dkny.jakhar
(dkny.jakhar)
February 26, 2008, 11:21am
743
@carobee, is the answer Ci.e. 2 integers. my explanation is...let us take 5 consec integers as-- (n-2)+(n-1)+n+(n+1)+(n+2)=35,; where n comes out to be 7... substituting it to get various integers we have....5,6,7,8,9...so only 5&7 are prime... am i right??? regards Jakhar
The sum of 5 consecutive integers is 35. How many of the five consecutive integers are prime numbers? a) 0 b) 1 c) 2 d) 3 e) 4 ****************************************************** If my post benefits you then don't forget to thank me
dkny.jakhar
(dkny.jakhar)
February 26, 2008, 11:27am
744
i even tried the question with the following set of integers... n,n+1,n+2,n+3,n+4... i got the same answer again... regrds Jakhar
carobee
(carobee)
February 26, 2008, 11:30am
745
jakhar lets wait for other to drill their minds...
dkny.jakhar
(dkny.jakhar)
February 26, 2008, 11:41am
746
@carobee, sorry for jumping the gun,, willl wait .. regards Jakhar
jakhar lets wait for other to drill their minds...
ajayreddy
(Ajay Reddy)
February 26, 2008, 2:24pm
747
The sum of 5 consecutive integers is 35. How many of the five consecutive integers are prime numbers? a) 0 b) 1 c) 2 d) 3 e) 4 ****************************************************** If my post benefits you then don't forget to thank me let the 5 nos. be x,x+1,x+2,x+3,x+4,x+5...solving for equation, u get x = 5
hence, nos. are 5,6,7,8,9 out of which 5 and 7 are prime nos.
hence, answer is
C ...
vicky.verma
(vicky.verma)
February 26, 2008, 6:00pm
748
The sum of 5 consecutive integers is 35. How many of the five consecutive integers are prime numbers? a) 0 b) 1 c) 2 d) 3 e) 4 ****************************************************** If my post benefits you then don't forget to thank me The sum of 5 consecutive integers is 35
=> The numbers should lie on either side of average ie. 35/5=7
5 and 7 are the only primes among 5,6,7,8,9
Ans : C
bashask
(bashask)
February 27, 2008, 6:05am
749
How many intergers n are there such that 1 A)Five B)Four C)Three D)Two E)Zero Could u plz clarify about that prob
bashask
(bashask)
February 27, 2008, 6:10am
750
The sum of 5 consecutive integers is 35 => The numbers should lie on either side of average ie. 35/5=7 5 and 7 are the only primes among 5,6,7,8,9 Ans : C i think that would be the best way to solve the above prob.
vicky.verma
(vicky.verma)
February 27, 2008, 6:50am
751
How many intergers n are there such that 1 A)Five B)Four C)Three D)Two E)Zero Could u plz clarify about that prob For 1
n cannot have any -ve value as it will lead to 5n+5 n cannot have any value greater than or equal to 4, coz that will lead to 5n+n >25
n can have only 4 integer values = 0,1,2,3
Ans : B
dkny.jakhar
(dkny.jakhar)
February 27, 2008, 7:22am
752
HI, my take.... B.(there are 4 integers that satisfy the given condition. take n=0 , 5n+5 comes out to be 5, 1take n=1 , 5n+5 comes out to be 10, 1similarly for n=2 and n=3 the condition would be satisfied i hope it helps Regards Jakhar ow many intergers n are there such that 1 A)Five B)Four C)Three D)Two E)Zero Could u plz clarify about that prob
carobee
(carobee)
February 27, 2008, 9:37am
753
The sum of 5 consecutive integers is 35. How many of the five consecutive integers are prime numbers? a) 0 b) 1 c) 2 d) 3 e) 4 ****************************************************** If my post benefits you then don't forget to thank me Ans : C)
The "middle number" should be near 7 because 35/5 = 7. Since 5 + 6 + 7 + 8 + 9 = 35, 5 and 7 are prime numbers
carobee
(carobee)
February 27, 2008, 10:14am
754
How many different positive integers exist between 10^6 and 10^7, the sum of whose digits is equal to 2?
6 7 5 8 18
vicky.verma
(vicky.verma)
February 27, 2008, 11:06am
755
How many different positive integers exist between 106 and 107, the sum of whose digits is equal to 2?6 7 5 8 18 Can you pls check the question.
How many different positive integers exist between 106 and 107
??? between 106 and 107 ???
carobee
(carobee)
February 27, 2008, 11:19am
756
Can you pls check the question. How many different positive integers exist between 106 and 107 ??? between 106 and 107 ??? i have done the corrections please check now
vscid
(vscid)
February 28, 2008, 2:40am
758
A certain car averages 25 miles per gallon of gasoline when driven in the city and 40 miles per gallon when driven on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway? 28 30 33 36 38
vicky.verma
(vicky.verma)
February 28, 2008, 2:54am
759
A certain car averages 25 miles per gallon of gasoline when driven in the city and 40 miles per gallon when driven on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway? 28 30 33 36 38 36
Ans. D
Let me know if this is correct...i'll post the complete soln.
vscid
(vscid)
February 28, 2008, 3:02am
760
D is correct. However please tell me what is the flaw in my approach:25 (1/6) + 40 (5/6) ( 1/6th of the time driven in the city and 5/6th of the time driven on highway) I am getting 37.5.
D is correct. However please tell me what is the flaw in my approach: 25 (1/6) + 40 (5/6) ( 1/6th of the time driven in the city and 5/6th of the time driven on highway) I am getting 37.5. You should look at the fuel consumed when driving in the city and then the fuel used up in the highway and then calculate based on that ..
in this .4 gallon for the city..1.25 gallon for the highway..
u get 60 kilometers in 1.65 gallons..
carobee
(carobee)
February 28, 2008, 7:35am
762
How many different positive integers exist between 10^6 and 10^7, the sum of whose digits is equal to 2?6 7 5 8 18 Find the number of such integers existing for a lower power of 10 and extrapolate the result of the present case.
Between 10 and 100, that is 101 and 102, we have 2 numbers, 11 and 20.
Similarly, between 100 and 1000, that is 102 and 103, we have 3 numbers, 101, 110 and 200.
Therefore, between 106 and 107, one will have 7 integers whose sum will be equal to 2.