GMAT Data Sufficiency Discussions

How to address such questions..??.. CG makes me go nuts..:banghead:

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In the xy-plane, is the slope of line k positive?
(1) Line k passes through the points (-1, -7) and (2, 5).
(2) Line k has equation y = 4x 3.
=====
In the
xy-plane, line l and line k intersect at the point (16/5, 12/5). What is the slope of
line
l?
(1) The product of the slopes of line
l and line k is 1.

(2) Line
k passes through the origin.
=====



for the first ques the ans is D(IMO). From 1) u can calc slope. so A alone is suff. From 2) we can calc the slope from y=mx+C so slope is +ve.


For the 2nd ques

we want the slope of line l.

Take 1)we can only know that the 2 lines are perpendicular.

SO 1) alone is insuff

Take 2) we have no info on line l so insuff.

take 1) and 2) here we have 2 points for k so we can calc slope of K and so we can calc slope for l since k and l are perpendicular.

So C.

Whats the answer for both?
For the first one,compare the lines with the standard equation of y=mx+c and if m positive slope positive.
for first statement-
m=(5+7)/(2+1)=4
second statement,m=4
so either is suffeciet-D

2.answer is C.
from the point of intersection, the two equations will be-
k=>12=16m'+5c'
l=>12=16m"+5c"

from first statement m'*m"=-1
and from second statement 5C'=0,m'=3/4
so m"=-4/3.



Hey guywithguts,
U need not actually calculate the values to answer this particular question.
Hey guywithguts,
U need not actually calculate the values to answer this particular question.


@siddharthaduggirala: I guess that was to help dumbos like me.. as I pointed out that I am bad @ CG..

@gutsy: thanks πŸ˜‰
@siddharthaduggirala: I guess that was to help dumbos like me.. as I pointed out that I am bad @ CG..

@gutsy: thanks ;)



No one is a dumb buddy..

Time to try some tough one...
IS X a negative number?

1) X^2 is a positive number
2) x. Y| is not a positive number

If a & b are integers, and a| > |b|, is a.b1) a b) ab >= 0.

Time to try some tough one...
IS X a negative number?

1) X^2 is a positive number
2) x. Y| is not a positive number


1)=> X #0 but X>0 or X
2)=> since Y is always >= 0 => x
from 1 and 2 => x
Hence ans C) Answered using both but not alone..


If a & b are integers, and a| > |b|, is a.b1) a b) ab >= 0.


too drowsy to ans this now..on a rough mental calc is it A??
Time to try some tough one...
IS X a negative number?

1) X^2 is a positive number
2) x. Y| is not a positive number

From 1.
X not equal to 0.
x can take both +ve and -ve. so cannot ans from 1.
From 2:
x.y is zero or -ve.
a.if y is not 0 , x has to be -ve . => not +ve
b.If y=0 then x can take any number. => not +ve
c. y any number ( 0 , -ve,+ve) and x is 0. => not +ve
so, from 2 we cannot conclude whether x is -ve.
from 1 & 2 :
x is not equal to 0.
cases a, b.
nothing says Y is is not zero
so 1 and 2 are not sufficient to ans the q

If a & b are integers, and a| > |b|, is a.|b1) a b) ab >= 0.

from 1.
a| > |b and a
b can be 0,+ve ( but so range of b can be (-a,a)

a.b
so 1 is not sufficient.

from 2.

a| > |b
implies a|-|b > 0

a cannot be 0. but b can be 0

for ab>=0
If a > 0 , b (0,+ve)
if a
is a.|bfails when any a,b are +ve

so 2 alone is not sufficient.

from 1 & 2

a is
so .can be ans using both.


...............

OAs pls

For the below q

S X a negative number?

1) X^2 is a positive number
2) x. Y is not a positive number


It cannot be answered by using both the statements together.

For the below q

If a & b are integers, and a > |b|, is a.b1) a b) ab >= 0.


Statement 1 alone is not sufficient as b=0 case is not clear from statement 1

From statement 2 :it is also not clear :a0 ,b>0 or a0 , b=0.

Even combining both the statements
a=0.so b can be -ve or b=0.

Even combining both the statenebts will not give solution.


IS X a negative number?

1) X^2 is a positive number
2) x. Y| is not a positive number


Option 1: X^2 = positive number
X can be +ve or -ve.
NOT SUFF

Option 2: X.Y
+ve
now, Y is always +ve
but
+ve can mean X.Y| = -ve or X.Y = 0
NOT SUFF

Now taking option 1 and option 2 together, we find that X is -ve.. thus correct answer must be option C
Option 1: X^2 = positive number
X can be +ve or -ve.
NOT SUFF

Option 2: X.Y|
+ve
now, Y is always +ve
but
+ve can mean X.Y| = -ve or X.Y = 0
NOT SUFF

Now taking option 1 and option 2 together, we find that X is -ve.. thus correct answer must be option C


hey varun ...not necessary that x wud be -ve.
St 2 has 2 alternatives. y could be zero and x could be any real no OR x is -ve ...
So combines we cannot sat that x is necessarily negative ...

Ans E
hey varun ...not necessary that x wud be -ve.
St 2 has 2 alternatives. y could be zero and x could be any real no OR x is -ve ...
So combines we cannot sat that x is necessarily negative ...

Ans E


Well I was left with only C and E to chose from.. but if u wud combine the 2 option in the question u wud see that both option give X as possibly -ve.. which kinda reinforces that X is not 0 and not +ver either.. thats' how -ve..

your thoughts..!!..
Time to try some tough one...
IS X a negative number?

1) X^2 is a positive number
2) x. Y is not a positive number


Well I was left with only C and E to chose from.. but if u wud combine the 2 option in the question u wud see that both option give X as possibly -ve.. which kinda reinforces that X is not 0 and not +ver either.. thats' how -ve..

your thoughts..!!..


well..

St 1 : x is +ve or -ve
St 2: x. Y is not a positive number implies product is 0 or -ve

possibilities:
a) X=0 and Y is any no
OR
b) x= any real no and y = 0
OR
c) x= -ve and y = any no

combined statements :

It tells us x is not zero ...so option a) of St 2 is gone ...
But still we cannot rule out option b and c of statement 2 ..

Or in other words, x can be any real no (which includes positive no) Or -ve ..still no concensus whether x is -ve ...

Hence E ..

I guess this should be correct

well.. for me it goes something like..

option1:
possibly X is +ve or -ve..
and
for sure X ??????>?>?>?> ZERO

option2:
possible X is zero or -ve
and
for sure X ??????>?>?>?> +ve

combining 2 we get..for sure X ??????>?>?>?> ZERO and for sure X ??????>?>?>?> +ve

thus answer can be reached with the help of both statements...

remember this is a YES/NO answer..and using the statement provided the answer can be reached, i.e. YES.

my asnwer choice still remains option C ;)

well..

St 1 : x is +ve or -ve
St 2: x. Y is not a positive number implies product is 0 or -ve

possibilities:
a) X=0 and Y is any no
OR
b) x= any real no and y = 0
OR
c) x= -ve and y = any no

combined statements :

It tells us x is not zero ...so option a) of St 2 is gone ...
But still we cannot rule out option b and c of statement 2 ..

Or in other words, x can be any real no (which includes positive no) Or -ve ..still no concensus whether x is -ve ...

Hence E ..

I guess this should be correct
well..

St 1 : x is +ve or -ve
St 2: x. Y is not a positive number implies product is 0 or -ve

possibilities:
a) X=0 and Y is any no
OR
b) x= any real no and y = 0
OR
c) x= -ve and y = any no

combined statements :

It tells us x is not zero ...so option a) of St 2 is gone ...
But still we cannot rule out option b and c of statement 2 ..

Or in other words, x can be any real no (which includes positive no) Or -ve ..still no concensus whether x is -ve ...

Hence E ..

I guess this should be correct


Try this...
If x and y are positive, is 4x > 3y?
(1) x > y - x
(2) x/y
Few more....
1. If x and y are positive, is 3x > 7y?
(1) x > y + 4
(2) -5x
2. If w and c are integers, is w > 0?
(1) w + c > 50
(2) c > 48
Yesterday Diana spent a total of 240 minutes attending a training class, responding to Emails, and talking on the phone. If she did no two of these three activities at the same time, how much time did she spend talking on the phone?

(1) Yesterday the amount of time that Diana spent attending the training class was 90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was 60 percent of the total amount of time that she spent responding to E-mails and talking on the phone.
What is the cube root of w ?
(1) The 5th root of
w is 64.
(2) The 15th root of
w is 4.

the OA is option B.. how come..??..
Try this...
If x and y are positive, is 4x > 3y?
(1) x > y - x
(2) x/y


Serious connectivity issues at my end ..unable to post solutions ..

Since variables are positive, we can perform operations without worrying abt inequality
Question : Is x/y > 0.75 ?

St 1 : 2x>y i.e x/y > 0.5, so the ratio may or maynot be greater than 0.75 ..not suff ..

St 2: x/y
Combined : ratio is between 0.5 and 1, it may or maynot be greater than 0.75 ...not suff ..

Ans E
Few more....
1. If x and y are positive, is 3x > 7y?
(1) x > y + 4
(2) -5x



Question : Is x/y > 7/3 i.e is x/y > 2.33 ?

St 1 : mult by 3 i.e 3x> 3y +12 ..cant say if 3x is greater or not than 7y ..not suff

St 2 : mult by -ve, change in inequality, 5x>14y
i.e x/y > 14/5 ...i.e x/y > 2.8 ...suff

Ans B