GMAT Data Sufficiency Discussions

So here is my explanation of A being the right answer.

Given: x is integer. x raised to an Odd number gives us >0. This means x>0.

Stem: Is w-z> 5(7^(x-1)-5^x) ?

1. z
Substituting the value of w in question stem, we get.

Is 7^x - z > 5.7^(x-1) - 5^(x+1) ?

Solving,

Is 2.7^(x-1) + 5^(x+1) > z ?

Now, we are given that x>0, thus min possible value of x =1

Substitute x=1

Is 27> z ?

We are given that z


2. x=4

Even if we substitute this value in the question stem, we have no clue about w and z. Thus Insufficient.


Hence the answer A.



Could anyone please post the explaination for q2. IMO Answer should be B

Could anyone please post the explaination for

If w, x, y, and z are the digits of the four-digit number N, a positive integer, what is the remainder when N is divided by 9?
a)w + x + y + z = 13
b)N + 5 is divisible by 9

Could anyone please post the explaination for

If w, x, y, and z are the digits of the four-digit number N, a positive integer, what is the remainder when N is divided by 9?
a)w + x + y + z = 13
b)N + 5 is divisible by 9


1) remainder will be 4 clearly.So sufficient
2) Taking some e.g for N=9940%9 = 4
N=9976%9 = 4.So sufficient


I will go with option D.

-Deepak.
he has wriiten -x = 3x-2 (so LHS is -0.5)

since x = 3x-2

either x = 2-3x
(which gives x=0.5)

or

x=3x-2 (which gives us x=1)

my take - E


for your equation1: you first assume x
Could anyone please post the explaination for

If w, x, y, and z are the digits of the four-digit number N, a positive integer, what is the remainder when N is divided by 9?
a)w + x + y + z = 13
b)N + 5 is divisible by 9

Divisibility test for 9 is : The sum of the digits of the number should be divisible by 3 & 9 both.
From statement 1: If w+x+y+z = 13. Not divisible by 3 & 9 both.
So the remainder is 13/9 ; Rem 4. (Sufficient)

from statement 2: N+5 is divisible then N/9 will leave remainder 9-5 = 4 (Sufficient)


Correct choice D
.
Could anyone please post the explaination for

If w, x, y, and z are the digits of the four-digit number N, a positive integer, what is the remainder when N is divided by 9?
a)w + x + y + z = 13
b)N + 5 is divisible by 9



stmt 1 : sufficient

stmt 2: sufficient

so option D )

Thanks all fro the response.

@Gail : " So the remainder is 13/9 ; Rem 4"
Thanks

Thanks all fro the response.

@Gail : " So the remainder is 13/9 ; Rem 4"
Thanks


The above rule also holds good for 3.

-Deepak.

For positive integer k, is the expression (k + 2)(k2 + 4k + 3) divisible by 4?

(1) k is divisible by 8.

(2) (k + 1)/3 is an odd integer.



In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d

(2) Sq.Rt(a^2) + Sq.Rt(b^2) = Sq.Rt(c^2) + Sq.Rt(d^2)

For positive integer k, is the expression (k + 2)(k2 + 4k + 3) divisible by 4?

(1) k is divisible by 8.

(2) (k + 1)/3 is an odd integer.



In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d

(2) Sq.Rt(a^2) + Sq.Rt(b^2) = Sq.Rt(c^2) + Sq.Rt(d^2)




Qno.1:
=====
The expr can be modified as (k+1) (k+2) (k+3)

statement 1 : k=8...so the expr becomes 9*10*11....nt divisible by 4
: k=16...so the expr becomes 17*18*19 ..nt divisible by 4.

So suff.

Statement 2 : eg. K+1 /3 = 3..So K = 10...expr becomes 11*12*13...divisible by 4
k+1/3 = 5...so k = 16..expr becomes 17*18*19...nt divisible by 4.

So,I will go with option A


Qno2:
====
statement 1 : let the points be (1,1) (2,2)..they are not equidistant from origin
let the points be (1,1) (-1,-1)...they are equidistant from origin...


statement 2 :clearly both the points are equidistant from origin..


So,I will go with option B.

-Deepak.
For Q.1., OA is (A)
For Q.2., OA is (C)

Qno.1:
=====
The expr can be modified as (k+1) (k+2) (k+3)

statement 1 : k=8...so the expr becomes 9*10*11....nt divisible by 4
: k=16...so the expr becomes 17*18*19 ..nt divisible by 4.

So suff.

Statement 2 : eg. K+1 /3 = 3..So K = 10...expr becomes 11*12*13...divisible by 4
k+1/3 = 5...so k = 16..expr becomes 17*18*19...nt divisible by 4.

So,I will go with option A


Qno2:
====
statement 1 : let the points be (1,1) (2,2)..they are not equidistant from origin
let the points be (1,1) (-1,-1)...they are equidistant from origin...


statement 2 :clearly both the points are equidistant from origin..


So,I will go with option B.

-Deepak.

hi
i am new to this thread and planning to appear GMAT.
which books i should refer for DS and others.
where i will get downloadable tests for preparation..?
please guide...

hi
i am new to this thread and planning to appear GMAT.
which books i should refer for DS and others.
where i will get downloadable tests for preparation..?
please guide...


For the complete quant section Official Guide is sufficient. Even if you think you need more practice you can refer to Kaplan Premier or Official guide Verbal review. For tests you can buy Kaplan tests, tests from 800score.com, Manhattan GMAT tests. These should provide you with enough practice tests.

Hi,
Need help in the following question:

Q-If x and y are integers, is the value of x(y+1) even?
1. x and y are prime numbers.
2. x is greater than 7.


Ans: C

Hi,
Need help in the following question:

Q-If x and y are integers, is the value of x(y+1) even?
1. x and y are prime numbers.
2. x is greater than 7.


Ans: C


Are you sure the answer is C, I think the answer should be E. I might be missing something but this is my explanation why E should be the answer.

Considering Statement 1 alone :given x and y as prime numbers, we can check that since every prime number except 2 is odd so in each case the solution would come out to be even except if y=2 and x is odd , where the solution would become odd. So you cannot come to a definite answer from this.
Considering statement 2 alone :Given x>7 doesn't give us any idea of neither x nor y. So the result could be either odd or even. You cannot come to a definite conclusion with this either.
Considering both the statements together :Given x and y as prime numbers and x>7 we are certain that x cannot be equal to 2 but we are still not sure of the value of y so the we cannot come to a definite solution from this too.

Do tell me if there is anything I am missing out because DS can be really nasty!

Anuj
Hi,
Need help in the following question:

Q-If x and y are integers, is the value of x(y+1) even?
1. x and y are prime numbers.
2. x is greater than 7.


Ans: C


Statement 1:
============
x= 2 y =3 ==> 2(4) = even
x= 2 , y=2 ===> 2(3) = 6
x= 5 , y =2 ===> 5(3) =15 = odd
Nt suff

Statement 2:
============
x = 11 , y=2 ===> 33 = odd
x = 9 , y =3 ===> 36 = even
Nt suff

Combining both we get

x = 11 , y = 2 ===> 33
x = 11 , y = 3 ===> 44

Nt suff..

I will go with option E

-Deepak.

guys please help me out:

In which quadrant of the coordinate plane does the point (x, y) lie?

(1) xy + x|y| + |xy + xy > 0
(2) -x y y


I am basically interested in knowing the way (1) is solved to get the answer

guys please help me out:

In which quadrant of the coordinate plane does the point (x, y) lie?

(1) xy + x|y| + |xy + xy > 0
(2) -x y y


I am basically interested in knowing the way (1) is solved to get the answer

(x,y) could lie in any of the 4 quadrants. let's check if condition (1) is satisfied for each of these.
I. Yes
II. xy = - xy, hence these two sum to 0
xy|is -ve and xy is +ve, these two sum to 0 as well;
The sum of all four = 0 and not >0
III.xy|+xy = 2xy
xy|+ y|x= -2xy
sum = 0 and not>0
IV. xy = - xy, hence these two sum to 0
xy|is +ve and xy is -ve, these two sum to 0 as well;
The sum of all four = 0 and not >0

Thus as per statement(1), (x,y) lies in I Quandrant.

Q. Does the line K intersect at quadrant II

1. slope of line K is -1/6
2. Y-intercept of K is -6

Q. Does the line K intersect at quadrant II

1. slope of line K is -1/6
2. Y-intercept of K is -6




Answer: A

1) If a line has a -ve slope, it should ideally go through quadrant 2 and 4. Thus it is Sufficient.
(Note: It will be vice versa for + ve slope i.e: the line should pass through 1 and 3)

2) If the Y-intercept is -6 it mean it passes through the point (0, -6). This information is not sufficient to tell whether the line passes through the 2nd Quadrant.