Dude, if you want to prove option 'a' as false, it should be 1-1-1-8. As per you, it satisfies the 1st condition, that is it makes it true. Still, the answer is c. Just the reasoning for the first option u gave seems incorrect.
bro, it is given ''2 boys receive more than 1 choco'' i am just proving it wrong by allotting only 1 choco( not more than) to 2 boys...and rest to others..
what you are proving wrong is '' only 2 boys receive 1 choco''
hope i am clear :)
one small confusion.. one of boys means we can take more than one boy or exactly one boy??.. thanks for answer
bro, it is given ''2 boys receive more than 1 choco'' i am just proving it wrong by allotting only 1 choco( not more than) to 2 boys...and rest to others..
what you are proving wrong is '' only 2 boys receive 1 choco''
hope i am clear :)
exactly 1 boy.
So is this case falsify option C? 2243 or 2144 etc..your suggestion will be helpful..thanks..
a doubt... the power of 45 that will exactly divide 123! now i know a procedure to solve this.... 45 can be expressed as 3^2*5.... so i checked (123/5)+(123/5^2)...the answer comes out to be 28..... but the answer given is 31.... please explain...where am i going wrong....
If we consider the given condition then from first three conditions satisfies is 4+3+3+1...only the last option dosnt not satisfy the distribution...so i think its a,b,c...
to find the answer,the other method is: 123/5 =24/5=4..so the ans is 28 and not 31..must be a printing mistake..
No, answer will not be 28. Here, 45 = 3^2 * 5. So, 3^2 occurs for less times than 5. So, here deciding factor will be 3, not 5. Hence, we need to divide successively by 3. Hope it helps.
Originally Posted by meba View Post to find the answer,the other method is: 123/5 =24/5=4..so the ans is 28 and not 31..must be a printing mistake.. No, answer will not be 28. Here, 45 = 3^2 * 5. So, 3^2 occurs for less times than 5. So, here deciding factor will be 3, not 5. Hence, we need to divide successively by 3. Hope it helps.
the power of 3 in 123! is 59 so it will be decided by power of 5
a doubt... the power of 45 that will exactly divide 123! now i know a procedure to solve this.... 45 can be expressed as 3^2*5.... so i checked (123/5)+(123/5^2)...the answer comes out to be 28..... but the answer given is 31.... please explain...where am i going wrong....
Ans is 28(a) in the new edition the ans is 28
ans is 28 only 5 occurs 28 times , 3 occurs 59 times so 3^2 occurs 29 times, so 5 will come less number of times . therefore , ans is 28 only
pugs who r saying 9 will come less number of times are incorrect coz the rule 123/3+123/(3^2)+...is valid only when denominator is a prime number so we cannot calculate is dividing by 9 and then 9^2
plz provide me the solution of the following question:- If p=1! + 2x2! + 3x3! + ......+ 10x10! , Then what is the REMAINDER when (p+2) is divided by 11 ?
plz provide me the solution of the following question:- If p=1! + 2x2! + 3x3! + ......+ 10x10! , Then what is the REMAINDER when (p+2) is divided by 11 ?
plz provide me the solution of the following question:- If p=1! + 2x2! + 3x3! + ......+ 10x10! , Then what is the REMAINDER when (p+2) is divided by 11 ?
plz provide me the solution of the following question:- If p=1! + 2x2! + 3x3! + ......+ 10x10! , Then what is the REMAINDER when (p+2) is divided by 11 ? options: a.1 b.2 c.3 d.4
p= 1! + 2x2! + 3x3! + ......+ 10x10!= 11! - 1
so, (p+2) = 11! + 1 therefore remainder when (p+2) is divided by 11 will be 1
