Q1) If x and y are positive integers and x is a multiple of y, is y = 2? (1) y 1 (2) x + 2 is a multiple of y.
Q2) If x and y are integers between 10 and 99, inclusive, is ((x-y)/9) an integer? (1) x and y have the same two digits, but in reverse order. (2) The tens digit of x is 2 more than the units digit, and the tens digit of y is 2 less than the units digit.
Q1 ans is C x and x+2 are multiples of y (used 2nd condition). Choices are 2,4/4,6/6,8 etc... The options for y is 1 or 2 only. If you use condition 1 also answer is 2. You can answer the question using both
Q2 Ans is D using statement 1 choices are 12,21/23,32/18,81 /25,52 etc...always diff is divisible by 9 using st 2 choces are 13,31 /24,42/57,75 etc.. check the diff, always multiple of 9.
you always can derive this using Maths equations for ex (10X+Y)-(10Y+X)=9*(X-Y). (10X+X+2) -(10*(X+2)+X) = -18 . always divisible by 9
ans to first one : C (by assuming values n checking) ans to the second Q: C
statement 1 gives you numbers like: 12,21/13,31/14,41... 13/31,14/41 etc and also not to miss 11,11/22,22/33,33 etc :mg
statement 2 gives u alot of no.s where the difference can or cannot be a multiple of 9 eg: 13/31 (diff is multiple of 9) 13,42/24,31 etc where the diff is not a multiple of 9.
combining the two we get a limited list: 13,31/24,42/35,53 ....
For Q2 I have 1 doubt as to why can't we take x/y as 11/11 or 22/22. Since X and Y are 2 different variables so, do v need to take them as different values. I think for option 2 u have missed out nbrs like 13/42, which are not divisible by 9
For Q2 I have 1 doubt as to why can't we take x/y as 11/11 or 22/22. Since X and Y are 2 different variables so, do v need to take them as different values. I think for option 2 u have missed out nbrs like 13/42, which are not divisible by 9
Ans : Q1) C Q2) A
no where was it mentioned that they are two different no.s so i would stick with C otherwise it would have been A.. n yeah i did consider combinations like 13-42 but eliminated them by using both statements 2gether.. check my solution..
---added later--- on second thoughts even in case of no.s like 11,22,33 etc the diff = 0 which divided by 9 = 0 which is an integer so only this statement can also give an answer so solution would be A u were right
Q1) What is the value of x? (1) x = -|x (2) x2 = 4
statement 1:
if x = -x or x = -x x can be anything here so no solution from this statement
Stament 2:
x^2 =4
x = +2 or -2 |x will always be 2 so we get an answer
Hi, I was going through this post and found this question with the answer listed below.Can some explain this answer, becuase according to me the answer should be E.
******************* 4) What is the value of xy? (1) y = x + 1 (2) y = x^2 + 1
C) ******************** Since , from 1 , you cannot determine value of xy thus B,C,E From 2, you cannot determine , thus C,E Now , taking both into consideration X2 + 1 = x +1 , thus x2 - x = 0 , which makes x = 0 , 1 . This makes y = 1, 2 and thus xy is 0, 2 . Thus the answer should be E. Some please explain ???
For Q2 I have 1 doubt as to why can't we take x/y as 11/11 or 22/22. Since X and Y are 2 different variables so, do v need to take them as different values. I think for option 2 u have missed out nbrs like 13/42, which are not divisible by 9
Ans : Q1) C Q2) A
Yes Q2 answer is A. I was trapped with using option 1 (reverseing X and Y ) for option B also.
11.3%* (20%) Here question is 10% of total population
Originally Posted by coolest View Post Are at least 10% of the people in Country X who are 65 years old or older employed?
1) In Country X, 11.3% of the population is 65 years old or older.
2) In Country X, of the population 65 years old or older, 20% of the men and 10% of the women are employed. x
I think the answer for the above question is B... bcoz irrespective of the male & female population the number of employed population will always be atleast 10%... Plz correct me if I am wrong....
4) What is the value of xy? (1) y = x + 1 (2) y = x^2 + 1
C)
Is m != n (m not equal to n)? (1) m + n (2) mn D) 1. m+n 2. If m=n then mn Hence m not equal to n
Hey All,
I was just going thru the posts and found out a set of questions put forth by alien and answered by sailor. This was some 2 months back.
But i have a little doubt in the above 2 questions.
In the 1st question, even if we consider both the statements together, then we can get at least 2 values of x which satisfy the equations and hence value of xy will be different.
If x = 0, then y = x+1 => y = 1 y = x^2 +1 => y =1 There fore xy = 0
if x = 1 , then y = x+1 => y = 2 y = x^2 +1 => y =2
There fore xy = 2
So, according to me the answer to this should be E For 2nd question, statement 1 alone is not sufficient it says m+n if m = -2 and n = -1 then m+n = -3 So this does not give the answe.
So, according to me the answer to this should be B. Can some one plz confirm my observation. Thanks and Regards, Maunang
I was just going thru the posts and found out a set of questions put forth by alien and answered by sailor. This was some 2 months back.
But i have a little doubt in the above 2 questions.
In the 1st question, even if we consider both the statements together, then we can get at least 2 values of x which satisfy the equations and hence value of xy will be different.
If x = 0, then y = x+1 => y = 1 y = x^2 +1 => y =1 There fore xy = 0
if x = 1 , then y = x+1 => y = 2 y = x^2 +1 => y =2
There fore xy = 2
So, according to me the answer to this should be E For 2nd question, statement 1 alone is not sufficient it says m+n if m = -2 and n = -1 then m+n = -3 So this does not give the answe.
So, according to me the answer to this should be B. Can some one plz confirm my observation. Thanks and Regards, Maunang
Q1 I agree with you Q2 Fromeither of these conditions you can conclude that either M or N is negative. Factorial is not defined for -ve integers. So you can easily conclude that m! is not equal to n for any pair.(since one of them is -ve,)
Q1 I agree with you Q2 Fromeither of these conditions you can conclude that either M or N is negative. Factorial is not defined for -ve integers. So you can easily conclude that m! is not equal to n for any pair.(since one of them is -ve,)
If a certain grove consists of 36 pecan trees, what was the yield per tree last year? *(1) The yield per tree for the 18 trees in the northern half of the grove was 60 kilograms last year. *(2) The yield per tree for the 18 trees in the eastern half of the grove was 55 kilograms last year
If a certain grove consists of 36 pecan trees, what was the yield per tree last year? *(1) The yield per tree for the 18 trees in the northern half of the grove was 60 kilograms last year. *(2) The yield per tree for the 18 trees in the eastern half of the grove was 55 kilograms last year Thanks and Regards, Maunang
I think the answer is A as the 2nd one does'nt yield the answer.It can be {6,5},{3,10},{10,15},{6,10}.In the case of last 2 r>1 while in the case of first 2, r=1.
1) 3.2@#6 : If @ and # each represent single digits in the given decimal, what digit does @ represent? (1) When the decimal is rounded to the nearest tenth, 3.2 is the result. (2) When the decimal is rounded to the nearest hundredth, 3.24 is the result.
2) What is the value of integer n? (1) n(n+1) = 6 (2) 2^2n = 16
3) In triangle ABC, Angle A = x, Angle B = y, Angle C = z (All in degrees). What is the value of z? (1) x + y = 139 (2) y + z = 108
4) What is the value of xy? (1) y = x + 1 (2) y = x^2 + 1
5) Is rst = 1? (1) rs = 1 (2) st = 1
6) If a,b,c are integers, is a-b+c greater than a+b-c? (1) b is negative. (2) c is positive.
7) In the xy plane, does the point (4,12) lie on line k? (1) The point (1,7) lies on line k. (2) The point (-2,2) lies on line k.
Is m != n (m not equal to n)? (1) m + n (2) mn
1)e
2)b as 2nd stat. alone gives the answer
3)a
4)e as x^2+1=x+1=>x=0,1=>y=1,2=>xy=2/0
5)e as for eg. r=1,s=1,t=1=>rst=1 but r=1/3,s=3,t=1/3=>rst=1/3
If p is a positive integer, what is the remainder when p is divided by 4? (1) When p is divided by 8, the remainder is 5. (2) p is the sum of the squares of two positive integers.
In the xy-plane, at what two points does the graph of y = (x+a)(x+b) intersect the x-axis? (1) a+b = -1 (2) The graph intersects the y-axis at (0,-6).
If x and y are integers greater than 1, then is x a multiple of y ? (1) 3y^2 + 7y = x (2) x^2 - x is a multiple of y.
If the operation # is one of the four operations +, - , * (multiply) and / (divide), is (6 # 2) # 4 = 6 # (2 # 4)? (1) 3 # 2 > 3 (2) 3 # 1 = 3
Six countries in a certain region sent a total of 75 representative to an internation congress, and no two countries sent the same number of representatives. Of the six countries, if country A sent the second greatest number of representatives, did country A send at least 10 representatives? (1) One of the six countries sent 41 representatives to the congress. (2) Country A sent fewer than 12 representatives to the congress.
Each of the students in a certain class received a single grade P, F or I. What percent of students in the class were females? (1) Of those who received a P, 40% were females. (2) Of those who received either an F or I, 80% were males.
Need as people as possible to answer as I do not have the answers. These questions are from the Practice Test 1 from GMAC. If someone knows from where I can get the answers to that, do tell me.
Is m != n (m not equal to n)?