly excuse.
my answer is E because from the 2 statement it is not mention that which 2 sides are equal.. it may either equal to MN or Np..
But how do you know that MN is the isosceles side??? It can be other side too..
I mean perimeter can be 16+16+20 or 20+20+16. both are equally correct... So E!!
I found this question in OG 12th edition.
My question is:
what is the perimeter of an isosceles triangle MNP?
1. MN = 16
2. NP = 20
now the answer given for this question is E. But now the perimeter is
P = MN + MP + NP = 2MN + NP
with 1 alone we cannot get the answer, but with 1 & 2 we can easily get the answer by applying the basic theorem "The sum of the lengths of any two sides of a triangle must be greater than the third side." So aint the answer C?
Am I making sense?
P.S:I am new to this site and this is my first post. If am not followign any conventional rules of this forum, kindly excuse.
How many integers n are there such that r
How many integers n are there such that r
IMO Ans C ...
St 1 : if r and s are integers, there are another 4 integers between them.
Eg 4 int between 5 and 10
If r and s are not integers then there are 5 integers between them
Eg 5 int between 4.5 and 9.5
Not suff...
St 2 : tells us nothing ..not suff ...
Combined : there have to be 5 integers between r and s ...suff
Ans C
IMO Ans C ...
St 1 : if r and s are integers, there are another 4 integers between them.
Eg 4 int between 5 and 10
If r and s are not integers then there are 5 integers between them
Eg 5 int between 4.5 and 9.5
Not suff...
St 2 : tells us nothing ..not suff ...
Combined : there have to be 5 integers between r and s ...suff
Ans C
Thanks. the OA is C.
when i solved couldn't understand why there are 4 int b/w 5 and 10. and5 b/w 4.5 and 9.5.
thanks for explaining.
Regards,
Neha
Hi Puys, This question already been explained before but I couldn't understand the explanation given. Please help me out. Thanks for the help.
Is mod (x)
(1) mod (x + 1) = 2 mod (x - 1)
(2) mod (x - 3) 0
Is it A?
Hi Puys, This question already been explained before but I couldn't understand the explanation given. Please help me out. Thanks for the help.
Is mod (x)
(1) mod (x + 1) = 2 mod (x - 1)
(2) mod (x - 3) 0
Is it A?
No ..it cant be A ...It has to be C ..
We need to check if -1
St 1 : On solvng, either x = 3 OR x =1/3 ...not suff ...
St 2 : just tells us x is not 3 ...not suff ..
Combined : x=1/3 ...suff ..Ans C
Over a holiday weekend, a certain car dealer sold off the cars on its lot. If the cars sold for an
average of $6,000 each, how many cars were on the dealers lot at the beginning of the weekend?
(1) The average value of the remaining cars on the lot is $5,000.
(2) The car dealer made $48,000 in car sales over the weekend.
explanation :B. Given statement (1) alone, we only know average values of both the cars that were sold and the cars that remained;
With statement (2), we are able to find the number of cars sold by dividing the total sales by the
average price. 48,000/6,000 = 8, so the dealer sold 8 cars. Since that is 4/5
of the cars on the lot,
the dealer started off with 10 cars. Statement (2) is sufficient, so the answer is B.
from where does this 4/5 funda come??
Is the ques complete or there is more to it?
check whether you have written the complete ques or not.
There has to a relation b/w the no of cars sold off and no of cars at the beginning of the weekend.
Over a holiday weekend, a certain car dealer sold off the cars on its lot. If the cars sold for an
average of $6,000 each, how many cars were on the dealer's lot at the beginning of the weekend?
(1) The average value of the remaining cars on the lot is $5,000.
(2) The car dealer made $48,000 in car sales over the weekend.
explanation :B. Given statement (1) alone, we only know average values of both the cars that were sold and the cars that remained;
With statement (2), we are able to find the number of cars sold by dividing the total sales by the
average price. 48,000/6,000 = 8, so the dealer sold 8 cars. Since that is 4/5
of the cars on the lot,
the dealer started off with 10 cars. Statement (2) is sufficient, so the answer is B.
from where does this 4/5 funda come??
Is the ques complete or there is more to it?
check whether you have written the complete ques or not.
There has to a relation b/w the no of cars sold off and no of cars at the beginning of the weekend.
hi neha
Q. is complete as far as it is given in the book
this is from tmh gmat book
actually this weekend i was starting quant n was looking for some good option to get started, so for the time being i started with tmh.
i scored 44 in gmat prep test 1 quant sec without any preparation so i guess quant is not a very big hurdle
so could u plz suggest me some good strategy for quant
i mean i need a decent book/ material which covers all the concepts.