what is the remainder of 7^7^7/13 ???
orangejawan Sayswhat is the remainder of 7^7^7/13 ???
e(13)= 12
so 7^7/12 gives remainder 7
so given can b written as 7^(12k+7)
7^(12k+7)/13= 7^7/13
is the remainder 6?
Hi, Vivek , i did't understood the why are we dividing it with 12 ( 7^7/12) ?? Please explain the problem in detail
Yes answer is 6
Hi, Vivek , i did't understood the why are we dividing it with 12 ( 7^7/12) ?? Please explain the problem in detail
Yes answer is 6
euler of 13 is =12
( u know euler rule? )
then it simplifies and we can proceed .
if u want euler rule , i will upload it
Hi, Vivek , i did't understood the why are we dividing it with 12 ( 7^7/12) ?? Please explain the problem in detail
Yes answer is 6
euler number for 13 is 12
by euler theorem a^e mod x is 1
where e is euler number for x
hence he is dividing 7^7 by 12
Hope you got the point
yes i have read the euler rule ... 7^12/13 =1 , but the next step of dividing by 12 , please explain that
Hi, Vivek , i did't understood the why are we dividing it with 12 ( 7^7/12) ?? Please explain the problem in detail
Yes answer is 6
Lal Jawan..or orange one...hehe...well this theorem is called the EULER theorem...well in simple words let me explain....
7^1 mod 13 = 7
7^2 mod 13 = 10
7^3 mod 13 = (7^2 mod 13) *(7^1 mod 13) = 5
7^4 mod 13 = (7^3 mod 13) *(7^1 mod 13) = 9
7^5 mod 13 = (7^4 mod 13) *(7^1 mod 13) = 11
7^6 mod 13 = (7^5 mod 13) *(7^1 mod 13) = 12 or -1...
so 7^12 mod 13 = (7^6 mod 13) *(7^6 mod 13) = 1...
so after every 12 cycles remainder would be 1.....
now power is 7^7...so we have to take its mod by 12...
which is 7^7 mod 12 = 7....so we'll search for 12k+7...which gives us remainder 6.....
orangejawan Saysyes i have read the euler rule ... 7^12/13 =1 , but the next step of dividing by 12 , please explain that
I'll take a try @ dis..
u no..euler of 13=12..
now remaindr(7^12/13)=1..
so
7^7(i.e. the power of denominator 7 ) has to be expressed as a factor of 12.
so next step is to find rem(7^7/12)
we get it as 7
thus 7^7=12k+7
thus given expression=7^(12k+7)/13
7^12k/13=1
thus we nid to find only remaindr(7^7/13)
rem=6 (ans)
answer is 36..i think....
Layer 1 = 1 ball
Layer 2 = 1+2 balls
Layer 3 = 1+2+3 balls
Layer 4 = 1+2+3+4...so on...
Layer n = 1+2+3+4+...+(n-1)+n.
so n*1 + (n-1)*2 + (n-2)*2 + .... + (n-1)*2 + n = 8436....
so n = 36..
tn term will be n(n+1)/2
sum of tn terms will be
n(n+1)(n+2)/6 = 8436
solving n=36
explain the bold section, how did you puys arrived this??
Sahana Kavitha Saysexplain the bold section, how did you puys arrived this??
s=1+3+6+.......................................tn---------------1
s= 1+3+6+.......................................tn---------------2
1-2=>
tn=1+2+3+.............................n
tn=n(n+1)/2
and sigma tn will b n(n+1)(n+2)/6
hope i m clear!
Every ceiling, when reached, becomes a floor
What is the reamainder of 38! / 41 ?
What is the general method of solving the question like : find the last three digits of 3^1994 ???
orangejawan SaysWhat is the reamainder of 38! / 41 ?
by wilsons theorm i m gettin answer as 2
is it correct?
Every ceiling, when reached, becomes a floor
find the remainder when (38^16!)^1777 is divided by 17
a. 1
b. 16
c. 8
d. 13
what do you mean by " ^ "
sanjeev-garg Sayswhat do you mean by " ^ "
find the remainder when (38^16!)^1777 is divided by 17
"^" means to the power of.
16!^1777 can be expressed as 16k
17 and 38 are comprime
So 38^16kmod 17 =1
by wilsons theorm i m gettin answer as 2
is it correct?
Every ceiling, when reached, becomes a floor
Not sure about the answer , pleaase explain the method too ???
Problem is easy but what is the answer for this ???
if A=33*32*31*30*29*28
&
if Remainder [ A/(12k)] = 0......then find the minimum value of k
will an body tell me what does this mean
^
thanks yaar raja ram varun