jha buddy,
montaques said average of EVEN number of consecutive integers is always odd!
1 2 3 4
2 3 4 5
Yar post karne se pahle ek baar padh lo .. kya post kar rahe ho. So for being informal.
they r not even integers forget abt odd or even.
Yar post karne se pahle ek baar padh lo .. kya post kar rahe ho. So for being informal.
they r not even integers forget abt odd or even.
bhavin422 Saysyes jha...sum of odd no of conscutive integers can be even or odd...but given that average of consecutive integers is odd not only implies that no of terms are odd but also implies that sum of these odd no of consecutive integers is odd only..Ans A
Yes Bhawin, got ur point, thanks a lot.
A is indeed the correct answer.. 😃
If x,y,z are non-zero numbers,is xz=12?
1)x^2yz=12xy
2)z/4=3/x
This is a pretty straight forward problem.However i want to know how to solve condition 1
I did the following,
x^2yz=12xy
x^2yz-12xy=0
xy(xz-12)=0
xy=0 or xz-12=0
=>xy=0 or xz=12
But OG says just divide xy on both sides and arrive a the solution.
Which is the correct way of doing it?
If x,y,z are non-zero numbers,is xz=12?
1)x^2yz=12xy
2)z/4=3/x
This is a pretty straight forward problem.However i want to know how to solve condition 1
I did the following,
x^2yz=12xy
x^2yz-12xy=0
xy(xz-12)=0
xy=0 or xz-12=0
=>xy=0 or xz=12
But OG says just divide xy on both sides and arrive a the solution.
Which is the correct way of doing it?
Hi RajKumar,
As x, y and z are non zero integers, we can divided by xy, to get xz = 12. The way u have done is also correct but xy cannot be 0, so xz =12. But the former approach will take comparatively less time.
So answer is D.
Hi Guys,
Can you'll plz help me with the following:
1) The lifetimes of all batteries produced by a certain company in a year have a distribution that is symmetric about the mean m. if the distribution has a standard deviation of d, what% of the distribution is greater than m+d?
1) 68% of the distribution lies in the interval from m-d to m+d, inclusive
2) 16 % of the distribution is less than m-d
2)
if absolute of x+2 = 4, what is the value of x?
1 : X^2 is not equal to 4
2 : X^2=36
Thanx in advance!
2)
if absolute of x+2 = 4, what is the value of x?
1 : X^2 is not equal to 4
2 : X^2=36
x+2 = 4
thus x can either be 2 or be -6
1 : X^2 is not equal to 4 tells us that x cant be 2 , thus its -6
2 : X^2=36 tells us that x can be 4 😃 ... thus -6
thus the question can be answered using either of the statements
Hi Guys,
Can you'll plz help me with the following:
1) The lifetimes of all batteries produced by a certain company in a year have a distribution that is symmetric about the mean m. if the distribution has a standard deviation of d, what% of the distribution is greater than m+d?
1) 68% of the distribution lies in the interval from m-d to m+d, inclusive
2) 16 % of the distribution is less than m-d
Thanx in advance!
Ans D..each statement individually is sufficient..
St 1 : 68% of the distribution lies in the interval from m-d to m+d, inclusive, implies remaining 32 % have to be equally distributed on the lower and upper deviations i.e 16% is below m-d and 16% above m+d...sufficient..
St 2 : 16 % of the distribution is less than m-d . Since it is symmetric, 16 % would be above m+d as well...sufficient..
Basically, for SD sums, data is normally distributed and u can assume entire data to be within 3 deviations from mean...i.e it approx follows a trend of 34 % , 14% and 2 % for each deviation...
During an experiment some water was removed from each of the 6 water tanks.If the std. deviation of the volumes of the water in the tanks at the beginning of the experiment was 10 gallons,what is the std deviation of the volumes of water at the end of the experiment?
1)For each tank,30 % of the volume that was in the tank at the beginning of the experiment was removed during experiment.
2)The average volume of water in the tanks at the end of the experiment was 63 gallons.
Can someone explain the answer to this question?
Basically, for SD sums, data is normally distributed and u can assume entire data to be within 3 deviations from mean...i.e it approx follows a trend of 34 % , 14% and 2 % for each deviation...
Bhavin,
Could you pls explain this portion of ur explanation ?
THanks.
Bhavin,
Could you pls explain this portion of ur explanation ?
THanks.
the thing is for normal distribution of data about the mean...
34 % of the data falls within 1 standard deviation above the mean and 34 % data falls within 1 standard deviation below the mean...OR 68 % of the data is within 1 std deviation from mean..
14 % of the data is between 1st and 2nd deviation above mean and 14 % of the data is between 1st and 2nd deviation below mean... OR 96 % of the data is within 2 deviations from mean..
2 % of the data is between 2nd and 3rd deviation above mean and 2% of the data is between 2nd and 3rd deviation below mean... OR 100% of the data is within 3 deviations from mean..
this is very much a valid assumption for GMAT..actually 99.xx data is within 3 std deviations from mean...on GMAT u can approximate it to 100% and use 34 % , 14 % and 2% rule..
hope this answers ur question...
Could someone plz help with these problems?
If M is a positive integer, then M^3 has how many digits?
(1) M has 3 digits.
(2) M^2 has 5 digits
_______________________________________________________________-
(unable to copy figure)
In the figure, each side of square ABCD has length 1, the length of line
Segment CE is 1, and the length of line segment BE is equal to the length
Of line segment DE. What is the area of the triangular region BCE?
a. 1/3 b. (2^-2 )/4 c. 1/2
d. (2^-2)/2 e. 3/4
_______________________________________________________
Last year in a group of 30 businesses, 21 reported a net profit and
15 had investments in foreign markets. How many of the businesses
did not report a net profit nor invest in foreign markets last year?
(1) last year 12 of the 30 businesses
reported a net profit and had investments
in foreign markets.
(2) last year 24 of the 30 businesses
reported a net profit or invested in
foreign markets, or both.
______________________________________________________
If M+4 =2, what is the value of M?
(1) M
If M is a positive integer, then M^3 has how many digits?
(1) M has 3 digits.
(2) M^2 has 5 digits
_______________________________________________________________-
(unable to copy figure)
In the figure, each side of square ABCD has length 1, the length of line
Segment CE is 1, and the length of line segment BE is equal to the length
Of line segment DE. What is the area of the triangular region BCE?
a. 1/3 b. (2^-2 )/4 c. 1/2
d. (2^-2)/2 e. 3/4
_______________________________________________________
Last year in a group of 30 businesses, 21 reported a net profit and
15 had investments in foreign markets. How many of the businesses
did not report a net profit nor invest in foreign markets last year?
(1) last year 12 of the 30 businesses
reported a net profit and had investments
in foreign markets.
(2) last year 24 of the 30 businesses
reported a net profit or invested in
foreign markets, or both.
______________________________________________________
If M+4 =2, what is the value of M?
(1) M
If M+4| =2, what is the value of M?
(1) M
From |M+4 = 2,
We get two possibilities for M:
M = -2 and M = -6
Now from statement 1: M Hence, '1' alone cannot answer the question.
Now from statement 2: M^2+8M+12 = 0
gives M = -2 and -6. Hence, statement 2 also doesn't help.
Hence, this problem cannot be answered by both the statements together too.
Hope this helps.
Could someone plz help with these problems?
If M is a positive integer, then M^3 has how many digits?
(1) M has 3 digits.
(2) M^2 has 5 digits
_______________________________________________________________-
Ans E..
St 1 :
M has 3 digits...so M^3 can have 7,8 or 9 digits...
Eg ..100^3 has 7 digits and 999^3 has 9 digits..
not sufficient..
St 2 :
M^2 has 5 digits, hence 100
not sufficient..
st 1 and st 2 combined also tells us m is between 100 and 300 smtng..hence not sufficient..
Ans E..
_______________________________________________________
Last year in a group of 30 businesses, 21 reported a net profit and
15 had investments in foreign markets. How many of the businesses
did not report a net profit nor invest in foreign markets last year?
(1) last year 12 of the 30 businesses
reported a net profit and had investments
in foreign markets.
(2) last year 24 of the 30 businesses
reported a net profit or invested in
foreign markets, or both.
Ans D..
just draw venn diagrams..it becomes simple..
St 1:
12 businesses belong to both grps...
Hence neither = 30 - ( 21 +15 - 12 )
= 6
sufficient..
St 2:
24 is the union of 2 grps ...Hence remaining 30-24 = 6 do not belong to either of the 2 grps...
sufficient..
(unable to copy figure)
In the figure, each side of square ABCD has length 1, the length of line
Segment CE is 1, and the length of line segment BE is equal to the length
Of line segment DE. What is the area of the triangular region BCE?
a. 1/3 b. (2^-2 )/4 c. 1/2
d. (2^-2)/2 e. 3/4
_______________________________________________________
dude...are d ans options correct ??...
irrespective of whether E is outside or inside of square, am getting area of BCE as 1/(2 root 2) i.e root 2/4...
i think the option B shd be (2^1/2)/4...
if that is the case...can explain d approach..
Hi Bhavin,my ans was also the same but the solutiin said ans b is right...which actually confused me
Yash,
Can you pls tell us the source of these questions that you are posting ?
yash.kotak SaysHi Bhavin,my ans was also the same but the solutiin said ans b is right...which actually confused me
i think there is some printing mistake then...area cannot be 1/16..
if smbdy does get it as 1/16, would be glad to correct my mistake..
Hi,
I downloaded some tests from esnips , the answers are provided bt no explanations ...............