Official Quant thread for CAT 2013

MBA CAT 2022
2001
@soumitrabengeri said:
A wire if bent into a square encloses an area of 484 cm^2. The wire is cut into 2 pieces; with the larger piece having a length 3/4th of the original wire's length. Now, if a circle and a square are formed with the bigger and smaller pieces resp, what should be the area enclosed by the 2 pieces?1) 4642) 576.253) 376.754) 424.25
Wire=4l
l2=484
larger=3l and smaller=l
circle=>radius=3l/2pi =>area=9l2/4pi
square=>l2/16
sum=l2(9/4pi+1/16)=484(63/88+1/16)=484*137/176=376
2002
@sujamait said:
5,8 = 13
@maddy2807 said:
138,5?
@krum hit and trial lagaya hai kya? agar koi method hai to plz post
2003
@soumitrabengeri said:
A wire if bent into a square encloses an area of 484 cm^2. The wire is cut into 2 pieces; with the larger piece having a length 3/4th of the original wire's length. Now, if a circle and a square are formed with the bigger and smaller pieces resp, what should be the area enclosed by the 2 pieces?1) 4642) 576.253) 376.754) 424.25
376.75?

2004
@soumitrabengeri said:
A wire if bent into a square encloses an area of 484 cm^2. The wire is cut into 2 pieces; with the larger piece having a length 3/4th of the original wire's length. Now, if a circle and a square are formed with the bigger and smaller pieces resp, what should be the area enclosed by the 2 pieces?1) 4642) 576.253) 376.754) 424.25
3)376.75

484 = 22^2
wire length = 88
(66,22)
2pi *r = 66
4a = 22

pi*r^2 = pi * (33/pi)^2 = 22/7 * 3 * 3 * 7 * 7 / 4 = 346.5
a^2 = 11/2 * 11/2 = 121/4 = 30.25

Total = 376.75
2005
@pankaj1988 said:
@krum hit and trial lagaya hai kya? agar koi method hai to plz post
i checked thru the last digit and the power. last digit is 1 and the power is 4.
2006
@pankaj1988 said:
@krum hit and trial lagaya hai kya? agar koi method hai to plz post
yaar 13 se hee start karoge..kyunki baaki options does not make any sense except none of these..
17 dekhoge toh minumum...8,9 hee dega..but yeh max exceed kar jayegi...so...13 se hee kar oge check.
2007
@pankaj1988 said:
@krum hit and trial lagaya hai kya? agar koi method hai to plz post
yaar 9^4 = 720*9=63XX matlab both numbers are
last digit is 1
last digit 2^4=6
last digit 3^4=1
last digit 4^4=6
last digit 5^4=5
last digit 6^4=6
last digit 7^4=1
last digit 8^4=6

ab 6+5 chahiye to ya to 5^4+6^4 hoga ya 5^4+8^4, iskeliye bhi pen nai chahiye
2008
Twp points A and B are selected on a straight line segment of length 10cm. What is the probability that length(AB)>4cm .
1)5/24
2)9/25
3)3/8
4)4/15
2009
@krum said:
Twp points A and B are selected on a straight line segment of length 10cm. What is the probability that length(AB)>4cm .1)5/242)9/253)3/84)4/15
option 2?
2010
@maddy2807 said:
option 2?
approach?
2011
@krum said:
approach?

if the distance is less than equal to 4= 4/10=2/5
so required distance= 1-2/5=3/5
req prob= 3/5*3/5= 9/25
2012

2 years ago, one-fifth of Amita's age was equal to 1/4th of the age of Sumita and the average of their ages was 27 years. If the age of Paramita is also considered, the average age of the 3 of them falls down to 24. What will be the average age of Sumita and Paramita 3 years from now?


1) 25
2) 26
3) 27
4) CBD
2013

so gaye kkya sab?

2014
@soumitrabengeri said:
2 years ago, one-fifth of Amita's age was equal to 1/4th of the age of Sumita and the average of their ages was 27 years. If the age of Paramita is also considered, the average age of the 3 of them falls down to 24. What will be the average age of Sumita and Paramita 3 years from now?1) 252) 263) 274) CBD
(a-2)/5=(s-2)/4
(a+s)=54+4

=>4a-8=5s-10
=>4a=290-5a-2
=>9a=288
=>a=32,s=26

p=72-54=18
current age = 20

(29+23)/2=26

2)26

edited
2015
@soumitrabengeri said:
2 years ago, one-fifth of Amita's age was equal to 1/4th of the age of Sumita and the average of their ages was 27 years. If the age of Paramita is also considered, the average age of the 3 of them falls down to 24. What will be the average age of Sumita and Paramita 3 years from now?1) 252) 263) 274) CBD
2 yrs ago: a+s=54 also 4a=5s
solving a=30,s=24
so for avg to be 24 paramita age should be p=3*24-54=18
5 yrs aftr=>s=29,p=23
avg=s+p /2=26
2016
@soumitrabengeri said:
2 years ago, one-fifth of Amita's age was equal to 1/4th of the age of Sumita and the average of their ages was 27 years. If the age of Paramita is also considered, the average age of the 3 of them falls down to 24. What will be the average age of Sumita and Paramita 3 years from now?1) 252) 263) 274) CBD
26?
2017
@soumitrabengeri said:
2 years ago, one-fifth of Amita's age was equal to 1/4th of the age of Sumita and the average of their ages was 27 years. If the age of Paramita is also considered, the average age of the 3 of them falls down to 24. What will be the average age of Sumita and Paramita 3 years from now?1) 252) 263) 274) CBD



1/5(A-2) = 1/4(S-2) => ?
A+S-4 = 54=> A+S=58

considerin avg age of 3 given 2 years ago...
A+S+P = 78
P = 20
aise hee ho jayega..


2018
@soumitrabengeri said:
2 years ago, one-fifth of Amita's age was equal to 1/4th of the age of Sumita and the average of their ages was 27 years. If the age of Paramita is also considered, the average age of the 3 of them falls down to 24. What will be the average age of Sumita and Paramita 3 years from now?1) 252) 263) 274) CBD
26?
2019
Data sufficiency

Q. The roots of the equation Ax^3 + Bx^2 + Cx + D = 0, where A > 0, are in AP. Find all possible roots of the equation Bx^2 + Cx + D = 0.
I. One of the roots of the equation Ax^3 + Bx^2 + Cx + D = 0 is 0.
II. C
2020

Historical Data of a retail store indicated that 40 percent of all the customers that entered the store make a purchase .Determine the probability that exactly two out of the next three make a purchase?