U can calulate the range of the numbers using the inequalities, and the both x and y are +ve. So C.
Hi can u elaborate it a little more? I am drawing the graps and find out that the entire region of the two graps coming in second quadrant making x0 so making D as answer. I know I am wrong somewhr.
Hi can u elaborate it a little more? I am drawing the graps and find out that the entire region of the two graps coming in second quadrant making x0 so making D as answer. I know I am wrong somewhr.
There won't be any intersection in the IInd quad. Check your equations again:lookround:
May be you are marking the regions wrong after drawing the correct lines. Put (0,0) (say) in each line and see the sign (+/-) to get the correct region on the number line.
U can calulate the range of the numbers using the inequalities, and the both x and y are +ve. So C.
Take 1) x-y>-2 so we have 2 unknowns and 1 equation. so 1) alone is insuff
take 2) x-2y take both 1) and 2) we get x-y>-2 and 2y-x>6. Solving, we get y>4 and x>2. so both are +ve real numbers hence product is always +ve. Hence C.
few DS problems. Please post explanations as well as i need to find the best approach.
Are x and y both positive? 1. 2x - 2y =1 2. x/y > 1
Is x-y > |x| -y? 1. y 2. xy The positive integers x, y, and z are such that x is a factor of y and y is a factor of z. is z even?
1. xz is even 2. y is even
1)E consider 1, x-y = .5 so there are number of solns for this equation so insuff consider 2 not suff, as x,y can be both -ve or +ve
consider both still there is no clue of the sign
2)C consider 1) we can have many equations satisfying the inequality. so insuff conisder 2) we dont know whether x is +ve or y. so insuff Consider both we know the signs and hence can solve the equation.
3)B
here y/x and z/y the question is z even?
consider 1) either x or z can be even so insuff
Consider 2) y is even so z has to be even as an odd number cannot have even factors.
In a certain senior class, 72 percent of the male students and 80 percent of the female students have applied to college. What fraction of the students in the senior class are male?
(1) There are 840 students in the senior class (2) 75 percent of the students in the senior class have applied to college
1)E consider 1, x-y = .5 so there are number of solns for this equation so insuff consider 2 not suff, as x,y can be both -ve or +ve
consider both still there is no clue of the sign
2)C consider 1) we can have many equations satisfying the inequality. so insuff conisder 2) we dont know whether x is +ve or y. so insuff Consider both we know the signs and hence can solve the equation.
3)B
here y/x and z/y the question is z even?
consider 1) either x or z can be even so insuff
Consider 2) y is even so z has to be even as an odd number cannot have even factors.
1) Is x^y option 1 : y^2=x , then to check if x^y 2 the inequality remains the same y reverses --> no relevance option 2 : y so Answer is 5 ------------------------------------------ 2) Is 1/(a-b) 1) alet a-b = A then 1/A +A so a-b should be definitely negative or definitely postive to get the answer. Option 1 )a a-b Option 2) 1 a-b >1 or a-b so Answer is 1 ------------------------------------------ 3) In the fraction x/y, where x and y are +v integers, what is the value of y? 1) the least common denominator of x/y and 1/3 is 6. 2) x=1
option 1 )Least common denominator of x/y and 1/3 is 6 so Y can be 2 or 6 or ..so value of y cant be found Option 2) x = 1 who cares this is not relevant at all..!! so Answer is 5 ------------------------------------------ 4)If x is a +ve integer and w is a -ve integer, what is the value of xw?
1) x^w= 1/2 2) w=-1
Option 1) x^w= 1/2 since w is negative. and the RHS is a 2^-x form,(2^-1) X is a multiple of 2 2^w =1\2 w = -1 4^w =1\2 w = -1/2 ... so on ....!! but we know W is an integer , a negative integer so (x,w) can be only (2,-1) so Answer is 1 ------------------------------------------ 5) Is x/m (m^2+n^2+k^2) = xm+yn+zk?
1) z/k = x/m 2) x/m = y/n
x*m^2+x*n^2+x*k^2) = x*m*m+y*m*n+z*m*k x*n*n + x*k*k = y*m*n+z*m*k ? is the kostin.. option 1 z/k = x/m --> k*x =m*z x*n*n + x*k*k = y*m*n+z*m*k -->x*n*n = y*m*n ? --> x*n =y*m ? so u cant answer from this option 2 x/m = y/n -->m*y =x*n x*n*n + x*k*k = y*m*n+z*m*k--> k*x =m*z ? so u cant answer from this taking both u get x/m (m^2+n^2+k^2) = xm+yn+zk so so Answer is 3 ------------------------------------------ 6)if k and n are integers is n divisible by 7? 1) n-3 =2k 2)2k+4 is divisible by 7.
option 1 : n =2k+3 --> no relevance option 2 : 2k+4 is divisible by 7 no relevance to n joining both n = 2k+4-1 --> 7p-1 so is not divisble by 7 hence so Answer is 3
P.S: will add other answer in a while ..brb :lunch :biggrin:
In a certain senior class, 72 percent of the male students and 80 percent of the female students have applied to college. What fraction of the students in the senior class are male?
(1) There are 840 students in the senior class
(2) 75 percent of the students in the senior class have applied to college
Let male students be M and female students be f total students=m+f Consider statement 1 Total 840 students i.e. m+f=840 0.72m+ .80f=students who applied for college--> this is not given so insufficient
Consider statement 2
.75(m+f)=students who applied for college=0.72m+ .80f only one equation-- so not sufficient
1) Is x^y option 1 : y^2=x , then to check if x^y 2 the inequality remains the same y reverses --> no relevance option 2 : y so Answer is 5 ------------------------------------------ 2) Is 1/(a-b) 1) alet a-b = A then 1/A +A so a-b should be definitely negative or definitely postive to get the answer. Option 1 )a a-b Option 2) 1 a-b >1 or a-b so Answer is 1 ------------------------------------------ 3) In the fraction x/y, where x and y are +v integers, what is the value of y? 1) the least common denominator of x/y and 1/3 is 6. 2) x=1
option 1 )Least common denominator of x/y and 1/3 is 6 so Y is a multiple of 6 like 6, 12, 18 etc .. Option 2) x = 1 who cares this is not relevant at all..!! so Answer is 5 rechecked-value of y could be 2 also.ans remains the same. ------------------------------------------ 4)If x is a +ve integer and w is a -ve integer, what is the value of xw?
1) x^w= 1/2 2) w=-1
Option 1) x^w= 1/2 since w is negative. and the RHS is a 2^-x form,(2^-1) X is a multiple of 2 2^w =1\2 w = -1 4^w =1\2 w = -1/2 ... so on ....!! but we know W is an integer , a negative integer so (x,w) can be only (2,-1) so Answer is 1 ------------------------------------------ 5) Is x/m (m^2+n^2+k^2) = xm+yn+zk?
1) z/k = x/m 2) x/m = y/n
x*m^2+x*n^2+x*k^2) = x*m*m+y*m*n+z*m*k x*n*n + x*k*k = y*m*n+z*m*k ? is the kostin.. option 1 z/k = x/m --> k*x =m*z x*n*n + x*k*k = y*m*n+z*m*k -->x*n*n = y*m*n ? --> x*n =y*m ? so u cant answer from this option 2 x/m = y/n -->m*y =x*n x*n*n + x*k*k = y*m*n+z*m*k--> k*x =m*z ? so u cant answer from this taking both u get x/m (m^2+n^2+k^2) = xm+yn+zk so so Answer is 3 ------------------------------------------ 6)if k and n are integers is n divisible by 7? 1) n-3 =2k 2)2k+4 is divisible by 7.
option 1 : n =2k+3 --> no relevance option 2 : 2k+4 is divisible by 7 no relevance to n joining both n = 2k+4-1 --> 7p-1 so is not divisble by 7 hence so Answer is 3
P.S: will add other answer in a while ..brb :lunch :biggrin:
Coz we are interested to compare y^2y and y^(y^2) ... Now, y could be -ve integers as well ...so it would depend whether y is -ve odd or -ve even .. not decisive ..Ans E ...
Guys, here is a very simple DS, just want to confirm the answer..
If n is an integer and 100 n n? (1) N/36 is an odd integer. (2) N/45 is an even integer. Another PS (sorry , i know that there is a different thread), i just want to make sure that my answers, which seem to be not matching to OA, are right.. At a certain company, each employee has a salary grade s that is at least 1 and at most 5. Each employee receives an hourly wage p, in dollars, determined by the formula p = 9.50 + 0.25(s 1). An employee with a salary grade of 5 receives how many more dollars per hour than an employee with a salary grade of 1? A.$0.50 B.$1.00 C.$1.25 D.$1.50 E.$1.75 Cheers