Guys I need the approach for a particular prblm.... I dont remember the exact data ....bt it goes smthin like ths there are 5 students and they have different integral weights they are weighted in pairs of 2...so we have 10 different combined values...say C1, C2, C3, C4, C5, C6, C7, C8, C9, C10 how to find out the lightest of the five??
the combined value are arranged in increasing order maybe like 35,37,.......etc(10 values)
i have seen such prob .. but it would be better if u give the question so that it is easy to understand with a prob
The game of "chuck a luck" is played. its rules are as follows: If you pick a number from 1 to 6, the operator will throw three dices. the operator will pay u 3 rs if the number you hve chosen comes on three dices. the operator will pay u 2 rs if the number you hve chosen comes on two dices. the operator will pay u 1 rs if the number you hve chosen comes on one dice. Only if the number u picked does not come on any of the dice, you have to pay operator 1 rs. What is the probablity than you win money in this game Choices 0.52 0.753 0.42 0.39
i have seen such prob .. but it would be better if u give the question so that it is easy to understand with a prob
ok dude here is the question.....
A rural child specialist has to determine the weight of five children of different ages. He knows from his past experience that each of the children would weigh less than 30 Kg and each of them would have different weights. Unfortunately, the scale available in the village can measure weight only over 30 Kg. The doctor decides to weigh the children in pairs. However his new assistant weighed the children without noting down the names. The weights were: 35, 36, 37, 39, 40, 41, 42, 45, 46 and 47 Kg. The weight of the lightest child is: A. 15 Kg. B. 16 Kg. C. 17 Kg. D. 18 Kg. E. 20 Kg.
A rural child specialist has to determine the weight of five children of different ages. He knows from his past experience that each of the children would weigh less than 30 Kg and each of them would have different weights. Unfortunately, the scale available in the village can measure weight only over 30 Kg. The doctor decides to weigh the children in pairs. However his new assistant weighed the children without noting down the names. The weights were: 35, 36, 37, 39, 40, 41, 42, 45, 46 and 47 Kg. The weight of the lightest child is: A. 15 Kg. B. 16 Kg. C. 17 Kg. D. 18 Kg. E. 20 Kg.
Guys I need the approach for a particular prblm.... I dont remember the exact data ....bt it goes smthin like ths there are 5 students and they have different integral weights they are weighted in pairs of 2...so we have 10 different combined values...say C1, C2, C3, C4, C5, C6, C7, C8, C9, C10 how to find out the lightest of the five??
the combined value are arranged in increasing order maybe like 35,37,.......etc(10 values)
A rural child specialist has to determine the weight of five children of different ages. He knows from his past experience that each of the children would weigh less than 30 Kg and each of them would have different weights. Unfortunately, the scale available in the village can measure weight only over 30 Kg. The doctor decides to weigh the children in pairs. However his new assistant weighed the children without noting down the names. The weights were: 35, 36, 37, 39, 40, 41, 42, 45, 46 and 47 Kg. The weight of the lightest child is: A. 15 Kg. B. 16 Kg. C. 17 Kg. D. 18 Kg. E. 20 Kg.
add all possible pairs
that results in
4*(a+b+c+d+e) = 408 => a+b+c+d+e=102
always lowest sum given is sum of two lightest item and highest sum is sum of two heaviest item
here is anotherone..: The game of "chuck a luck" is played. its rules are as follows: If you pick a number from 1 to 6, the operator will throw three dices. the operator will pay u 3 rs if the number you hve chosen comes on three dices. the operator will pay u 2 rs if the number you hve chosen comes on two dices. the operator will pay u 1 rs if the number you hve chosen comes on one dice. Only if the number u picked does not come on any of the dice, you have to pay operator 1 rs. What is the probablity:w00t: than you win money in this game Choices 0.52 0.753 0.42 0.39
The game of "chuck a luck" is played. its rules are as follows: If you pick a number from 1 to 6, the operator will throw three dices. the operator will pay u 3 rs if the number you hve chosen comes on three dices. the operator will pay u 2 rs if the number you hve chosen comes on two dices. the operator will pay u 1 rs if the number you hve chosen comes on one dice. Only if the number u picked does not come on any of the dice, you have to pay operator 1 rs. What is the probablity than you win money in this game Choices 0.52 0.753 0.42 0.39
dekh yaar seedhi si baat hai.. probability that he will NOT get the no. he selected on the 1st dice is 5/6.. not on the 2nd dice=5/6 and on the 3rd dice= 5/6
probability he will not get on any of the dice = (5/6)*(5/6)*(5/6) => 125/216 => probability he will win = 1-125/216 =91/216 =0.42..
Hello Frnds, Try solving these questions??? 1. 3^1010 % 1001.
3^1010 mod 13*7*11 3^1010 mod 13 = 3^9 mod 13 = 1 3^1010 mod 11 = 3^9 mod 11 = 4 3^1010 mod 7 = 3^9 mod 7 = 6 13a+1 = 11b+4 = 7c+6 a = (11b +3)/13 b=8, a = 7 so 143k+92 = 7c+6 c = (143k + 86)/7 c = 20k + 12 + (3k + 2)/7 k = 4 c = 94 remainder = 664
here is anotherone..
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