Something would be wrong because in the directions say that x and y are integers, so statement 1 could not claim 2x -2y=1.
In the figure shown above, two identical squares are inscribed in the rectangle. If the perimeter of the rectangle is 18 by squareroot2, then what is the perimeter of each square?
(A)8 by squareroot2
(B)12
(C)12 by squareroot2
(D)16
(E)18
Someone please gimme the solution, its been driving me mad :(.
In the figure shown above, two identical squares are inscribed in the rectangle. If the perimeter of the rectangle is 18 by squareroot2, then what is the perimeter of each square?
(A)8 by squareroot2
(B)12
(C)12 by squareroot2
(D)16
(E)18
Someone please gimme the solution, its been driving me mad :(.
Before I actually tell you the solution lets see the choices...if the perimeter of rectangle is 18 by squareroot2 or 9*Root(2) ... Eliminate choices B,D,E coz perimeter of square inside can't be greater than perimeter of rectangle.
Now here is the solution :
Both the squares are identical and we know diagonals of a square are equal => Length of rectangle(l)=2*breadth of rectangle(b)
Perimeter of rectangle = 18/Root(2) = 9*Root(2) = 3*Root(2) + 6*Root(2)
Length(l) = 6*Root(2)
Breadth(b) = 3*Root(2)
Side of square = Root ((b/2)^2 + (l/4)^2)
Perimeter of square = 4*Side of Square .... Rest is all yours :-)
Ans. (C)12 by squareroot2
^ How did you arrive at Side of square^2= ((b/2)^2 + (l/4)^2)??
I didnt get the length/4 part, how did you conclude that it was length by 4?
Hope you dont mind answering that part :).
Dear All,
this email is with reference to the following problem--
i) 2x-2y=1
ii) x/y >1
***************
x and y are integers. Then how can we take values as 7.5 ?
secondly x is supposed to be geater than y as per B. Then how can we take x as -7.5 and y as -7 (on the number line -7 comes first) ?
cheers,
ranjit
Flintoff,Thank you for the reasoning.
Substiture -7.5 with -8.I guess that should solve your doubts.
Thanks,
Raj
^ How did you arrive at Side of square^2= ((b/2)^2 + (l/4)^2)??
I didnt get the length/4 part, how did you conclude that it was length by 4?
Hope you dont mind answering that part :).
l is divided into into 4 equal parts..each of length l/4
Before I actually tell you the solution lets see the choices...if the perimeter of rectangle is 18 by squareroot2 or 9*Root(2) ... Eliminate choices B,D,E coz perimeter of square inside can't be greater than perimeter of rectangle.
Now here is the solution :
Both the squares are identical and we know diagonals of a square are equal => Length of rectangle(l)=2*breadth of rectangle(b)
Perimeter of rectangle = 18/Root(2) = 9*Root(2) = 3*Root(2) + 6*Root(2)
Length(l) = 6*Root(2)
Breadth(b) = 3*Root(2)
Side of square = Root ((b/2)^2 + (l/4)^2)
Perimeter of square = 4*Side of Square .... Rest is all yours :-)
Ans. (C)12 by squareroot2
the actual answer is 6...not mentioned in the options...
the fault in the above logic is...the perimeter is 9*root(2) so total length is 6*root(2)...that is 2*L=6*root(2)...
hence, length=L=3*root(2)...similarly B=1.5*root(2)
simpler method is...let breadth=x
so by logic of length=2*breadth, perimeter=6x
now 6x=9*root(2)
hence x=1.5*root(2)=breadth of rectangle=diagonal of square
now let side of square=a
a*root(2)=diagonal of square=1.5*root(2)
hence, a=1.5
so perimeter of one square=4a=6
the actual answer is 6...not mentioned in the options...
the fault in the above logic is...the perimeter is 9*root(2) so total length is 6*root(2)...that is 2*L=6*root(2)...
hence, length=L=3*root(2)...similarly B=1.5*root(2)
simpler method is...let breadth=x
so by logic of length=2*breadth, perimeter=6x
now 6x=9*root(2)
hence x=1.5*root(2)=breadth of rectangle=diagonal of square
now let side of square=a
a*root(2)=diagonal of square=1.5*root(2)
hence, a=1.5
so perimeter of one square=4a=6
Another way to look at the problem:
Divide the rectangle with 3 diagonals (one horizontal and 2 perpendicular)
Now you have 12 equal parts of the perimeter of the rectangle. Each part equals x. Perimeter of rectangle is 18 square root 2 divide by 12 is equal to 3/2 square root 2 =x.
2x =L (you have a triangle 45 45 90)
So 8x or 4xL equals 12 square root 2.
hello everyone,
I am a mechanical engineer and working with a steel compny for last 3 years..all these years i have never thought of CAT or GMAT..but now i know dat i have to go for dat to make a big leap in the professional game...
and i wld like to appead GMAT....so guys any one help in guiding whats the pettern and how to prepare for it...and 4m wher i will get preparation resources...
and what scrore it needs to make into a good bussiness schools...
ajaya
If points X and Y are two distinct points in the coordinate plane, which of the following can have more than one possible value?
1. The circumference of a circle with diameter XY
2. The area of a square with diagonal XY
3. The perimeter of a right isosceles triangle with a leg XY
4. The area of a circle with chord XY
5. The area of a equilateral triangle with bease XY
If points X and Y are two distinct points in the coordinate plane, which of the following can have more than one possible value?
1. The circumference of a circle with diameter XY
2. The area of a square with diagonal XY
3. The perimeter of a right isosceles triangle with a leg XY
4. The area of a circle with chord XY
5. The area of a equilateral triangle with bease XY
We can go ahead by elimination here.
1. Circumference is always constant as the diameter is constant (pi*diameter)
2. Area is constant when diagonal is constant (dia*dia/2)
3. Perimeter is constant as the leg here is supposedly not the hypotenuse :smile:.
4. The area can vary as the chord can be any line parallel to a diameter or the diameter itself.
5. Area of the equilateral triangle is constant as the side is constant and the area is sqrt(3)*(side)*(side)/4
So answer is 4.
shud be E....both are insufficient and in combination also they tell u nothing....
ab=cd=5 bc=10 cdbc yes
no specific answer.
Hiii
How get the CD u mentioned in the blogspot?
Is it readily available in the market?
Thank you..
If points X and Y are two distinct points in the coordinate plane, which of the following can have more than one possible value?
1. The circumference of a circle with diameter XY
2. The area of a square with diagonal XY
3. The perimeter of a right isosceles triangle with a leg XY
4. The area of a circle with chord XY
5. The area of a equilateral triangle with bease XY
obly ans must be 4
Neo
If points X and Y are two distinct points in the coordinate plane, which of the following can have more than one possible value?
1. The circumference of a circle with diameter XY
2. The area of a square with diagonal XY
3. The perimeter of a right isosceles triangle with a leg XY
4. The area of a circle with chord XY
5. The area of a equilateral triangle with bease XY
1. Since the diameter of the circle is XY, we will always get only one unique area for the circle.
2. Similar to the diameter case, a square will always have a unique length for each side which is diagonal/sqrt(2)...hence, we will get one area for a square too.
3. since one leg of the right isosceles triangle is XY, the length of the other leg too will be XY and the length of the hypotenuse will be sqrt(2)x XY...thus, we will again get a unique answer for the perimeter
4. A chord is any length of line other than the diameter...A circle can have many chords within its perimeter..hence, this is the only option that will give us multiple answers.
5. Since the base is XY, the length of the other two sides is also XY and hence we will get a unique answer.
hence, answer is 4.
p.s. : Mods, plz excuse me this time for including my signature on the post. it was a mistake..it wont happen in future posts.
Hi Guys,
I think Ive spotted an incorrect question in he OG 11.
Question 109 in the Data Sufficiency section is like this:
"Are positive integers p and q both greater than n?
1)p-q is greater than n
2)q>p"
If you go thru the explanation it says:
1st statement implies p>n
2nd statement implies q>p
So together they imply that q>p>n and so answer should be C.
However if q>p, then p-q will be negative and so (p-q) cant be greater than the positive integer n.So i think the 2 statements are not sufficient coz they contradict each other and so the answer should be E.
Please comment.
Hi Guys,
I think Ive spotted an incorrect question in he OG 11.
Question 109 in the Data Sufficiency section is like this:
"Are positive integers p and q both greater than n?
1)p-q is greater than n
2)q>p"
If you go thru the explanation it says:
1st statement implies p>n
2nd statement implies q>p
So together they imply that q>p>n and so answer should be C.
However if q>p, then p-q will be negative and so (p-q) cant be greater than the positive integer n.So i think the 2 statements are not sufficient coz they contradict each other and so the answer should be E.
Please comment.
It does not say whether n is positive or not, only p and q are positive.
The Question 110 i was talking about is from the OG 11 DS Section.Here it is:
Whenever Martin has a restaurant bill with an amount between $10 and $99, he calculates the dollar amount of the tip as 2 times the tens digit of the amount of the bill.If the amount of Martin's most recent restaurant bill was between $10 and $99, was the tip calculated by Martin on his bill greater than 15% of the amount of the bill?
1) Amount of the bill was between $15 and $55
2) The tip calculated by Martin was $8.
Thanks in advance!
The Question 110 i was talking about is from the OG 11 DS Section.Here it is:
Whenever Martin has a restaurant bill with an amount between $10 and $99, he calculates the dollar amount of the tip as 2 times the tens digit of the amount of the bill.If the amount of Martin's most recent restaurant bill was between $10 and $99, was the tip calculated by Martin on his bill greater than 15% of the amount of the bill?
1) Amount of the bill was between $15 and $55
2) The tip calculated by Martin was $8.
Thanks in advance!
Given that he calculates the tip as twice the tens digit and from B this is 8, then the ten's digit has to be 4 which means max bill has to be 49.99. If its greater, then the tip amt > 8.
Is 15% of 49.99 > 2% of 4?? Thus Q can be answered from B
Alright this problem's been driving me nuts.
A fairly biased coin is tossed 6 times. What is the probability that it will fall as a head more than twice but less than 5 times?
a)3/4
b)3/8
c)7/8
d)1/4
e)3/5
Alright this problem's been driving me nuts.
A fairly biased coin is tossed 6 times. What is the probability that it will fall as a head more than twice but less than 5 times?
a)3/4
b)3/8
c)7/8
d)1/4
e)3/5
r u sure dis r the ans options?
my ans works to be 35/64
heads more than 2 n less than 5 implies 2 poss:
1) 3 H & 3 T
OR
2) 4 H & 2 T
i.e (6C3 + 6C4)/2^6
=(20+15)/64
=35/64