b) it says that x
Hi Montaque,
Could u pls elaborate this ? How can u say thata x
Btw, both the answers are right !
Hi Montaque,
Could u pls elaborate this ? How can u say thata x
Btw, both the answers are right !
Hi Montaque,
Could u pls elaborate this ? How can u say thata x
Btw, both the answers are right !
Hi KigCat,
b) Given that: -xmod(x) > 0 ; Since X is nothing but the numerical value of X. For example, If X = 2, then |X is equal to 2 is equal to 2 only.
Therefore, in order to make above inequality true, we need to have only negative values of X which can be represented as X
If X = 1 , then -(1)*1| = -1 ===> which doesn't satisfy the inequality
If X = -1, then -(-1)*|-1 => 1*1 = 1 ====> which satisfies the inequality
hope this will help...
Hi could someone explain the solution for
Is xy > 0 ?
1. x-y > -2
2. x-2y
Hi could someone explain the solution for
Is xy > 0 ?
1. x-y > -2
2. x-2y
i feel the ans is C...
for xy to be greater than 0 both x and y should be of same sign..
approach..
Clearly statement 1 n statement 2 is not sufficient individually...ans options A, B and D out of window..
Consider st 1 and st 2 combined :
x>y-2 ...st 1
x
i.e y-2
given eqn does not satisfy for yi.e y>4 => x>4.....hence x and y are both positive only..hence xy > 0 only..Ans C..
i feel the ans is C...
for xy to be greater than 0 both x and y should be of same sign..
approach..
Clearly statement 1 n statement 2 is not sufficient individually...ans options A, B and D out of window..
Consider st 1 and st 2 combined :
x>y-2 ...st 1
x
i.e y-2
given eqn does not satisfy for yi.e y>4 => x>4.....hence x and y are both positive only..hence xy > 0 only..Ans C..
Your answer is correct.
Can you explain the message ,
"i.e y-2
Your answer is correct.
Can you explain the message ,
"i.e y-2given eqn does not satisfy for y
Substitute y=3 in the above inequality, it says that x>1 and xSimilary for y=2,1,0.....
Only for values >=4, the equation makes sense.
Its easy to explain, but not so easy to think of it while taking the test
Hope it helps.
Your answer is correct.
Can you explain the message ,
"i.e y-2given eqn does not satisfy for y
hi raj,
kingcat has already explained y it does not hold true for ybasically for all real values for y upto 4....x has to be simultaneously be bigger than larger value and smaller than lower value...which is not possible...hence y is always +ve and above 4 and so is x..
hi raj,
kingcat has already explained y it does not hold true for ybasically for all real values for y upto 4....x has to be simultaneously be bigger than larger value and smaller than lower value...which is not possible...hence y is always +ve and above 4 and so is x..
thanks Kingcat,Bhavin...
I hope I choose the right answer when answering this type of question on exam day as I'm not sure I'll have the time to find out this answer.
Raj
Hi could someone explain the solution for
Is xy > 0 ?
1. x-y > -2
2. x-2y
This Q has been solved. But I have one more approach to put forth.
we can c that either of them alone is not sufficient. So let's take them together. So what will be the range of x and y?
Ignore inequality and draw graphs of both of them, st. line so won't take long. And decide which side of the line will hold true. Then the intersection area of the two will tell us that both x and y are always +ve for both of them to hold. So xy>0 is true. Ans is C.
Ignore inequality and draw graphs of both of them, st. line so won't take long. And decide which side of the line will hold true. Then the intersection area of the two will tell us that both x and y are always +ve for both of them to hold. So xy>0 is true. Ans is C.
after drawing the graph , i see that the lines intersect in the second quadrant , what next ? can u help me out with this ?
1. Customers can use a manufacturer's coupon and a store coupon to obtain a discount when buying soap powder in a certain store. In one week, 65 percent of customers used the store coupon when purchasing the soap powder, and 35 percent used the manufacturer's coupon. What percent of customers used both the manufacturer's and the store coupon when purchasing the soap powder?
a) 15 percent of customers used neither coupon when purchasing the soap powder.
b) 50 pecent of customers used the store coupon but not the manufacturer's coupon when purchasing the soap powder.
I am stuck with this question...need ur inputs guys..
one more question guys..
1. If m and n are both two digit numbers, and m-n = 11x, is x an integer?
a) The tens difit and the units digit of m are the same.
b) m + n is a multiple of 11.
one more question guys..
1. If m and n are both two digit numbers, ans m-n = 11x, is x an integer?
a) The tens difit and the units digit of m are the same.
b) m + n is a multiple of 11.
Well I guess, d q is asking if n is an integer. Cos m-n is always an integer. So x will always be an integer.
In case if u r asking if n is an integer then the answer is A. cos if m = aa => m = 11a.
Please confirm.
Fuzon Saysafter drawing the graph , i see that the lines intersect in the second quadrant , what next ? can u help me out with this ?
I saw few more q's on the same concept. And I think graph will be pretty handy to solve them all.
Here ignoring the inequality we have equations as
x - y = -2 and x - 2y = -6 solving them we get (2,4) and that is 1st quadrant. (The quadrant is important, if it is other than 1st is 3rd we cannot determine the sign og xy and hence the answer). Now the common area falls in between the 2 st lines only in 1st quadrant. So xy>0.
Well I guess, d q is asking if n is an integer. Cos m-n is always an integer. So x will always be an integer.
In case if u r asking if n is an integer then the answer is A. cos if m = aa => m = 11a.
Please confirm.
equation m-n = 11x implies that only 11x is an integer; x can have a value 10/11 which makes 11x an integer.
I have picked up this question from kaplan800..but not convinced with its answer and explanation....
i think, question is asking whether x is an integer or not. but in the book, they have solved to justify whether m-n = 11x or not.
per my understanding of the question answer has to be (D), but as per book it is (C).
what do u think abt the ques...what is the real question: is x an integer? or is m-n=11x?
1. Customers can use a manufacturer's coupon and a store coupon to obtain a discount when buying soap powder in a certain store. In one week, 65 percent of customers used the store coupon when purchasing the soap powder, and 35 percent used the manufacturer's coupon. What percent of customers used both the manufacturer's and the store coupon when purchasing the soap powder?
a) 15 percent of customers used neither coupon when purchasing the soap powder.
b) 50 pecent of customers used the store coupon but not the manufacturer's coupon when purchasing the soap powder.
I am stuck with this question...need ur inputs guys..
Hey answer is C. It is a simple application of V'diagram. I m sure u can solve it now.
1. Customers can use a manufacturer's coupon and a store coupon to obtain a discount when buying soap powder in a certain store. In one week, 65 percent of customers used the store coupon when purchasing the soap powder, and 35 percent used the manufacturer's coupon. What percent of customers used both the manufacturer's and the store coupon when purchasing the soap powder?
a) 15 percent of customers used neither coupon when purchasing the soap powder.
b) 50 pecent of customers used the store coupon but not the manufacturer's coupon when purchasing the soap powder.
I am stuck with this question...need ur inputs guys..
I think, this was lost as this was the last post on the second last page...i m really not convinced with the explanation provided in the book....so need ur inputs plzzz...
equation m-n = 11x implies that only 11x is an integer; x can have a value 10/11 which makes 11x an integer.
I have picked up this question from kaplan800..but not convinced with its answer and explanation....
i think, question is asking whether x is an integer or not. but in the book, they have solved to justify whether m-n = 11x or not.
per my understanding of the question answer has to be (D), but as per book it is (C).
what do u think abt the ques...what is the real question: is x an integer? or is m-n=11x?
Hi montaques,
the first statement says The tens difit and the units digit of m are the same.
So let's say m is 88.n can be anything, say 60. Then m-n = 11x implies x = 28/11 (not an integer). If n = 66, x can be an integer.
So statement 1 is not sufficient.
The 2 statements together mean that m has both the digits same and m+n is a multiple of 11.Hence n has to be a multiple of 11 too. So if both m and n are multiples of 11 and m-n = 11x , then x has to be an integer.
So C is the answer!
Hope this clears your confusion..
jha16june SaysHey answer is C. It is a simple application of V'diagram. I m sure u can solve it now.
thanku jha, for replying to it...and forgive me if i ask some stupid question..but dont u think 65% and 35% add up to 100% of customers..and also if 65% used store coupon and 35% used manufacturer's coupon ..there would be no space left for any person using neither of these two coupons?
Please clarify
equation m-n = 11x implies that only 11x is an integer; x can have a value 10/11 which makes 11x an integer.
I have picked up this question from kaplan800..but not convinced with its answer and explanation....
i think, question is asking whether x is an integer or not. but in the book, they have solved to justify whether m-n = 11x or not.
per my understanding of the question answer has to be (D), but as per book it is (C).
what do u think abt the ques...what is the real question: is x an integer? or is m-n=11x?
Hey answer is C. And the question too is fine. It is simply asking whether 11 is a factor of m-n or not.
So m == 11a, now m-n = 11I. I is an integer. So n = 11(a-I) so 11 is factor of N . so 11 is factor of m-n , so x is an integer. 😃 Got confused what the options C and D says. so editted.