(9^8!)/90,,,,,,,,,WHAT IS THE REMAINDER?
- 81
- 1
- 9
- 89
0 voters
how 2 identify a prime number rather than 6n+1/5 form?
(1*1*1) + (2 *2*2) + (3*3*3) + (4*4*4) +. . 10 terms is divided by 1*1 + 2 *2 + 3 *3 + 4 *4 + . . .10 terms . Find the remainder.
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7920
N is a three-digit natural number divisible by 11 such that the sum of its unit and hundreds digits is greater than its tens digit. What is the number of possible values of N?
(a) 76 (b) 36 (c) 45 (d) 44
N is a three-digit natural number divisible by 11 such that the sum of its unit and hundreds digits is greater than its tens digit. What is the number of possible values of N?
(a) 76 (b) 36 (c) 45 (d) 44
ANS is 36.
Check if correct. Not a shortcut :-(
Finding pattern:
xyz
x+z-y=11k -> x+z=11k+y hence, x+z>y only
x+z>y
using AP : 80 nos div by 11.
then,
110
121
132
143
154
165
176
187
198
-209 (1)
220
231
242
...
-308
-319 (2)
330
341
...
-407
-418
-429 (3)
440
-506
-517
... (4)
so on..
-605 (5)
-704 (6)
-803 (7)
-902 (8)
8*9/2 = 36
The LCM of two numbers is 495 and their HCF is 5. if sum of the numbers is 100, then find these numbers.? please explain approach..😠
the reminder when 3^67! is divided by 80?
what is the greatest number that will divide 99, 123, and 183 leaving the same remainder in each case? also find the common remainder?.
what should be the approach to this type questions, please explain in detail.
there are 5 numbers. HCF of each possible pair is 4 and LCM of all the 5 numbers is 27720. what will be the product of all five numbers?
please explain approach...
Q1) A no. if divided by 13 and 7 leaves remainders as 4 and 3. when any such no. is divided by 182, how many distinct remainders are possible.? ans [ 2 ]
Q2) How many values can x take if LCM ( 15^ 4 , 5^12 , x)= 15^12 ??
options 169 or 13 or 1 or 24. [ans given = 13 ]
@scrabbler
Hello everyone, I have a question on Quant... Here it is..
X goes to market for every 64 days and Y goes to market for every 72 days.On which day both of them would meet ?
It would be grateful,if you could respond with the solution at the earliest.
23x27 = 621 (3x7=21 last two digit, 2x3(number next to 2)=6)
44x46 = 2024 (4x6=24 last two digit, 4x5(number next to 4) = 20)
how to show the formula of this shortcut using perfect square binomial? pls. show solutions, tnx:)
This is a cool site to practice questions with friends:
www.thath.in
How to prove this:
(a-b/1+ab) + (b-c/1+bc) + (c-a/1+ac) = (a-b/1+ab) x (b-c/1+bc) x (c-a/1+ac)
(a-b/1+ab) + (b-c/1+bc) + (c-a/1+ac) = (a-b/1+ab) x (b-c/1+bc) x (c-a/1+ac)
how to prove this (a-b/1+ab) + (b-c/1+bc) + (c-a/1+ac) = (a-b/1+ab) x (b-c/1+bc) x (c-a/1+ac)
1,6,7,13,20,......Sum upto 52 terms.
what least number must be added to 8961 to make it exactly divisible by 84?? explain solution with answer
Find the remainder when 12^(13^(14)) is divided by 145
- 132
- 2
- 12
- 133
0 voters
what is the remainder when 2582^801 - 2579^401 is divided by 3..
Pls provide the steps as well!!
Thanks in advance
Hey frnds, Some time I feel difficult to workout problems under number systems. Because of too many formulae, shortcuts. Please give me some tips to handle this topic easily. Thanks in advance.