Number System - Questions & Discussions

viveknitw Says
pls explain


see 5N is cuming as 5pd+260 but here 4 is cuming as remaindr n we knw 5pd is divisible by d and 260 will giv remaindr as 4 only for the nos. whch are factors of 256......but it should be grtr thn 52.....factors can be 64,128,256......256=2^8.....factors grtr thn 52 will be 2^6,2^7,2^8...
hope it will make u undrstnd
5N = bd + 4..(1)
N = ad + 52..(2)
Multiply 2 by 5
5N = 5ad + 260
Now 260 mod Any Number Must Leave 4....
So Largest Number = 256...
Rest Numbers Are Factors of 256...
So total Factors = 9
But 1,2,4 will not suffice...
Also Value less than 52 will not suffice....
So Values of d = 3



divishth 8,16,32 se validate kariyo

Thanks sumit...all clear 😃

ajit@mumbai Says
Thanks sumit...all clear :-)

oh welcum hai jee.....but brother no need to thank......

PUYS explanation Please......:-P

Let a, c 2, 4, 6, 8, 10, 12 and b 22, 24, 26, where a, b and c are distinct. Find the number of equations of the form ax2 + bx + c = 0, that can be formed such that the equation has real roots.

a)15
b)18
c)45
d)90
e)36



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PUYS explanation Please......:-P

Let a, c 2, 4, 6, 8, 10, 12 and b 22, 24, 26, where a, b and c are distinct. Find the number of equations of the form ax2 + bx + c = 0, that can be formed such that the equation has real roots.

a)15
b)18
c)45
d)90
e)36


Answer is 90
PUYS explanation

Let a, c 2, 4, 6, 8, 10, 12 and b 22, 24, 26, where a, b and c are distinct. Find the number of equations of the form ax2 + bx + c = 0, that can be formed such that the equation has real roots.

a)15
b)18
c)45
d)90
e)36



For the roots to be real
D>=0
b^2-4ac>=0
now we can see that the maximum values of a and b possible are 10,12
and the minimum value of b = 22
22 ^2 > 4* 12 *10

11^2 > 10*12

Hence we can take all possible values from the given without any eliminations.

Ways of selecting for A n B are 6C2 * 2
Ways of selecting B are 3
hence Answer should be 6C2 * 2 *3
Hence the answer is 90.

No sumit the answer to 2nd problem is 84

ans 1.: conventional method: =x^99+x^88+x^77+x^66+x^55+x^44+x^33+x^22+x^11+1
=(x^9)^11+(x^8 )^11+(x^7)^11+(x^6)^11+(x^5)^11+(x^4)^11+(x^3)^11+(x^2)^11+(x)^11+(1)^11

as we know: a^n + b^n +.........+z^n is divisible by a+b+.....z if n is odd

therfore, remainder is zero.

unconventional: put x=1 n njoy ur life
as 10/10 rem=0

Ans2. r u asking 4 min sum of all the sides:(assuming u r asking 4 same)

231= 3*7*11
3+7+11=21 option (a)

Q2) the volume of cuboid is 231cubic centimeter. All dimensions r integers.Find minimum sum of all the cuboid?
a)21 b)63 c)84 d)126

Sumit the correct answer is 84. bt i dnt knw how?

The number of positive integral solutions of the equation xyz=30 is
a.24 b.25 c.26 d.27

Can you explain to approach

The number of positive integral solutions of the equation xyz=30 is
a.24 b.25 c.26 d.27

Can you explain to approach

30 = 2*3*5
x=2,y=3,z=5-----------6 nos.
x=1,y=6,z=5 --6 nos.
x=1,y=1,z=30 --3 nos.
x=1,y=15, z=2---6 nos.
x=10,y=3, z=1---6 nos.
total = 27

There are 4 balls to be put in five boxes where each box can accommodate any number of balls. In how many ways can one do this if
1.Balls are similar and box are different.
2.. ball are diff and boxes are similar
3.. both ball and box are similar
4.both ball and boxes are differ

PUYS explanation Please......:-P

Let a, c 2, 4, 6, 8, 10, 12 and b 22, 24, 26, where a, b and c are distinct. Find the number of equations of the form ax2 + bx + c = 0, that can be formed such that the equation has real roots.

a)15
b)18
c)45
d)90
e)36

answer is 90..
as for real roots b^2>=4ac..WHICH BTW MEAN D=B^2-4AC>=0
so there r 30 cases each 4 evry value of b...
in al 90 values!!


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PUYS explanation Please......:-P

Let a, c 2, 4, 6, 8, 10, 12 and b 22, 24, 26, where a, b and c are distinct. Find the number of equations of the form ax2 + bx + c = 0, that can be formed such that the equation has real roots.

a)15
b)18
c)45
d)90
e)36

answer is 90..
as for real roots b^2>=4ac..
so there r 30 cases each 4 evry value of b...
in al 90 values!!


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Dear ankitrajpal,
For the roots to be real the Determinant of a quadratic equation has to be zero.
Determinant of a quad eqn ax^2 + bx + c = 0 is b^2 - 4ac
which should be greater than zero.
Just put the max values of a, b and minimum values of b and you can see that the problem is just a problem based on the selection of values from a given set of values.

We have 3 possible values for b sine we have to select from 22, 24 and 26 ..............(1)
Now since a and b cannot have the same value.
Hence we can select two number from the given 6 numbers in 6C2 ways. ...............(2)
Since a and b are different hence we can get 2 cases for each ...............(3)
Multiplying Eqns 1 , 2 and 3 we get the desired result.

I hope the solution is clear this time.:)
There are 4 balls to be put in five boxes where each box can accommodate any number of balls. In how many ways can one do this if
1.Balls are similar and box are different.
2.. ball are diff and boxes are similar
3.. both ball and box are similar
4.both ball and boxes are differ




box ----------- object -------------- what to do

distinct-------- distinct ------------- box ^ object

distinct -------- identical------------ whole number sol

identical--------- identical -----------jus count number of ways

identical ---------distinct------------ number of ways * arranging

hope this helps

:


Dear ankitrajpal,
For the roots to be real the Determinant of a quadratic equation has to be zero.
Determinant of a quad eqn ax^2 + bx + c = 0 is b^2 - 4ac
which should be greater than zero.
Just put the max values of a, b and minimum values of b and you can see that the problem is just a problem based on the selection of values from a given set of values.

We have 3 possible values for b sine we have to select from 22, 24 and 26 ..............(1)
Now since a and b cannot have the same value.
Hence we can select two number from the given 6 numbers in 6C2 ways. ...............(2)
Since a and b are different hence we can get 2 cases for each ...............(3)
Multiplying Eqns 1 , 2 and 3 we get the desired result.

I hope the solution is clear this time.:)


@freak!!!
for real roots determinant,D>=0..and not just equal 2 0..as d=0 gives real but equal roots nd v r lookin for real roots may or may not b equal!!!nd for dat d>=0..
chk it out..
Quadratic equation - Wikipedia, the free encyclopedia..
hope it helps

Q)Find the remainder when 39! is didided by 41?
Ans- 1. (Hint- Use Wilson Theorem)

q)How many 3 digit number has its sum of the digits equal to 17.
(Solution other than conventional way is needed)

q)How many 3 digit number has its sum of the digits equal to 17.
(Solution other than conventional way is needed)

coeficient of X^17 in (x+x^2+..x^9)(1+x+..x^9)^2
=x(1-x^9)(1-x^10)^2*(1-x)^-3
= (x-x^10)(1-2x^10)*(1-x)^-3
= x(1-x)^-3 - 2x^11(1-x)^-3 - x^10(1-x)^-3
= 16+3-1C2 - 2* 6+3-1C2 - 7+3-1C2
= 153 - 56 - 36 = 61...
wats the OA???
q)How many 3 digit number has its sum of the digits equal to 17.
(Solution other than conventional way is needed)



x + y + z = 17

no of positive integral solution : 16 C 2 = 16 * 15/2 = 120

but x,y,z
x = x + 10

x + y + z = 7

no of solution = 6 C 2 = 15

so we get 120 - (3*15) = 75