1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4,…………………………………..
Then what is the 2320 position of the number in the sequence?
b) 2 b) 1c) 3 d) 4
pls explain..
@thunderstorm1 It will be 7.assume he travels at constant speed so diff is constant.now last no must be of 10x form.= 6 fits as 61-16 = 106-61.
@nsrk said:1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4,…………………………………..Then what is the 2320 position of the number in the sequence?b) 2 b) 1c) 3 d) 4pls explain..
4??
1 2 2 3 3 3 4 4 4 4 = 10 terms
next cycle all are doubling. so 20 terms
next 40 terms
from this we can find out that it is Geometric series with 10 as first term and 2 as the ratio
so 2320 = 10*2^(n-1)
232 = 2^(n-1)
now 2^8 = 256 > 232
so it has to be 2^7
for that n =8
now put n = 8 in the sum of goemetric series formula you will get 2550
but we want 2320th position.(2550-2320 = 230)
if you observe
when n = 1 4 appears - 4 times
n = 2 4 appears 8 times
n = 3 16
i.e 2^(n+1) times
so when n = 7 it would appear 256 times
which means last 256 terms of 2550 terms are 4
and we want last 230th term
hence it has to be 4
please confirm
@chandrakant.k said:4??1 2 2 3 3 3 4 4 4 4 = 10 termsnext cycle all are doubling. so 20 termsnext 40 termsfrom this we can find out that it is Geometric series with 10 as first term and 2 as the ratioso 2320 = 10*2^(n-1)232 = 2^(n-1)now 2^8 = 256 > 232so it has to be 2^7for that n =8now put n = 8 in the sum of goemetric series formula you will get 2550but we want 2320th position.(2550-2320 = 230)if you observewhen n = 1 4 appears - 4 timesn = 2 4 appears 8 timesn = 3 16i.e 2^(n+1) timesso when n = 7 it would appear 256 timeswhich means last 256 terms of 2550 terms are 4and we want last 230th termhence it has to be 4please confirm
yeah 4 is d ans....
Q.1 what is the highest power of 3 available in expression 58! -38!
answer is 17..
can sum1 explain??
Q.2 what is the remainder when 2(8!)-21(6!) divides 14(7!) + 14(13!) ??
A number is divided by 7,remainder is x. then divided by 19, leaves remainder
2x & when divided by 39, gives remainder 3x. if x=4,then find least possible such number?
in details plss...
@leo12
1). you can write the expression as
38!(58.57.56....39 - 1)
58.57.56.55...39 is a multiple of 3
hence (58.57.56....39 - 1) will not be a multiple of 3 so just worry about 38!
that will give you 17 as the highest power of 3
2). is the answer 1??
@Napster29 said:A number is divided by 7,remainder is x. then divided by 19, leaves remainder2x & when divided by 39, gives remainder 3x. if x=4,then find least possible such number?in details plss...
N= 7a+4=19b+8=39c+12
7a-19b=4
values that satisfy 6,2
so b=2+7k
also 7b-39c=8
values 31,15
so b=31+39w
2+7k=31+39w
7k-39w=29
k,w =32,5
so b=31+39*5=226
N=19b+8=4302
@themaster
N= 7a+4=19b+8=39c+12
7a-19b=4
values that satisfy 6,2
so b=2+7k
also 7b-39c=8
values 31,15
so b=31+39w
2+7k=31+39w
7k-39w=29
k,w =32,5
so b=31+39*5=226
N=19b+8=4302
courtsey
K is a three digit nymber such that the ratio of the number to the sum of its digits is least.what is the difference between the hundreds and tens digit of K ?
1)9
2)8
3)7
4) none of these
plz explain also!!
if u form a subset of integers chosen from between 1 to 3000, such that no two integers add up to a multiple of nine,what can be maximum no. of elements in the subset.(include both 1 and 3000)
1)1668
2)1332
3)1333
4)1336
explain!!
for every equation in the form of
ax+by=c
the integer value of x lie at a common difference of b
and
the integer value of y lie at a common difference of a
@leo12 said:if u form a subset of integers chosen from between 1 to 3000, such that no two integers add up to a multiple of nine,what can be maximum no. of elements in the subset.(include both 1 and 3000)1)16682)13323)13334)1336explain!!
1336
@leo12 the numbers which we can include will be numbers having remainders as 1,2,3,4
we cannot include 5 as the sum of numbers with 4 and 5 as remainder will be divisible by 9
3000/9=333 and also 3 as remainder thus a total of 1335 numbers
also we can include 1 number divisible by 9 so 1336
@leo12 said:K is a three digit nymber such that the ratio of the number to the sum of its digits is least.what is the difference between the hundreds and tens digit of K ?1)92)83)74) none of theseplz explain also!!
8?