Hi Ashish,
I guess he means as in the question ..."that are related linearly. "
If anything is related linearly...then the normal expression will be y = bx + c
where b is the rate of linear increase and c is the constant that varies.......
if it varies quadratically (suppose of degree2 )..then y = ax^2 + bx + c...
Hope you got it...
cheers
:boat: Madhav
Hi ankit,
What u said is absolutely true...I mean..How could i write this (Constant that varies)....
What i mean to say was...b & c are constants that are different for two expressions ....
Anyways..thanks a lot ...I hope i ll not make this again.... 😁
1.C
let that company has 20 projects.....
1.25% of the projects at Company Z have 4 or more employees assigned to each project
ie 5 projects have 4 or more employees. Not sufficient so BCE
2.25 % of the projects at Company Z have 2 or fewer employees assigned to each project
ie 5 projects have 2 or fewer employees. Not sufficient so CE
Combining, the rest of the projects have 3 employees each......ie projects from 6-15
so median is the average no: of employees in 10& 11th project and it is 3 employees...... SO ans C
2.is r^2+s^2?
Sorry Guys,
My mistake in typing........The questions should be as below:
Q1. What is the median no. of employees assigned per project for the projects at Company Z?
1.25% of the projects at Company Z have 4 or more employees assigned to each project
2.35 % of the projects at Company Z have 2 or fewer employees assigned to each project
Q2. In the xy plane, point(r,s) lies on the circle with its center at the origin. What is the value of r^2+s^2 ?
1.The circle has radius 2
2.The point (v2, -v2) lies on the circle
Please revert with your answers and explanations.
Regards
MSD
What does it mean if we say that a graph is symmetrical at a point x=2 ?
Also, Is there a relationship between coordinates of a perpendicular line ?
16. The triangles in the figure attached are equilateral and the ratio of the length of a side of the larger triangle to the length of a side of the smaller triangle is . If the area of the larger triangular region is K, what is the area of the shaded region in terms of K?
(A)
(B)
(C)
(D)
(E)
(A)
(B)
(C)
(D)
(E)
Can some one help with the attached question
Another one
18. In the figure above, three squares and a triangle have areas of A, B, C, and X as shown. If A = 144, B=81, and C=225, then X =
(A) 150
(B) 144
(C) 80
(D) 54
(E) 36
Another one
18. In the figure above, three squares and a triangle have areas of A, B, C, and X as shown. If A = 144, B=81, and C=225, then X =
(A) 150
(B) 144
(C) 80
(D) 54
(E) 36
area of square=(side)^2
hence, side of square A=12
side of square B=9
side of square C=15
this is a triplet: 12^2 + 9^2 = 15^2
hence, the triangle has to be a right angled triangle
area of triangle X = 0.5*12*9=54
16. The triangles in the figure attached are equilateral and the ratio of the length of a side of the larger triangle to the length of a side of the smaller triangle is . If the area of the larger triangular region is K, what is the area of the shaded region in terms of K?
(A)
(B)
(C)
(D)
(E)
for the triangles to equilateral, the attached figure should be the one....let me know if i misinterpreted the ques
harneet.m.kaur SaysCan some one help with the attached question
the perimiter of the circular portion will be 0.75 *(2*pi*r)=3*pi
for the triangular part, draw the figure as attached.
now, angle AOB=90 degrees as the circumference of the givn circular part is 0.75 of the actual circle which subtends 270 degrees . Hence, the remaining angle=90 deg.
Now, AB^2=OA^2+OB^2=2^2+2^2=8
AB=2*sqrt(2)
Now, AQ^2=AP^2+PQ^2
=(AB/2)^2+(PQ)^2
=(Sqrt(2))^2+5^2
=27
hence, AQ=3*sqrt(3)
also, BQ=AQ, as it is an isosceles triangle
hence, perimieter=3*pi+AQ+BQ=3*pi+2*3*sqrt(3) = 3*pi+6*sqrt(3)
In this figure 3/4 of a circle mean that the angle made at the triangle by the two radius of the circle is 90. As you know the radius you can find out half the base of the triangle.using it and the hight given you can find the perimeter
For the first one Both are required and are sufficient
25% above 4 and 35% below 2 leaves you with 3 employees as median
for the second radius is sqrt(r^2 + s^2) therefore 1 is sufficient , i donno what v2 and -v2 means , if v is a variable 2 is not sufficent else distance of this point from origin is the radius
holy_luv Saysfor the triangles to equilateral, the attached figure should be the one....let me know if i misinterpreted the ques
Thats the figure. Do you have a soln to this problem
:
the perimiter of the circular portion will be 0.75 *(2*pi*r)=3*pi
for the triangular part, draw the figure as attached.
now, angle AOB=90 degrees as the circumference of the givn circular part is 0.75 of the actual circle which subtends 270 degrees . Hence, the remaining angle=90 deg.
Now, AB^2=OA^2+OB^2=2^2+2^2=8
AB=2*sqrt(2)
Now, AQ^2=AP^2+PQ^2
=(AB/2)^2+(PQ)^2
=(Sqrt(2))^2+5^2
=27
hence, AQ=3*sqrt(3)
also, BQ=AQ, as it is an isosceles triangle
hence, perimieter=3*pi+AQ+BQ=3*pi+2*3*sqrt(3) = 3*pi+6*sqrt(3)
May be I am missing a point - Can you explain why PQ is bisecting AB ?
18. The figure above shows the dimensions of a rectangular board that is to be cut into four identical pieces by making cuts at points A, B, and C, as indicated. If x = 45, what is the length AB ?
(1 foot = 12 inches)
(A) 5 ft 6 in
(B) 5 ft in
(C) 5 ft 3 in
(D) 5 ft
(E) 4 ft 9 in
Q. If Line k in the xy plane has the equation y=mx+b, where m and b are constants, what is the slope of line k?
1. k is parallel to the line with equation y = (1-m)x +b+1
2. k intersects the line with equation y = 2x+3 at the point (2,7)
Please help with explanation.:boat:
Q. If Line k in the xy plane has the equation y=mx+b, where m and b are constants, what is the slope of line k?
1. k is parallel to the line with equation y = (1-m)x +b+1
2. k intersects the line with equation y = 2x+3 at the point (2,7)
Please help with explanation.:boat:
Is the answer A ?
harneet.m.kaur SaysMay be I am missing a point - Can you explain why PQ is bisecting AB ?
since the triangle is isosceles...the perpendicular (PQ) drawn from the vertex (P) to the side which is not equal to the other two (AB), is also a median to that side. this is true for an equilateral triangle too.
18. The figure above shows the dimensions of a rectangular board that is to be cut into four identical pieces by making cuts at points A, B, and C, as indicated. If x = 45, what is the length AB ?
(1 foot = 12 inches)
(A) 5 ft 6 in
(B) 5 ft in
(C) 5 ft 3 in
(D) 5 ft
(E) 4 ft 9 in
Since, x=45, AP=PQ=6inches. Also, the figure is symmetrical so RB=20 ft/2=10 ft.
Now, RB=RA+AP+PB=10ft. Here, RA=PB
hence, PB=(10ft-6in)/2= 4ft 8in.
AB=AP+PB=4ft 8in + 6in =5ft 2in
can u chk the options?
Q. If Line k in the xy plane has the equation y=mx+b, where m and b are constants, what is the slope of line k?
1. k is parallel to the line with equation y = (1-m)x +b+1
2. k intersects the line with equation y = 2x+3 at the point (2,7)
Please help with explanation.:boat:
y=mx+b----(1)
with the first stmnt. we get,
y=x-mx+b+1----(2)
sub 1 and 2, we get, m=(x-1)/2x----(3)
=>stmnt.1 is not sufficient
from stmnt 2, substitute co-ordinates in (1): 7=2m+b
=>stmnt 2 is not sufficient.
Now combine both stmnts....u get x=2 substitue it in eq(3) and u have m=1/3
hence the ques can b answerd by both the stmnts