one more time.. my answer doesn't match with the OA.. share your thoughts..
If Line k in the xy-plane has equation y = mx + b, where m and b are constants, what is the slope of k?
(1) k is parallel to the line with equation y = (1-m)x + b +1.
(2) k intersects the line with equation y = 2x + 3 at the point (2, 7).
Each of the 45 boxes on shelf J weighs less than each of the 44 boxes on shelf K. What is the median weight of the 89 boxes on these shelves?
(1) The heaviest box on shelf J weighs 15 pounds.
(2) The lightest box on shelf K weighs 20 pounds.
my answer doesn't match with the OA.. and I am not sure if the OA could be true.. share your thoughts..
median means the weight of 45th box.
If the weight of the boxes are same,the answer will be A.
elsewhile E
one more time.. my answer doesn't match with the OA.. share your thoughts..
If Line k in the xy-plane has equation y = mx + b, where m and b are constants, what is the slope of k?
(1) k is parallel to the line with equation y = (1-m)x + b +1.
(2) k intersects the line with equation y = 2x + 3 at the point (2, 7).
A.equating two equations slope ,m can be calculated as1/2.
Each of the 45 boxes on shelf J weighs less than each of the 44 boxes on shelf K. What is the median weight of the 89 boxes on these shelves?
(1) The heaviest box on shelf J weighs 15 pounds.
(2) The lightest box on shelf K weighs 20 pounds.
my answer doesn't match with the OA.. and I am not sure if the OA could be true.. share your thoughts..
IMO the answer must be A.
The median in the 89 boxes is 45th box. so weight of the 45 box is enough to answer the question.
Here 1) alone is suff. since the weight of the 45th box is 15 pounds.
2) this gives the weight of 46 box so insuff..
Hence A.
one more time.. my answer doesn't match with the OA.. share your thoughts..
If Line k in the xy-plane has equation y = mx + b, where m and b are constants, what is the slope of k?
(1) k is parallel to the line with equation y = (1-m)x + b +1.
(2) k intersects the line with equation y = 2x + 3 at the point (2, 7).
IMO the answer is A.
consider 1) (1-m)=m so m=1/2
Consider 2) here we have one pt (2,7) and no slope. we have no addl info on the second line. so insuff
So A
median means the weight of 45th box.
If the weight of the boxes are same,the answer will be A.
elsewhile E
Hey guy with guts,
option A says the heaviest. The weights need not be equal.
Each of the 45 boxes on shelf J weighs less than each of the 44 boxes on shelf K. What is the median weight of the 89 boxes on these shelves?
(1) The heaviest box on shelf J weighs 15 pounds.
(2) The lightest box on shelf K weighs 20 pounds.
my answer doesn't match with the OA.. and I am not sure if the OA could be true.. share your thoughts..
IMO the answer must be A.
The median in the 89 boxes is 45th box. so weight of the 45 box is enough to answer the question.
Here 1) alone is suff. since the weight of the 45th box is 15 pounds.
2) this gives the weight of 46 box so insuff..
Hence A.
how did you conclude that the weight of 45th Box is enough..??.. boxes are not arranged on the basis of their wights.. in any kinda order..
what is all the boxes in J shelf are simply 15 KG each.. and since you dunno anything about shelf K how would you even know the median of the 2 shelves??
now u use eqn B, saying lightest in K shelf is 20KG.. that again doesnt mean anything whatsoever.. so insuff again..
using both together.. still no clear picture..
plz share a little more on your answer bcoz I am unable to comprehend how you concluded that..
BTW.. OA is indeed option A.. 😉
how did you conclude that the weight of 45th Box is enough..??.. boxes are not arranged on the basis of their wights.. in any kinda order..
what is all the boxes in J shelf are simply 15 KG each.. and since you dunno anything about shelf K how would you even know the median of the 2 shelves??
now u use eqn B, saying lightest in K shelf is 20KG.. that again doesnt mean anything whatsoever.. so insuff again..
using both together.. still no clear picture..
plz share a little more on your answer bcoz I am unable to comprehend how you concluded that..
BTW.. OA is indeed option A.. ;)
Ok . i will explore a bit more.
Here in the options the words heaviest and lightest are important. To calculate the median we need the weight of the 45 box. Now if we start arranging the boxes, we will first find all the boxes on J shelf followed by boxes on K shelf. Since we have the statement "Each of the 45 boxes on shelf J weighs less than each of the 44 boxes on shelf K". So the heaviest box on shelf J,which also happens to be the 45 box, is enough to answer the question. Hence A.
I hope i explained more clearly this time.
I'm loving the discussion on this thread.
Reg the prblm 55. N is a positive three digit number denoted by N=(a^2)*(b), where and b are multiples of 3 and 5. Find N
1. a+b= even number
2.a=b
OA: B
I feel the ans must be option E since option b can't be achieved for the above conditions and option a is not suff
Yes. I too feel the ans must E. Because
consider 1) a and b are multiples of 3 and 5. so
let a=15 and b=30
so N = 225*30=6750 but N is a 3 digit number. so insuff.
consider 2) a=b so let a=b=15 so N=225*15 this is a 4 digit number. so insuff.
So E.
I think the correction in the problem must be "where and b are multiples of 3 and 5 respectively". even then IMO the ans is E.
consider 1) let a=3 and b=5
N=9*5
but this is just one possibility.
a=6 and b=10 is also a possible. so insuff
consider 2) here a=b but a and b must also be multiples of 3 and 5 respectively.
so let a=15=b
so N=15^2*15 hence insufficient.
Combining both still there is no solution so E.
I wonder why the OA is B.
Puys any alternative expln?
Ok . i will explore a bit more.
Here in the options the words heaviest and lightest are important. To calculate the median we need the weight of the 45 box. Now if we start arranging the boxes, we will first find all the boxes on J shelf followed by boxes on K shelf. Since we have the statement "Each of the 45 boxes on shelf J weighs less than each of the 44 boxes on shelf K". So the heaviest box on shelf J,which also happens to be the 45 box, is enough to answer the question. Hence A.
I hope i explained more clearly this time.
I'm loving the discussion on this thread.
ple re-read my thread above.. you seem to be assuming information NOT given in the question..
plz explain me the section marked in red above in your post... how did you assume that.. based on what information.. who said that the weights are ordered..??.. they can all be same or all be different by on 5 KGs..
all in J be 15.. but 44 in K be of diff wights.. then how do your propose to solve this question..??..
your explanation is hovering around one unwarranted assumption.. plz re-check and reply..
Reg the prblm 55. N is a positive three digit number denoted by N=(a^2)*(b), where and b are multiples of 3 and 5. Find N
1. a+b= even number
2.a=b
OA: B
I feel the ans must be option E since option b can't be achieved for the above conditions and option a is not suff
here again assume values and substitute values..
we know that, N=(a^2)*(b)
&
a and b are multiples of 3 and 5
Eqn 1:
a + b can be even in when
a = E and b = E
a = O and b = O
Doesnt help in finding out value of N..
Eqn 2:
For a = b, the main inequality can be changed as;
N=(a^2)*(a) = a^3
or
N=(b^2)*(b) = b^3
Notice the question again;
N is a positive three digit number.
Substitute the values 3 and 5 to figure out..
For, a = b = 3, N = 3^3 = 27
and
For, a = b = 5, N = 5^5 = 125
Thus 3 digits positive number..
OA is correct.. I wud guess so..
NOTE:
The question doesnt seem from OG.. since it leaves a lot of ambiguity around itself.. the lack of words like "respectively" or "can take any value" etc leaves everything on the problem solver.. and this gap is something which is NOT seen in OG questions..
ple re-read my thread above.. you seem to be assuming information NOT given in the question..
plz explain me the section marked in red above in your post... how did you assume that.. based on what information.. who said that the weights are ordered..??.. they can all be same or all be different by on 5 KGs..
all in J be 15.. but 44 in K be of diff wights.. then how do your propose to solve this question..??..
your explanation is hovering around one unwarranted assumption.. plz re-check and reply..
Hey varun,
I'm not assuming here. Ok.. let me put it in a different way..
Lets take boxes in shelf J.
If i start arranging according to their weights, the heaviest weight comes at the end. Now "Each of the 45 boxes on shelf J weighs less than each of the 44 boxes on shelf K". So all the boxes on K shelf come next. No assumptions here.
Now we need weight of 45 th box in order of arrangement.So 1) alone satisfies the condition.
Can you please elaborate on what my assumption are here?
Hey varun,
I'm not assuming here. Ok.. let me put it in a different way..
Lets take boxes in shelf J.
If i start arranging according to their weights, the heaviest weight comes at the end. Now "Each of the 45 boxes on shelf J weighs less than each of the 44 boxes on shelf K". So all the boxes on K shelf come next. No assumptions here.
Now we need weight of 45 th box in order of arrangement.So 1) alone satisfies the condition.
Can you please elaborate on what my assumption are here?
ok.. 45 boxes each weighs 15KG in J
>>INFO NOT KNOWN TO US
but for 44 next boxes the weights are in ascending order starting from 20.. it wud be something like 20, 21, 22, 23....64 or lets say even worse example, 15.014, 16.123, 18.905 etc etc
now tell me wats the median?? Can u tell me the median value only on the basis of weight of boxes in J..??..
Each of the 45 boxes on shelf J weighs less than each of the 44 boxes on shelf K. What is the median weight of the 89 boxes on these shelves?
(1) The heaviest box on shelf J weighs 15 pounds.
(2) The lightest box on shelf K weighs 20 pounds.
my answer doesn't match with the OA.. and I am not sure if the OA could be true.. share your thoughts..
Ok . i will explore a bit more.
Here in the options the words heaviest and lightest are important. To calculate the median we need the weight of the 45 box. Now if we start arranging the boxes, we will first find all the boxes on J shelf followed by boxes on K shelf. Since we have the statement "Each of the 45 boxes on shelf J weighs less than each of the 44 boxes on shelf K". So the heaviest box on shelf J,which also happens to be the 45 box, is enough to answer the question. Hence A.
I hope i explained more clearly this time.
I'm loving the discussion on this thread.
Hey varun ...siddharth is absolutely correct ...there are no assumptions whatsoever ...
My attempt at explanation :
Median is the middle value of the set ...hence the median of 89 elements is the value corresponding to 45th element when arranged in a sequential manner ( ascending or descending, that does not matter ) ...
Now, it is pretty clear that each of the 45 boxes on shelf J weigh less than each of the 44 boxes on shelf K ...
Hence, sequence of 89 boxes would start from lightest box of shelf J to heaviest box on shelf K ...Hence middle value of the ordered set is the 45th box i.e the heaviest box of shelf J ....
Hence, St 1 is sufficient ...once we know the weight of heaviest box of shelf J, weight of all other boxes on shelf J become insignificant ..
It would not even matter if all of the boxes weigh equal or different ..
I hope this settles the doubt
ok.. 45 boxes each weighs 15KG in J
>>INFO NOT KNOWN TO US
but for 44 next boxes the weights are in ascending order starting from 20.. it wud be something like 20, 21, 22, 23....64 or lets say even worse example, 15.014, 16.123, 18.905 etc etc
now tell me wats the median?? Can u tell me the median value only on the basis of weight of boxes in J..??..
Hey Varun,
Probably i'm not able to understand your question man. Anyways try to solve this problem after sometime.
Hey Varun,
Probably i'm not able to understand your question man. Anyways try to solve this problem after sometime.
u know wat.. gimme your number and I shall call u sometime.. and bug you with all my quant queries..
nuttyvarun Saysu know wat.. gimme your number and I shall call u sometime.. and bug you with all my quant queries..
Hey varun,
I'm not a quant guru
. Anyways I'll PM my number.
Hello everyone,
How's it going? I am new to pagalguy.com and was wondering if you could help me out a little. I have attached a file (sorry for the inconvenience, but I needed the triangle from the question), whose solution I am unable to understand.
Can anyone help me out here??
I guess statement 1 alone is sufficient to ans the q
You got the answer right!! But how do I solve it?? Its just not coming to me. I believe it has something to do with similar triangles, but I just can't seem to derive it.
Any further help would be greatly appreciated!!