there is a problem given in the gmat prep prac test..
Are positive integers p and q both greater than n?
1-p-q is greater than n 2-q>p
please answer with explanation.
Ques: Are positive integers p and q both greater than n?
Key word: both p and q are "positive integers"
option 1: p-q is greater than n
lets assume values in here.. p = 10 & q = 6 p - q = 10 - 6 = 4
lets shuffle the values p = 6, q = 10, thus 6 - 10 = -4
thus p and q both are greater than n
lets change the values in here such that the p and q are farther from each other p = 10 and q = 4 p - q = 10 - 4 = 6
but here q so there is no clarity on the relative values of p, q and n.
NOT SUFF option 2: q>p
this is just in addition to the above statement and I palced in order to confuse the test taker I guess.. this one its own is NOT SUFF now combining the 2 equations; if q > p and also p - q > n, then the value of n would always be smaller than both p and q
puys help me in solving this .. actually looking for a short cut to solve it..the guess wrk..etc
Store S sold a total of 90 copies of a certain book during the seven days of last week,and it sold different numbers of copies on any two of the days.If for the seven days Store S sold the greatest number of copies on Saturday and the second greatest number of copies on Friday, did the Store S sell more than 11 copies on Friday?
1-Last week store S sold 8 copies of the book on Thursday. 2-Last week store S sold 38 copies of the book on Saturday.
looks pretty straight forward.. hope my answer is correct
90 books in 7 days.. Max sold on Saturday and 2nd to Max sold on Friday.. different numbers of copies sold on any two days..
Ques: did the Store S sell more than 11 copies on Friday????
Option 1: Last week store S sold 8 copies of the book on Thursday.
Doesnt help at all since it doesnt tell the standing of thrusday, books sold on saturday or friday etc..
NOT SUFF Option 2: Last week store S sold 38 copies of the book on Saturday.
Let do some calculation.. 90 - 38 = 52
ques is "did the Store S sell more than 11 copies on Friday" that means did the store sell 12 or more copies..
52 - 12 (for Friday) = 40 Now 5 days 40 books, no 2 days sold the same number of books.. can we arrange.. lets see.. 11 + 10 + 9 + 8 + 2 (taking extreme case..).. so its possible..
lets try reverse.. lets assume Friday was less than or equal to 11. 52 - 11 = 41 10 + 9 + 8 + 7 + 6 = 40 So anything equal or less than 11 is not possible..
so it must have definitely sold more than 11.
SUFF
my answer is option B
also lemme know if this is short enuff approach for you 😉
looks pretty straight forward.. hope my answer is correct
90 books in 7 days.. Max sold on Saturday and 2nd to Max sold on Friday.. different numbers of copies sold on any two days..
Ques: did the Store S sell more than 11 copies on Friday????
Option 1: Last week store S sold 8 copies of the book on Thursday.
Doesnt help at all since it doesnt tell the standing of thrusday, books sold on saturday or friday etc..
NOT SUFF Option 2: Last week store S sold 38 copies of the book on Saturday.
Let do some calculation.. 90 - 38 = 52
ques is "did the Store S sell more than 11 copies on Friday" that means did the store sell 12 or more copies..
52 - 12 (for Friday) = 40 Now 5 days 40 books, no 2 days sold the same number of books.. can we arrange.. lets see.. 11 + 10 + 9 + 8 + 2 (taking extreme case..).. so its possible..
lets try reverse.. lets assume Friday was less than or equal to 11. 52 - 11 = 41 10 + 9 + 8 + 7 + 6 = 40 So anything equal or less than 11 is not possible..
so it must have definitely sold more than 11.
SUFF
my answer is option B
also lemme know if this is short enuff approach for you ;)
yaa varun.. the OA is B.
it took me long enuf in the mock test and that too i got it wrong by silly mistake I did while doing calculations.
I was actually looking for any short approach apart from this which cud have saved the calculations.
well.. the post looks big.. but the actual approach is not that big..
and trust me if you are good at numbers you should be able to kick this out of ya rack of ques in less than 1min.. but since I am not good with counting on fingers and in my mind, I would have done it no other way than the way I have depicted in the post :lookround:
yaa varun.. the OA is B.
it took me long enuf in the mock test and that too i got it wrong by silly mistake I did while doing calculations.
I was actually looking for any short approach apart from this which cud have saved the calculations.
A certain automobile manufacturer suggests a retail price for every car it builds. A car dealer bought a car from the manufacturer at a price below the manufacturer's suggested retail price (MSRP) and then sold the car to a customer. Was the price that the customer paid to the dealer more than the MSRP?
(1) The retailer paid the manufacturer 90% of the MSRP.
(2) The retailer made a profit on the sale to the customer equal to 10% of the price paid to the manufacturer.
A certain automobile manufacturer suggests a retail price for every car it builds. A car dealer bought a car from the manufacturer at a price below the manufacturer's suggested retail price (MSRP) and then sold the car to a customer. Was the price that the customer paid to the dealer more than the MSRP?
(1) The retailer paid the manufacturer 90% of the MSRP.
(2) The retailer made a profit on the sale to the customer equal to 10% of the price paid to the manufacturer.
Let MSRP=x
from 1) Cost Price to the retailer= .9x
from 2)I can not make anything out of it.
Combining 1 & 2, Selling price of the retailer= .9x +10 percent of .9x = .99 X which is less than X.
The OA is C. Correct me if I am wrong but i think only B is enough. Here is my approach. Lets the Manufaturer's price is M Dealer Pays to the Manufaturer C Selling price of the car is S
We have to find if S From B,
The profit to the delar is 10% of the cost price. Therefore,
S - C = 0.1 C => S = 1.1 C This implies that S And we know from the problem stem that C Please let me know where I went wrong.
Let MSRP=x
from 1) Cost Price to the retailer= .9x
from 2)I can not make anything out of it.
Combining 1 & 2, Selling price of the retailer= .9x +10 percent of .9x = .99 X which is less than X.
The OA is C. Correct me if I am wrong but i think only B is enough. Here is my approach. Lets the Manufaturer's price is M Dealer Pays to the Manufaturer C Selling price of the car is S
We have to find if S From B,
The profit to the delar is 10% of the cost price. Therefore,
S - C = 0.1 C => S = 1.1 C This implies that S
And we know from the problem stem that C Please let me know where I went wrong.
The OA is C. Correct me if I am wrong but i think only B is enough. Here is my approach. Lets the Manufaturer's price is M Dealer Pays to the Manufaturer C Selling price of the car is S
We have to find if S From B,
The profit to the delar is 10% of the cost price. Therefore,
S - C = 0.1 C => S = 1.1 C This implies that S And we know from the problem stem that C Please let me know where I went wrong.
Consider the 2 cases below
Case1: M = 100 S = 99 P= 9.9 C = 108.9 C > M
Case2 M = 100 S = 80 P = 8 C = 88 C You can't decide frm statement 2
Looking at options: 1. we dont know if there are other flavors also in the jar . Insuff. 2. Same as A. Only the ratio of almont cookies does nt give any info about choco ones. Insuff
Considering both together: This clarifies that we have only almond and choco cookies in the jar.
So if almond cookies are x, choco are 2x. probability of picking a coco is : 2x/3x= 2/3
Q. When a cookie is taken at random from a jar, what is the probability that it is chocolate flavored?
There are twice as many chocolate flavored cookies as there are almond flavored cookies in the jar.
One third of the cookies in the jar are almond flavored.
