Some more
What is the value of 5 r ?
(1) 4 r = 64
(2) r4 = 81
If k is a positive integer, is k a multiple of 40?
(1) k is a multiple of 4.
(2) k is a multiple of 10.
Sorry Q 1 is
What is the value of 5 r ?
(1) 4 ^ r = 64
(2) r^4 = 81
Sorry Q 1 is
What is the value of 5 r ?
(1) 4 ^ r = 64
(2) r^4 = 81
Prime Nos between 69 and 80 are : - 71 73 79
Now (1) with 73 and 79 we get 2 primes - 67 and 73 , thus no unique value Insuff
take (2) this again indicates 2 values : - 71 73 Insuff
Combining 73 is only prime satisfying both
C
Yes answer is C
Sorry Q 1 is
What is the value of 5 r ?
(1) 4 ^ r = 64
(2) r^4 = 81
My Ans is A
With 1 - 4^3 = 64
AND R = 3 and 5r = 15
With 2 - (+/- 3) ^ 4 = 81
r = +/ - 3
5 r = +/- 15 Insuff
Hence A
1) 4^r=64, so r has got to be 3.
r^4=81, r can be +3 or -3.
so the answer is A
2) any multiple of 4 need not be a multiple of 40 ex: 8,16
same wth 10. any multiple of 10 need not be a multiple of 40 ex: 20
taking both into acount, any number which is a multiple of both 4 & 10 is also a multiple of 40.
4*10*x=k
so the answer is C
Sorry Q 1 is
What is the value of 5 r ?
(1) 4 ^ r = 64
(2) r^4 = 81
1) 4^r=64, so r has got to be 3.
r^4=81, r can be +3 or -3.
so the answer is A
2) any multiple of 4 need not be a multiple of 40 ex: 8,16
same wth 10. any multiple of 10 need not be a multiple of 40 ex: 20
taking both into acount, any number which is a multiple of both 4 & 10 is also a multiple of 40.
4*10*x=k
so the answer is C
I differ with the bold statement as highlighted. Take 20 , its divisible by 4 and divisible by 10 but not divisble by 40..So u cant make this assumption. Only if factors of a given number are mutually prime then only u can make this statement.
this one is from OG-10... i couldnt agree with solution actually.
Q) If x is a positive integer, is Sqrt x an integer?
1) sqrt(4x) is an integer
2) sqrt(3x) is not an integer
please post your explanations.
this one is from OG-10... i couldnt agree with solution actually.
Q) If x is a positive integer, is Sqrt x an integer?
1) sqrt(4x) is an integer
2) sqrt(3x) is not an integer
please post your explanations.
My answer is A
Stat 1: rt(4x)= rt(4) * rt(x)
= 2 * rt(x) which is an integer.
Hence rt(x) is an integer
Stat 2: rt(3x) = rt(3) * rt(x) ........ not an integer
Insufficient information
Whats the OA.
My answer is A
Stat 1: rt(4x)= rt(4) * rt(x)
= 2 * rt(x) which is an integer.
Hence rt(x) is an integer
Stat 2: rt(3x) = rt(3) * rt(x) ........ not an integer
Insufficient information
Whats the OA.
OA is A. You are right. but my question is if rt(4x)=say 9 which is integer
then 2* rt(x) = 9 and rt(x) = 9/2 which is not an integer... and rt(x) is an integer if rt(4x) = 8... is this line of thinking true? or some flaw??
OA is A. You are right. but my question is if rt(4x)=say 9 which is integer
then 2* rt(x) = 9 and rt(x) = 9/2 which is not an integer... and rt(x) is an integer if rt(4x) = 8... is this line of thinking true? or some flaw??
You cannot assume an odd integer to be the answer for rt(4x). It will always be even integer since x is getting multiplied by 4. A better way of looking at it would by assigning values to x which are square of positive integers
rt(4*1) = rt (4) = 2
rt(4*4) = rt (16) = 4
rt(4*9) = rt (36) = 6
so on...
Hope this helps.
You cannot assume an odd integer to be the answer for rt(4x). It will always be even integer since x is getting multiplied by 4. A better way of looking at it would by assigning values to x which are square of positive integers
rt(4*1) = rt (4) = 2
rt(4*4) = rt (16) = 4
rt(4*9) = rt (36) = 6
so on...
Hope this helps.
hello varun, thanks for explanation.
actually, its a silly error in my reasoning. I didnt read the question properly
, i should have considered that x is an integer, which solves ambiguity. thanks i should improve on paraphrasing the question well.
rohan_vus SaysI differ with the bold statement as highlighted. Take 20 , its divisible by 4 and divisible by 10 but not divisble by 40..So u cant make this assumption. Only if factors of a given number are mutually prime then only u can make this statement.
Yes thats the catch in the problem 20 divisible by 4 and 10 but not with 40
cgt2k1 SaysYes thats the catch in the problem 20 divisible by 4 and 10 but not with 40
yeepp....i got it wrong..seemed easy at the outset but a samll catch!!
Hi,
Can someone please explain me below questions ?
Directions : For questions in this section mark
(a) If condition (i) alone is sufficient
(b) If condition (ii) alone is sufficient
(c) If both conditions together are sufficient
(d) If condition (i) alone & (ii) alone are sufficient
(e) information not sufficient
1. How many rolls of wall paper are necessary to cover the walls of a room whose floor and ceiling are rectangles 12 feet wide and 15 feet long
(i) A roll of paper covers 20 sq feet
(ii) There are no windows in the walls
Ans: (e)
My problem : Why not (a) ? We can calculate area of ceiling plus four walls , and then number of rolls required.
2. How much does John weigh? Jim weighs 200 pounds.
(i) Toms weight plus Moes weight equal to Johns weight.
(ii) Johns weight plus Moes weight equal to Twice Toms weight.
Ans: (c)
My problem : In all , there are 4 persons , and in given choices , we are not referring to Jim at all.
T = M + J
J + M = 2 T J+M = 2( M+J) J+ M = 0 , that gives Ts age as 0 yrs which is unique value though 0 yrs .
Is my approach ok?
3) Is angle BAC is a right angle
(i) AB=2BC
(2) BC=1.5AC
Ans: (e)
4. Is x greater than y
(i) x=2k
(ii) k=2y
Ans: (e)
My problem : Why not( c) ?
5. What is the distance from A to B
(i) A is 15 miles from C
(2) C is 25 miles from B
Ans: (e)
My problem : why not (c ) ?
Source is : http://www.koolkareers.com/mba-preparation/data-sufficiency/data-sufficiency-ex-2/
Thanks.
Can someone please explain me below questions ?
Directions : For questions in this section mark
(a) If condition (i) alone is sufficient
(b) If condition (ii) alone is sufficient
(c) If both conditions together are sufficient
(d) If condition (i) alone & (ii) alone are sufficient
(e) information not sufficient
1. How many rolls of wall paper are necessary to cover the walls of a room whose floor and ceiling are rectangles 12 feet wide and 15 feet long
(i) A roll of paper covers 20 sq feet
(ii) There are no windows in the walls
Ans: (e)
My problem : Why not (a) ? We can calculate area of ceiling plus four walls , and then number of rolls required.
2. How much does John weigh? Jim weighs 200 pounds.
(i) Toms weight plus Moes weight equal to Johns weight.
(ii) Johns weight plus Moes weight equal to Twice Toms weight.
Ans: (c)
My problem : In all , there are 4 persons , and in given choices , we are not referring to Jim at all.
T = M + J
J + M = 2 T J+M = 2( M+J) J+ M = 0 , that gives Ts age as 0 yrs which is unique value though 0 yrs .
Is my approach ok?
3) Is angle BAC is a right angle
(i) AB=2BC
(2) BC=1.5AC
Ans: (e)
4. Is x greater than y
(i) x=2k
(ii) k=2y
Ans: (e)
My problem : Why not( c) ?
5. What is the distance from A to B
(i) A is 15 miles from C
(2) C is 25 miles from B
Ans: (e)
My problem : why not (c ) ?
Source is : http://www.koolkareers.com/mba-preparation/data-sufficiency/data-sufficiency-ex-2/
Thanks.
Hi,
Can someone please explain me below questions ?
Directions : For questions in this section mark
(a) If condition (i) alone is sufficient
(b) If condition (ii) alone is sufficient
(c) If both conditions together are sufficient
(d) If condition (i) alone & (ii) alone are sufficient
(e) information not sufficient
1. How many rolls of wall paper are necessary to cover the walls of a room whose floor and ceiling are rectangles 12 feet wide and 15 feet long
(i) A roll of paper covers 20 sq feet
(ii) There are no windows in the walls
Ans: (e)
My problem : Why not (a) ? We can calculate area of ceiling plus four walls , and then number of rolls required.
2. How much does John weigh? Jim weighs 200 pounds.
(i) Toms weight plus Moes weight equal to Johns weight.
(ii) Johns weight plus Moes weight equal to Twice Toms weight.
Ans: (c)
My problem : In all , there are 4 persons , and in given choices , we are not referring to Jim at all.
T = M + J
J + M = 2 T J+M = 2( M+J) J+ M = 0 , that gives Ts age as 0 yrs which is unique value though 0 yrs .
Is my approach ok?
3) Is angle BAC is a right angle
(i) AB=2BC
(2) BC=1.5AC
Ans: (e)
4. Is x greater than y
(i) x=2k
(ii) k=2y
Ans: (e)
My problem : Why not( c) ?
5. What is the distance from A to B
(i) A is 15 miles from C
(2) C is 25 miles from B
Ans: (e)
My problem : why not (c ) ?
Source is : http://www.koolkareers.com/mba-preparation/data-sufficiency/data-sufficiency-ex-2/
Thanks.
Q.1 Its asking to cover the walls, to know the area of walls you need length and breadth of the wall, which is not available here. From the length and breadth of ceiling or wall you can get only one parameter. HTH
Q.2 Its a typo I guess. As you get two eq and 3 unknowns. So, could not be solved.
Q.4 Using both we get x=4y; now nowhere its mentioned that x and y are +ve integer. so if you will substitute Y with +ve and -ve value you will get different answer, hence E.
Q.5 Their is possibility that either you can have arrangement of these as ACB or BAC, in both the cases AB will have diff value.
For q.3 I am not sure because if A is 90 degree than BC should be hyp. and hyp>perpendicular so from A it can be deduced that A is not right angle.
Hi,
Can someone please explain me below questions ?
Directions : For questions in this section mark
(a) If condition (i) alone is sufficient
(b) If condition (ii) alone is sufficient
(c) If both conditions together are sufficient
(d) If condition (i) alone & (ii) alone are sufficient
(e) information not sufficient
1. How many rolls of wall paper are necessary to cover the walls of a room whose floor and ceiling are rectangles 12 feet wide and 15 feet long
(i) A roll of paper covers 20 sq feet
(ii) There are no windows in the walls
Ans: (e)
My problem : Why not (a) ? We can calculate area of ceiling plus four walls , and then number of rolls required.
2. How much does John weigh? Jim weighs 200 pounds.
(i) Toms weight plus Moes weight equal to Johns weight.
(ii) Johns weight plus Moes weight equal to Twice Toms weight.
Ans: (c)
My problem : In all , there are 4 persons , and in given choices , we are not referring to Jim at all.
T = M + J
J + M = 2 T J+M = 2( M+J) J+ M = 0 , that gives Ts age as 0 yrs which is unique value though 0 yrs .
Is my approach ok?
3) Is angle BAC is a right angle
(i) AB=2BC
(2) BC=1.5AC
Ans: (e)
4. Is x greater than y
(i) x=2k
(ii) k=2y
Ans: (e)
My problem : Why not( c) ?
5. What is the distance from A to B
(i) A is 15 miles from C
(2) C is 25 miles from B
Ans: (e)
My problem : why not (c ) ?
Source is : http://www.koolkareers.com/mba-preparation/data-sufficiency/data-sufficiency-ex-2/
Thanks.
Question 3: The answer is E.
If we assume a value of 2 for AC, then BC will be 3 and AB will be 6.
This will not form a triangle because for a triangle the sum of two sides should always be more than the third side. So one cannot determine the angle being formed by BAC. Hence E
Q. If z1, z2, z3....zn is a series of consecutive positive integers, is the sum of all the integers in this series odd?
(1) (z1+z2+z3......zn)/ n is an odd integer.
(2) n is odd.
Will post the answer later.
The Ans is "C"
1. probable soln can be 27/3=9 or 18/6=3 ::: hence no ans.
2.'n' cannot decide the summation of the numerator.
Combining the 2 : we get oddXodd i.e an ODD.
Hence we have an ANS now..
Hope this expl is OK.
The Ans is "C"
1. probable soln can be 27/3=9 or 18/6=3 ::: hence no ans.
2.'n' cannot decide the summation of the numerator.
Combining the 2 : we get oddXodd i.e an ODD.
Hence we have an ANS now..
Hope this expl is OK.
The OA is A. Here is the explanation.
Stat 1: It states that the average is an odd integer. It is important to know that the average of sum of even consecutive integers cannot be an integer. Which implies that there are odd number of integers which multiplied by the average which is also odd will result in an odd number. Hence this statement is sufficient.
Stat 2: a series with odd number of characters can have a sum which is even and odd.
Eg. 1,2,3 = 6 and 2,3,4 = 9 hence insufficient.
1. If x > 0, is x/y > x ?
(1) 0 y
(2) x > 1
(1) 0 y
(2) x > 1
1. If x > 0, is x/y > x ?
(1) 0 y
(2) x > 1
OA : (A) 1st option is sufficient to answer the question
