Number System - Questions & Discussions

catoholic2011 · June 20, 2010, 12:10pm

1. The least perfect square number which is divisible by 3,4,6,8,10 and 11 ??

2. Find the greatest number of 4 digits which when divided by 10,11,15 and 22 leaves 3,4,8 and 15 as remainder respectively

Plzz explain wid logic

thx

barclays_boss · June 20, 2010, 11:23pm

1. The least perfect square number which is divisible by 3,4,6,8,10 and 11 ??

2. Find the greatest number of 4 digits which when divided by 10,11,15 and 22 leaves 3,4,8 and 15 as remainder respectively

Plzz explain wid logic

thx

Answers :

2) 1313

Soln : k*( lcm of 10,11,15,22) - 7

barclays_boss · June 20, 2010, 11:41pm

1. The least perfect square number which is divisible by 3,4,6,8,10 and 11 ??

2. Find the greatest number of 4 digits which when divided by 10,11,15 and 22 leaves 3,4,8 and 15 as remainder respectively

Plzz explain wid logic

thx

Not sure about the answer : is it 435600 ?

Take the lcm of 3,4,6,8,11,11 = 1320 ..now we need to multiply some number to 1320 to make it a perfect square as well.

3= 3^1
4=2^2
6=3*2
8=2^3
10=2*5
11=11^1

so if we multiply (3*2*5*11 ) we get a perfect square

pls confirm the answer.

mr.kool · June 21, 2010, 2:06am

1. The least perfect square number which is divisible by 3,4,6,8,10 and 11 ??

2. Find the greatest number of 4 digits which when divided by 10,11,15 and 22 leaves 3,4,8 and 15 as remainder respectively

Plzz explain wid logic

thx

1. LCM (3,4,6,8,10, and 11) = 2^3 * 3 * 5 *11

make LCM as perfect square by multp it by 2 * 3 *5 *11

i.e 2^4 * 3 ^2 *5^2 *11^2

2. Larget 4 digit number = 9999
Lcm (10,11,15,22) = 2 * 11 * 5 * 3 = 330

remd(9999/330) = 99

and (10-3)=(11-4)=(15-

=(22-15)=7

Number = 9999 - 99 - 7 = 9893

prium01 · July 2, 2010, 5:11am

How to find the sum and number of factors divisible by 5 for 1000?
Can anyone please answer my question?

shikha_mehta · July 2, 2010, 5:29am

the sum is 2340 and factors divisible by 5 are 4

prium01 · July 2, 2010, 5:38am

SHIKHA mehta Says
the sum is 2340 and factors divisible by 5 are 4

I just wanted the method to derive the answers...

Please explain.

Thanks

eaglemenace · July 2, 2010, 5:48am

How to find the sum and number of factors divisible by 5 for 1000?
Can anyone please answer my question?

1000=2^3 x 5^3
normally to find the factors u would do 4x4=16 but here its numbers divisible by 5... So u shd make sure every factors have 5 in it...so u shd remove 5^0...
so number of factors would be 3 x 4 = 12...

and sum of factors= 2325

shikha_mehta · July 2, 2010, 5:50am

are the answes right?

prium01 · July 2, 2010, 5:58am

1000=2^3 x 5^3
normally to find the factors u would do 4x4=16 but here its numbers divisible by 5... So u shd make sure every factors have 5 in it...so u shd remove 5^0...
so number of factors would be 3 x 4 = 12...

and sum of factors= 2325

Sill not very clear....

Thanks again

mr.kool · July 2, 2010, 6:10am

How to find the sum and number of factors divisible by 5 for 1000?
Can anyone please answer my question?

2000 = 2^3 * 5^3

We have to find the factors which are dvisible by 5 i.e factors must be multiple of 5

2^3 have 4 factors i.e 1,2,4,8

For 1 * 5^3 we have 3 factors,
2 * 5^3 again 3 factors
4 ----3 factors
8 ----3 factors
hence Total factor = 3+3+3+3 =12

For Sum = (1+2+4+8 ) * (5+25+125) = 2325

disa_r89 · July 13, 2010, 3:45pm

if 2a.6 b.7 c.8 d.4e.none
please help me solve this

varun.garg.pec · July 13, 2010, 3:51pm

if 2a.6 b.7 c.8 d.4e.none
please help me solve this

Here we want max value of x+y which is = 4+3 = 7

and min. value of x-y which is = 2-3 =-1

So ratio is = 7/-1 = -7 Ans. e. none

Thanks!!

Varun

sumit99 · July 14, 2010, 1:19am

if 2a.6 b.7 c.8 d.4e.none
please help me solve this

but its ans is 4 acc. To arun sharma

tallzz · July 14, 2010, 10:29am

hi all, its tarun.

internet.fanboy · July 15, 2010, 12:23pm

Q: Which is greater a^b or b^a ?

Q: What is the largest number that can be formed using four 3's ?

Most probably these would have been discussed in some quant thread, but i couldn't find them in my 10 min search of the forum, hence asking the pro's for help

shashank3012 · July 15, 2010, 12:32pm

Q: Which is greater a^b or b^a ?

Q: What is the largest number that can be formed using four 3's ?

Most probably these would have been discussed in some quant thread, but i couldn't find them in my 10 min search of the forum, hence asking the pro's for help

1) depends, a^b can be greater than,equal to or lesser than b^a

a=2, b=4=> a^b=b^a
a=3, b=1=> a^b>b^a
a=5, b=2=> a^b

internet.fanboy · July 15, 2010, 1:08pm

1) depends, a^b can be greater than,equal to or lesser than b^a

a=2, b=4=> a^b=b^a
a=3, b=1=> a^b>b^a
a=5, b=2=> a^b

The question i had was which is greater 5^7 or 7^5, the calculations look humongous, is there a trick to it ?

For the 2nd Q, the answer is as you have written, whats the logic behind it ?

Kindly explain as and when you get time, Thanks 😃

internet.fanboy · July 15, 2010, 3:20pm

hello friends

Please solve this problem

Question : Given A = 265 and B = (264+263+262+...+20)

B is 264 larger than A
A and B are equal
B is larger than A by 1
A is larger than B by 1

and answer is ...?

B-A = (263+262+.....+20)

So none of the options given by you are correct

shashank3012 · July 15, 2010, 3:23pm

hello friends

Please solve this problem

Question : Given A = 265 and B = (264+263+262+...+20)

B is 264 larger than A
A and B are equal
B is larger than A by 1
A is larger than B by 1

and answer is ...?

I guess you meant A=2^65 and B=(2^64+2^63+...2^0)

Now, 2^0+2^1+...2^(n-1)=2^n-1

So, option 4

I hope I got the question right.