First of all my sincire apologies for severely overlooking the subtle rule that:
a^2 > b^2 => A> B; A
Still, i've come up with following
X> SQRT (3/14) ; x Y > 1 ; Y
Now big Question is that by drawing the 4 possible combinations here on number line....overlapping area results that...
XY(1-XY) > 0.
then why not answer shall be C?
Is it D?
According to first statement and given data if m=n then p is also even and n+2=According to sec statement LCM of m and p is 30. Factors of 30 are 1, 2, 3, 5, 6, 10, 15, 30. m>2 So possible values of m and p are 3 and 10 or 5 and 6 and in both the cases remainder is 1.
So both statements are individually sufficient.
What is the probability that (U/V)/W and (X/Y)/Z are reciprocal fractions?
(1)
v, w, y, and z are each randomly chosen from the first 100 positive integers.
(2) The product (u)(x) is the median of 100 consecutive integers.
buddy ..statements in bold are incorrect ..
xy can never simultaneously be lesser than zero and greater than 1 ..only your 1st argument has to hold true..
question says its x square =3/14 ...it has 2 poss roots ...+ve n -ve
even if u say x^2 >3/14 it does not imply x is greater than root 3/14 only ..
eg ..x^2> 25 it implies x>5 or x
similarly for statement 2 also
Detailed approaches have been discussed 2 pages back ...everybody concurs Ans is E ..
What is the probability that (U/V)/W and (X/Y)/Z are reciprocal fractions?
(1) v, w, y, and z are each randomly chosen from the first 100 positive integers.
(2) The product (u)(x) is the median of 100 consecutive integers.
I think D
For reciprocal fractions, we need:
u/vw = 1/(x/yz) = yz/x
=> ux = vwyz (say equation)
So we need to find the probability of the above equation being true.
A) Once we get 2 nos vwyz, we know RHS, say ux=123456, no we just need to find out multiples of 123456 and fit them in ux, hence we can determine the P(equation)
B) Again, we know ux, then we can again find out the 4 numbers on RHS and hence the probability.
Whats the OA?
Offtopic: I'm not able to change my status. Clicking on Edit doesn't work. Anyone facing the same issue?
OA is C) with explanation:
Statement (1) tells us that
vywz is an integer, since it is the product of integers. However,
this gives no information about u and x and is therefore not sufficient to answer the
question.
Statement (2) tells us that ux is NOT an integer. This is because the median of an even
number of consecutive integers is NOT an integer. (For example, the median of4
consecut ive integers - 9, 10, 11, 12 - equals 10.5.) However, this gives us no information
about vywz and is therefore not sufficient to answer the question.
Taking both statements together, we know that
vywz IS an integer and that ux is NOT an
integer. Therefore vywz CANNOT be equal to ux. The probability that the fractions are
reciprocals is zero.
shashankaggarwa Saysnice question !!!
and that would also decrease spamming... 
Ellen can purchase a certain computer at a local store at price of p dollars and pay 6% sales tax. Alternatively, Ellen can purchase same computer from catalog for q dollars including everything. Will it cost more for Ellen to purchase from local store or catalog?
1) q - p 2) q = 1,150
please explain
Ellen can purchase a certain computer at a local store at price of p dollars and pay 6% sales tax. Alternatively, Ellen can purchase same computer from catalog for q dollars including everything. Will it cost more for Ellen to purchase from local store or catalog?
1) q - p 2) q = 1,150
please explain
Ellen can purchase a certain computer at a local store at price of p dollars and pay 6% sales tax. Alternatively, Ellen can purchase same computer from catalog for q dollars including everything. Will it cost more for Ellen to purchase from local store or catalog?
1) q - p 2) q = 1,150
please explain
During an experiment, some water was removed from each of 6 water tanks. If the standard deviation of the volumes of water in the tanks at the beginning of the experiment was 10 gallons, what was the standard deviation of the volumes of water in the tanks at the end of the experiment?
1) For each tank, 30 percent of the volume of water that was in the tank at the beginning of the experiment was removed during the experiment.
2) The average (arithmetic mean) volume of water in the tanks at the end of the experiment was 63 gallons.
I found this is one of the earlier threads but the soln wasn't there. Please provide the explaantory soln.
Thanks.
IMO A
since the same amt of water was removed from each of the tank the SD remains same so A alone is sufficient.
2) gives the avg. this is not sufficient to determine the SD
So A
Puys any alternative expln?
Good question arijit ...
Hey siddharth , i feel statement in bold is incorrect ..
Yes, SD does not change for equal amount of changes in every qty, however question reads equal change in percent, which does not translate to equal amounts unless initial quantities are same ...So, 1 alone is not sufficient ...
Still not sure about the soln ...I guess it should be E ...
I guess, only new avg and equal % change still does not give us original values ...Should be E ...though dicy about this part ...
Yaa the thought had occured to me. But some how chose A. So I think the ans should be E
:|
Sorry dude :(...i have edited my post now...though SD does not remain same , we still have a definite SD from St 1 ...
I guess the answer is A ...not very sure this time..
Yaa since the same 30% is taken out from all the vessels. So we need not worry abt the initial quantity in the vessels. So the SD remains the same.
What say puys???
hey siddharth ...both of us agree that st 1 is sufficient for different reasons
Yes, since its DS we need not worry what is the exact new SD as long as we know only 1 values is poss ...
However SD does not remain same ...Infact it changes by the same percentage ...
Let me take a simple eg to prove my point
Let there be just 2 vessel with qty 10 and 30 Hence avg = 20 and SD =10
30% reduction
New qty are 7 and 21 , avg = 14 ; new SD =7
I.e new SD = 70 % original SD ...its not the same !!