My pick is A.. 4 cm
whats the OA?
A cylinder holds 10 liters of water. All of the water is poured into a cube, 50 cm on a side. What is the depth of the water (1 liter equals 1000 cubic cm of water)?
A) 4cm
B) 10cm
C) 40cm
D) 60cm
E) 100cm
My answer is D..
Alchemist-MBA where are you My Friend??
Need your inputs on my previous questions!
And here is another DS!!
If X+Y = 20, and XU+V
1. Y+U+V = 30
2. U+V
Please Help!!
A man can hit a target once in 4 shots. If he fires 4 shots in succession, what is the probability that he will hit his target?
A. 1
B.
C.
D.
E.
My Pick is D)
Whats the OA
D is right!
Can u please explain...
My Pick is D)
Whats the OA
q1) B
q2) let first odd no. be x
hence sum of first 6 odd nos, = 6x+30 = 6a
hence a = x+5
As x is odd, x+5 is always even.
For x = -5(an odd no), a becomes zero.
i am nt able to digest he D can be the OA can be D
For me its B.
thanks
I would agree with you.. that answer must be 'B'. odd numbers can be written in the form of '2n+1'-- so 6 odd integers can be -> 2n-5, 2n-3, 2n-1, 2n+1, 2n+3, 2n+5... so A.M can be 2n.... and clearly only III, will hold.
Where did you get the questions from?
DS
Is the positive integer r an even number?
(1) r is a prime number
(2) 3
PS
If a is the average (arithmetic mean) of 6 consecutive odd integers, which of the following must be true?
(I) a is a multiple of 6
(II)a is a non-zero integer
(III)a is an even integer
(A) I Only
(B) III Only
(C) I and III only
(D) II and III only.
(E) I , II and IIIS
You mentioned that OA is 'B' - but i would disagree.. it should be 'A'.
Is the positive integer r an even number?
(1) r is a prime number --- if r is a prime number, then it cannot be even.. (if its even - it would be divisible atleast by '2' - and hence cannot qualify to be a prime number in the first place) --> Sufficient
(2) 3 can be any no. b/w 3 and 26.... Not Sufficient
Solution should be 'A'.
A man can hit a target once in 4 shots. If he fires 4 shots in succession, what is the probability that he will hit his target?
A. 1
B.
C.
D.
E.
Prob = Prob. that he hits 1, 2,3, or 4 times
= 1 - Prob. that he hits none of the times
= 1 -(3/4 x 3/4 x 3/4 x 3/4) = 175/256
My take 'D'.
Calendar SaysThe answer should be D. whats the OA?
My take too is 'D'.
stmt 2 is clear.
stmt 1 -- the maximum value 'y' can take is 10.0000001.. which makes u+v to be 19.9999999999 which is definitely less than 20.
D is right!
Can u please explain...
There are 4 cases
Probability that he will hit the target in 1st shot = 1/4
Probability that he will hit the target in 2nd shot = 3/4 (miss the 1st) x 1/4
Probability that he will hit the target in 3rd shot =3/4 x 3/4 x 1/4
Probability that he will hot the target in 4th shot = 3/4 x 3/4 x 3/4 x 1/4
Sum of all =175/256
Hope this helps u...
You mentioned that OA is 'B' - but i would disagree.. it should be 'A'.
Is the positive integer r an even number?
(1) r is a prime number --- if r is a prime number, then it cannot be even.. (if its even - it would be divisible atleast by '2' - and hence cannot qualify to be a prime number in the first place) --> Sufficient
(2) 3 can be any no. b/w 3 and 26.... Not Sufficient
Solution should be 'A'.
Alchemist,
2 is the an even prime no:.
Alchemist,
2 is the an even prime no:.
Absolutely - so i take back my statement...
Both should be insufficient.. 'E'?
Absolutely - so i take back my statement...
Both should be insufficient.. 'E'?
Is the positive integer r an even number?
(1) r is a prime number
(2) 3
But, prime no: between 3 and 26 are all odd. So IMO ans is C.
Is the positive integer r an even number?
(1) r is a prime number
(2) 3
But, prime no: between 3 and 26 are all odd. So IMO ans is C.
Yes.. sounds right..
Last month 15 homes were sold in town X. The average sale price of teh homes was $ 150,000 and the median sales price was $130,000. Which of the following must be true?
I. At least one of the homes was sold for more than $165,000
II._____________________________ more than $130,000 and less than $150,000.
III. _____________________________ less than $130,000.
A.I only
B.II only
C. III only
D. I and II
E. I and III
My pick is C
Last month 15 homes were sold in town X. The average sale price of teh homes was $ 150,000 and the median sales price was $130,000. Which of the following must be true?
I. At least one of the homes was sold for more than $165,000
II._____________________________ more than $130,000 and less than $150,000.
III. _____________________________ less than $130,000.
A.I only
B.II only
C. III only
D. I and II
E. I and III
alchemist-mba SaysYes.. sounds right..
Hi all,
Thanks for solving this puzzle, yes my answer too is C.
However, the Pearsons GMAT prep ( low priced edition) says B which i completely disagree.
Jishnu
Last month 15 homes were sold in town X. The average sale price of teh homes was $ 150,000 and the median sales price was $130,000. Which of the following must be true?
I. At least one of the homes was sold for more than $165,000
II._____________________________ more than $130,000 and less than $150,000.
III. _____________________________ less than $130,000.
A.I only
B.II only
C. III only
D. I and II
E. I and III
The question can be reduced to the problem where the sum of 15 numbers is 225, where the median is 13 and the mean is 15.
Considering the following cases, numbers arranged in increasing order:
1.(13, 13, 13, 13, 13, 13, 13, 13, 17, 17, 17, 17, 17, 18, 18 ). In this case the maximum price of the house is at least 170, 000. Hence I is true. This also a case where none of the house is priced below 130,000, hence III is not true.
2.Considering the cases where the median can be fixed at 13:
a) (9, 10, 11, 11, 13, 13, 13, 13, 15, 15, 16, 20, 21, 22, 23)
b) (10, 11, 11, 11, 12, 12, 12, 13, 15, 16, 18, 19, 20, 21, 24)
in cases both a and b the median is 13, mean is 15 but the prices arent between 13 and 15. Hence II is not true.
Hence A.
Please lemme know if i have gone wrong anywhere.
Last month 15 homes were sold in town X. The average sale price of teh homes was $ 150,000 and the median sales price was $130,000. Which of the following must be true?
I. At least one of the homes was sold for more than $165,000
II._____________________________ more than $130,000 and less than $150,000.
III. _____________________________ less than $130,000.
A.I only
B.II only
C. III only
D. I and II
E. I and III
To make it simple.....
since the median of the 15 values is 13,000 and mean of 15 values is 15,000....
x be the individual value of 1st 7 values y be the individual value of last 7 values > 13000
for reducing the complexity i hv taken the first 7 values commonly as x and same with last values as y
==> (7x + 13000 + 7y) = 15*15000
7x+7y = 2,12,000
x+y = 30,300 (approx)
To calculate min value of Y ....take the Max value of x is 13000...
==> y = 17,300 ( Min value of last 7 values)
Hence we get I as the minimum answer.......
By using the same equations written above....since we havent used any value that is either
Regards
Madhav
Correct me if i was wrong.......
alchemist-mba SaysYes.. sounds right..
The answer to this whether r is even prime or not is B. We are asked not to prove whether "r" is even or not rather we have to find out "r" is actually prime or not. Fact Statement 2 says 3
Do quote on this.
Inputs are appreciated
Cheers
The answer to this whether r is even prime or not is B. We are asked not to prove whether "r" is even or not rather we have to find out "r" is actually prime or not. Fact Statement 2 says 3
Do quote on this.
Inputs are appreciated
Cheers
Common Bro...The statement in B just tells u that 3
We need to prove whether r is an even number....
we have even numbers from 4 to 24 that can be r......
So B cant be the answer.............
From A we just know that r is a prime number....
If you consider A ..then r can be 2,3 or any prime number....
A doesnt help because r can be 2 or any other prime number....So we cant judge r by only A ....
If you consider A & B..
we know that r is a even prime that is in between 3 & 26....Hence we know that answer for " Is the positive integer r an even number? " as NO...
I typed it fast ....I hope it helps..
regards
Madhav