Should be 1 ... Please confirm right answer...
i have 7^7sweets and i want to distribute them equally among 2^4students.after each of the student got maximum integral sweets how many sweets are left with me ?
a)8
b)5
C)1
d)none
i have 7^7sweets and i want to distribute them equally among 2^4students.after each of the student got maximum integral sweets how many sweets are left with me ?
a)8
b)5
C)1
d)none
none?? i think 7 should be the remainder
i have 7^7sweets and i want to distribute them equally among 2^4students.after each of the student got maximum integral sweets how many sweets are left with me ?
a)8
b)5
C)1
d)none
it should be 7...??
i have 7^7sweets and i want to distribute them equally among 2^4students.after each of the student got maximum integral sweets how many sweets are left with me ?
a)8
b)5
C)1
d)none
the answer will be the remainder of 7^7/2^4 = 7
so option d
it should be none as 7^7/16 :7 and 16 are coprime so 7^6/16 will give remainder as 1 so we r left with 7/16 which wull give remainder 7 ..
when i distribute a packet of chocolates to 7 students .i am left with 4 chocolates .when i distribute the same packet of chocolates to 11 students .i am left with 6 chocolate .how many chocolates will be left with me if i distribute the same packet of chocolate among 13 student .(a packet of chocolates contains total number of chocolates N,1000
b)0
c)6
d)7
when i distribute a packet of chocolates to 7 students .i am left with 4 chocolates .when i distribute the same packet of chocolates to 11 students .i am left with 6 chocolate .how many chocolates will be left with me if i distribute the same packet of chocolate among 13 student .(a packet of chocolates contains total number of chocolates N,1000a)2
b)0
c)6
d)7
It is Option B
when i distribute a packet of chocolates to 7 students .i am left with 4 chocolates .when i distribute the same packet of chocolates to 11 students .i am left with 6 chocolate .how many chocolates will be left with me if i distribute the same packet of chocolate among 13 student .(a packet of chocolates contains total number of chocolates N,1000a)2
b)0
c)6
d)7
the equations are
7x+4 = 11y+6
so we get the least number of chocolates to be 39
39 is divisible by 13
so total choclates are 77z+39
here z = 13
so 1040 which is perfectly divisible by 13.
so 0
1. Find the remainder when 25^102 is divided by 17?
2. Find the remainder when 83^261 is divided by 17?
3. Find the remainder when 54^214 is divided by 17?
Can anyone explain me the concept to solve such questions....
1. Find the remainder when 25^102 is divided by 17?
2. Find the remainder when 83^261 is divided by 17?
3. Find the remainder when 54^214 is divided by 17?
Can anyone explain me the concept to solve such questions....
http://www.pagalguy.com/discussions/number-system-questions-discussions-25043728
http://www.pagalguy.com/discussions/official-quant-thread-for-cat-2011-part-2-25067094
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go by this..
1. Find the remainder when 25^102 is divided by 17?
2. Find the remainder when 83^261 is divided by 17?
3. Find the remainder when 54^214 is divided by 17?
Can anyone explain me the concept to solve such questions....
1. 4
2.2
3.15
logic
: since 17 is a prime number so A^16/17 =1
:)
where from 77z came from...
Hey Puys i am putting up 3 questions!!
How many ways can 225 be written as difference of two perfect squares?
A-1 B-3 C-4 D-5
find highest power of 12 in 142! +143!
options :-67,68,69,70
find remainder when 25! is divided by 5^7
Options:- 6x5^5, 50000, 25x5^4, 1
Hey Puys i am putting up 3 questions!!
How many ways can 225 be written as difference of two perfect squares?
A-1 B-3 C-4 D-5
find highest power of 12 in 142! +143!
options :-67,68,69,70
find remainder when 25! is divided by 5^7
Options:- 6x5^5, 50000, 25x5^4, 1
2)142!*143+142!
142!(144)
in 142! the power is 68..
in 144 its 2
ans =70
whats the oa?
1)1 way...not sure
hey puys i am putting up 3 questions!!
how many ways can 225 be written as difference of two perfect squares?
A-1 b-3 c-4 d-5
find highest power of 12 in 142! +143!
Options :-67,68,69,70
find remainder when 25! Is divided by 5^7
options:- 6x5^5, 50000, 25x5^4, 1
1.3 113^2-112^2,,,,,25^2-20^2......15^2-0^2
2.70
3.i think it should be 4
For first i think answer is 2 .i can figure out 2nd number also 113^2-112^2=225
SRY FR THIRD CONSECUTIVE REPLY BUT ANSWER IS 3 15^2-0^2=225 ,,:p
rohit406 SaysSRY FR THIRD CONSECUTIVE REPLY BUT ANSWER IS 3 15^2-0^2=225 ,,:p
Answer is 4 .....even i dont know 4th one!!! can u explain your approach for this question? bcz i found 3 but it took longer time than u.........
1.3 113^2-112^2,,,,,25^2-20^2......15^2-0^2
2.70
3.i think it should be 4
3rd question's anwer is wrong.....!!! answer is 25x5^4