for interest question both statement sufficient to solve question
st1 from D(t) u can find value of r and from r value u will find D(t) after 3 year
st2
from r directy u can solve
each one sufficiet
hi jigar....could you pls explain why st 1 is sufficient by itself... if we know D(t) = 11000, how can we find r when t is also unknown...11000 may not be necessarily d amount after 1 year...it could be at any year t ...
11000 = (1+r/100)^t ..1 equation and 2 unknowns..not sufficient...
hi jigar....could you pls explain why st 1 is sufficient by itself... if we know D(t) = 11000, how can we find r when t is also unknown...11000 may not be necessarily d amount after 1 year...it could be at any year t ...
11000 = (1+r/100)^t ..1 equation and 2 unknowns..not sufficient...
Can you explain the percentile funda and your approach?
median is the middle value...half of the values are equal to or above median and other half are equal to or below median...
Percentile is the % of values equal to or below a given value...hence median is the 50th percentile ...
in the above sum, No of employees per project is always an integer value..
Hence, If suppose there are 100 projects...and if these projects are arranged sequentially acc to no of employees in every project, we want to know the no of employees in the 50th project...
hence , first 35 proj have 2 or lesser employees and last 25 have 4 or more...hence all proj from 35th to 75th have 3 employees ..(no ambiguity in no of employees for 50th proj...sufficient)
This translates to : 2 is the 35th percentile and 4 is the 75th percentile...there is only one integer between 2 and 4 which necessarily has to be the 50th percentile ..
Is x an even integer? (1) x is the square of an integer.
(2) x is the cube of an integer.
Ans E...
St 1 : Perfect squares can be even or odd...not sufficient... St 2 : Perfect cubes can be even or odd as well ...not sufficient...
ST 1 & st 2 : Sixth power of any integer wud be a perfect square as well as perfect cube...and sixth power of an integer cud be even or odd depending on whether integer is even or odd...not sufficient !!
Hey guys , thanks for the answers as well as the explanations !!! the OA's are for q10s30 its D(the explanition by bhavin is what i also assumed , but dunno y its mentioned D.Nonetheless i wud also go with B until someone provides some divine intervention on this one) for q35s30 its C(got the explantion for this one,Thanks )
1) The total capacity of three 8-ounce cups is double the capacity of pitcher P 2) Pitcher P fills two 8 ounce cups
My answer is D OA is A
for 2) Cant I make an assumption that the capacity of pitcher is equal to 16 ounce?
I also initially thought that answer would be D, but later -second option says it can fill two 8 ounce cup- it doesnt mean that the pitcher is empty after filling two cups,may be it can fill 2.5 cups.
1. If the co - ordinates are (1,1) and (-1,-1). The co-ordinates are equidistant Consider (1,2) and (2,4). These co-ordinates also satisfies the equation but they are not equidistant from origin.
A not sufficient
2. From this option, we can say that
a) a = (plus or minus) +- C, b = (plus or minus)+- d b) a = (plus or minus) +- d, b = (plus or minus) +-c
In both cases the co-ordinates are equidistant from origin.