Hi Puys, plz help me out with the following questions:
1. When 10^x is divided by 13, remainder is 1. If x is a natural number less than 100, how many values x can take?
a)8 b)16 c)1 d)12
2. x^6/9 remainder is 1 where 100a)33 b)12 c)67 d)68
3. AB=9C+1, where A,B,C are natural numbers and 100a)101 b)50 c)11 d)none of these
4. The equation 4x-Ay=B has a number of intergral solutions. If HCF(A,4)=1 and the number of solutions (x,y) for 0
Please reply along with the approach.
Hi Puys, plz help me out with the following questions:
1. When 10^x is divided by 13, remainder is 1. If x is a natural number less than 100, how many values x can take?
a)8 b)16 c)1 d)12
2. x^6/9 remainder is 1 where 100a)33 b)12 c)67 d)68
3. AB=9C+1, where A,B,C are natural numbers and 100a)101 b)50 c)11 d)none of these
4. The equation 4x-Ay=B has a number of intergral solutions. If HCF(A,4)=1 and the number of solutions (x,y) for 0a)3 b)2 c)1 d)none of these
Please reply along with the approach.
im getting the following answers, not very sure abt them, though:
1) option (b)
2) option (d)
3) option (e) {not very sure as i got the answer as 12... so 11 might be the answer if incase i would have missed out a case}
Hi Puys...
Can you plzz help me out in this ques
find the reminder when 21^875 is divided by 17..............
13.
Plz tell if the ans. is rgt.!!!
13.
Plz tell if the ans. is rgt.!!!
yup...its ryt
Hi Can anybody tell me how to solve this question
a young girl counted in the following way on the fingers of her left hand. She started calling the thumb 1,the index finger2,middle finger3,ring finger 4,little finger 5,then reversed direction,calling the ring finger 6,middle finger 7, index finger 8,thumb 9,then back to the index finger for 10,middle finger for11,and so on.She counted up to 1994. She ended on her
(a)thumb (b)index finger (c) middle finger (d) ring finger
Hi Can anybody tell me how to solve this question
a young girl counted in the following way on the fingers of her left hand. She started calling the thumb 1,the index finger2,middle finger3,ring finger 4,little finger 5,then reversed direction,calling the ring finger 6,middle finger 7, index finger 8,thumb 9,then back to the index finger for 10,middle finger for11,and so on.She counted up to 1994. She ended on her
(a)thumb (b)index finger (c) middle finger (d) ring finger
every count in reaching the thumb is in the form (8k+1)
now 1994= 249*8 + 2 =(8*249+1) + 1
so she will end on index finger
every count in reaching the thumb is in the form (8k+1)
now 1994= 249*8 + 2 =(8*249+1) + 1
so she will end on index finger
good one!!!! thanks
1..e.More than 4..
Nos will be=3*5*7*11*13=15015
3*17*7*11*13=51051
3*19*7*11*13=57057
3*23*7*11*13=79079
3*29*7*11*13=87087
3*31*7*11*13=93093
@ rituraj ... a shud lie btwn 4 and 8 thus 3003*17/19/23 will be only counted
@ priyanka it s arun sharma cat ques , chek d solution its dere printed over leaflet 😛
in the nineteenth century a person was X years old in the year X^2. how old was he in 1884?
a)43
b)58
c)68
d)78
please explain the solution in details
in the nineteenth century a person was X years old in the year X^2. how old was he in 1884?
a)43
b)58
c)68
d)78
please explain the solution in details
whats the answer???? 43???
girish142 Sayswhats the answer???? 43???
i dont have the answer key..sorry 😞
in the nineteenth century a person was X years old in the year X^2. how old was he in 1884?
a)43
b)58
c)68
d)78
please explain the solution in details
since the age of the person must be in 18XX and should be a perfect square, the only number has square in 1800 is 43. i.e 43^2=1849.
so the age of the person is 43 and the year is 1849.
In 1884 the person will be 35(1884-1849)+43=78
optinon d
:
girish142 Sayswhats the answer???? 43???
sorry...
the answer is 78 according to me..
the nearest square among the given options to 1884 is that of 43 i.e 1849
so in the year 1849, he was 43 yrs old.
so after 35 years, i.e. in 1884, his age will be 43+35=78
correct me if im wrng
:
in the nineteenth century a person was X years old in the year X^2. how old was he in 1884?
a)43
b)58
c)68
d)78
please explain the solution in details
he was 43 years old in 43^2=1849
so in 1884 he will be 78 years old:cheers:
Hi Can anybody tell me how to solve this question
a young girl counted in the following way on the fingers of her left hand. She started calling the thumb 1,the index finger2,middle finger3,ring finger 4,little finger 5,then reversed direction,calling the ring finger 6,middle finger 7, index finger 8,thumb 9,then back to the index finger for 10,middle finger for11,and so on.She counted up to 1994. She ended on her
(a)thumb (b)index finger (c) middle finger (d) ring finger
index finger:cheers:
in the nineteenth century a person was X years old in the year X^2. how old was he in 1884?
a)43
b)58
c)68
d)78
please explain the solution in details
well suppose the man lives for 100 years .... this means that his age on a particular day wud be near around the year 1884 ..... when u square 43 u get
1849.This is the only number that when squared produces a year nearer to 1884 ... therefore on 1849 i.e. when he was 43 years old , the condition was satisfied.Now just subtract the term 1884 from 1849 which gives us 35... Add this 35 to his previous age i.e. 43 ... hence we get 43+35=78
x is any even natural number such that y=x^2-2x. find the greatest natural number which always divides y^2-8y.
a) 192
b) 96
c) 384
d) 144
x is any even natural number such that y=x^2-2x. find the greatest natural number which always divides y^2-8y.
a) 192
b) 96
c) 384
d) 144
is d ans 384??
hii... plz tel me how to solve this...
what is the remainder when 128^(1000) is divided by 153? 