23. At a certain bookstore, each notepad costs x dollars and each markers costs y dollars.
If $10 is enough to buy 5 notepads and 3 markers, is $10 enough to buy 4 notepads and 4
markers instead?
1). each notepad cost less than $1
2). $10 is enough to buy 11 notepads
I'm getting a D...
1) Let's take the exytreme cases...if N = 1$
then from stem M = 5/3$
to test it further the condition..
4N + 4M = 4*1+5/3*4 > 10..
lest take next case N = 0
M = 10/3$
4N + 4M = 10*4/3$ > 10...
A is sufficient...
OA is E)...could you please explain?
1) x^2 is +ve #==> x is +ve or -ve
2)x.y is not +ve # ==> x is zero or -ve
1 & 2 ==> x is -ve , Hence option C
^ +1 agreed !!!!
If x is an integer, is y an integer?
(1) The average (arithmetic mean) of x, y and y - 2 is x.
(2) The average (arithmetic mean) of x and y is not an integer.
Puys..help me out 2 sort out d ans...
OA-> A
My ans -> E
If x is an integer, is y an integer?
(1) The average (arithmetic mean) of x, y and y - 2 is x.
(2) The average (arithmetic mean) of x and y is not an integer.
Puys..help me out 2 sort out d ans...
OA-> A
My ans -> E
statement 1: (x+y+y-2)/3 = x
x+2y-2=3x
2y-2 = 2x
y-1 = x
Since x is an integer Y is also an integer. Sufficient
Statement 2 is insufficient
Ans: A
A)
(X+Y+Y-2)/3 = X
---> 2X=2Y-2, ---> X = Y-1
as X is integer, Y is also an integer
Sufficient
B) we cannot say X is an integer. It can be real number also.
Insufficient
In a certain bookstore, each notepad costs x dollars and each markers costs y dollars.
If $10 is enough to buy 5 notepads and 3 markers, is $10 enough to buy 4 notepads and 4
markers instead?
1). each notepad cost less than $1
2). $10 is enough to buy 11 notepads
1). each notepad cost less than $1
2). $10 is enough to buy 11 notepads
1) Use two ends of extremes.
If Notepad cost = 0.99, then Marker cost is around 1.66, making it impossible to buy 4 Note pads and 4 Markers
If Notepad cost = $0.5, and the marker cost is $1 (the question stem says $10 is 'enough'). In this case with $10 we can buy 4 notepads and 4 markers
---> INSUFFICIENT
2) By the same logic as mentioned in case 1, it is not clear whether we can buy 4 notepads and 4 markers
---> INSUFFICIENT
Ans is: E
If $10 is enough to buy 5 notepads and 3 markers, is $10 enough to buy 4 notepads and 4
markers instead?
1). each notepad cost less than $1
2). $10 is enough to buy 11 notepads
1). each notepad cost less than $1
2). $10 is enough to buy 11 notepads
1) Use two ends of extremes.
If Notepad cost = 0.99, then Marker cost is around 1.66, making it impossible to buy 4 Note pads and 4 Markers
If Notepad cost = $0.5, and the marker cost is $1 (the question stem says $10 is 'enough'). In this case with $10 we can buy 4 notepads and 4 markers
---> INSUFFICIENT
2) By the same logic as mentioned in case 1, it is not clear whether we can buy 4 notepads and 4 markers
---> INSUFFICIENT
Ans is: E
In a certain bookstore, each notepad costs x dollars and each markers costs y dollars.
If $10 is enough to buy 5 notepads and 3 markers, is $10 enough to buy 4 notepads and 4
markers instead?
1). each notepad cost less than $1
2). $10 is enough to buy 11 notepads
1). each notepad cost less than $1
2). $10 is enough to buy 11 notepads
1) Use two ends of extremes.
If Notepad cost = 0.99, then Marker cost is around 1.66, making it impossible to buy 4 Note pads and 4 Markers
---> INSUFFICIENT
2) By the same logic as mentioned in case 1, it is not clear whether we can buy 4 notepads and 4 markers
---> INSUFFICIENT
Ans is: E
If Notepad cost = $0.5, and the marker cost is $1 (the question stem says $10 is 'enough'). In this case with $10 we can buy 4 notepads and 4 markers
I guess this isn't true....
if Notepad = 0.5 => Marker = 2.5
For the Notepad prblm, my take is option E
There can be 2 possibilities with both the statments combined
y = 2 ; x = .8 (8 + 1.6 )
y = 3 ; x = .2 ( 12 + .
So my take is option E
23. At a certain bookstore, each notepad costs x dollars and each markers costs y dollars.
If $10 is enough to buy 5 notepads and 3 markers, is $10 enough to buy 4 notepads and 4
markers instead?
1). each notepad cost less than $1
2). $10 is enough to buy 11 notepads
I'm getting a D...
1) Let's take the exytreme cases...if N = 1$
then from stem M = 5/3$
to test it further the condition..
4N + 4M = 4*1+5/3*4 > 10..
lest take next case N = 0
M = 10/3$
4N + 4M = 10*4/3$ > 10...
A is sufficient...
OA is E)...could you please explain?
My take : option-> E
Heres another one..
If x and y are positive. is y
(1) x > 2y
(2) x + 2
Bit confused wid d OA.. plz sort it out.. OA later..
Taking only (1)x = 4 y = 1
x = 9 y = 3 .Nt suff
Taking only (2) x = 2 y = 3
x = 1 y = 1 Nt suff
Combining both statements,we get x= 1 and y=0.But q states y as positive. 0 is neither + nor - confused.
Anyways I will go with option C
Heres another one..
If x and y are positive. is y
(1) x > 2y
(2) x + 2
Bit confused wid d OA.. plz sort it out.. OA later..
IMO C
From 1) we have the condition where y> 2 and y
Fro m2) we have a condition where y>2 and y
Combining both we have y
In a certain bookstore, each notepad costs x dollars and each markers costs y dollars.
If $10 is enough to buy 5 notepads and 3 markers, is $10 enough to buy 4 notepads and 4
markers instead?
1). each notepad cost less than $1
2). $10 is enough to buy 11 notepads
1). each notepad cost less than $1
2). $10 is enough to buy 11 notepads
1) Use two ends of extremes.
If Notepad cost = 0.99, then Marker cost is around 1.66, making it impossible to buy 4 Note pads and 4 Markers
If Notepad cost = $0.5, and the marker cost is $1 (the question stem says $10 is 'enough'). In this case with $10 we can buy 4 notepads and 4 markers
---> INSUFFICIENT
2) By the same logic as mentioned in case 1, it is not clear whether we can buy 4 notepads and 4 markers
---> INSUFFICIENT
Ans is: E
The question says " is $10 enough to buy 4 notepads and 4
markers instead" .
So it is enough to find out whether 4x+4y=10.
Now from 1) we have x
so from the info abv we can see that we can 4 note pads and 4 markers as it costs less than 10 dollars. So suff
Take 2) we have x = 10/11. so from this we have y = 20/11 so subs these values in 4x+4y=10 we have 120/11 so we cannot buy 4 markers and 4 notes pads. So suff
Hence D.
IMO C
From 1) we have the condition where y> 2 and y
Fro m2) we have a condition where y>2 and y
Combining both we have y
Hey siddharth..
plz clarify ..
y>2 and YIs Y ?
Im confused.. OA is C but wid d same conclusion i marked E.
Hey siddharth..
plz clarify ..
y>2 and YIs Y ?
Im confused.. OA is C but wid d same conclusion i marked E.
If x and y are positive. is y
(1) x > 2y
(2) x + 2
from 1 we can write the ineq as x-2y>0. but we have multiple scenarios here
such as x= 51 and y = 25; x = .9 and y = 0.4
so insuff
from 2) we can write the eq as x-y-20
here also we get multiple scenarios like 1) so insuff.
combining both and solving for y
we get y
I hope you understood.
The question says " is $10 enough to buy 4 notepads and 4
markers instead" .
So it is enough to find out whether 4x+4y=10.
Now from 1) we have x
so from the info abv we can see that we can 4 note pads and 4 markers as it costs less than 10 dollars. So suff
Take 2) we have x = 10/11. so from this we have y = 20/11 so subs these values in 4x+4y=10 we have 120/11 so we cannot buy 4 markers and 4 notes pads. So suff
Hence D.
Hi Siddarth,
combining both the statements we can have 2 possibilities
1. y = 2 ; x = .8 (8 + 1.6 ) $10 is suff
2. y = 3 ; x = .2 ( 12 + . 0.4) $10 is insuff.
So even combining both the statements we cannot ans the q.
Hi Siddarth,
combining both the statements we can have 2 possibilities
1. y = 2 ; x = .8 (8 + 1.6 ) $10 is suff
2. y = 3 ; x = .2 ( 12 + . 0.4) $10 is insuff.
So even combining both the statements we cannot ans the q.
Can you plz elaborate?
siddharthaduggirala SaysCan you plz elaborate?
Hi Siddarth,
We have to match 3 conditions namely :
1.5x + 3y = 10
2. x 3. 11x
With the above conditions we need to check if 4x+4y
We have two sets of values matching all the above conditions
a) x = 0.8 & y = 2. With this combination we will have 4x+4y b) x = 0.2 & y = 3. With this combination we will have 4x+4y > 10 .So $10 is not suff to buy the items
So we can't conclude even after combining both the statements.
crushkiller Says^ +1 agreed !!!!
amsey1382 SaysAnswer is E)..
Earlier I missed a case (in red)
1) x^2 is +ve #==> x is +ve or -ve
2)x.y is not +ve # ==> x can be zero , -ve and +ve(if y=0)
1 & 2 ==> x can be zero , -ve and +ve , Hence option E
Hey siddharth..
plz clarify ..
y>2 and YIs Y ?
Im confused.. OA is C but wid d same conclusion i marked E.
Simple Explaination:
Combining 1 & 2 you have --> 2y
if y=3 --> 6