@mbajamesbond said:Find the least possible value of a+b,where a,b are +ve integers such that 11 divides a+13b and 13 divides a+11b.
yaar ye to 22x33 aa raha hain 
I have three kinds of boxes: large, standard and small. I place 11 large boxes on a table. Ileave some of these empty and in each of the others I place 8 standard boxes. Some of thestandard boxes are left empty and in each of the others I place 8 small boxes. All thesmall boxes are empty. Of all the boxes on the table, 102 are now empty. How manyboxes have I used all together?
A) 64 B) 102 C) 115 D) 118 E) one cannot say
A) 64 B) 102 C) 115 D) 118 E) one cannot say
@mbajamesbond said:Find the least possible value of a+b,where a,b are +ve integers such that 11 divides a+13b and 13 divides a+11b.
a + 13 b = 11p
a + 11b = 13q
2b = 11p - 13q
2a = 169 q - 121p
2(a+b) = 156q - 110p
min a+ b = 23 ?
@mbajamesbond said:There are 10 boys in a class. On Saturday an important match will be played in the city.The boys that will go to watch the game will go as one group. If John will go to watch,then Piet will certainly also go. Now the min no. os students has to be 2 with the exception of john and piet.So 1 group can be choosen bywhen 2=10C2 -1Similary when the 3rd friend joins inwhen 3=10C3 - 8C1And so on until the last studentwhen 4=10C4 - 8C2when 5=10C5 - 8C3How many different groups of at least two boys are therethat can go to see the match?when 9 = 10C9 - 8C7
: 10c2 -1 walla explain karna !!!
@mbajamesbond said:Find the least possible value of a+b,where a,b are +ve integers such that 11 divides a+13b and 13 divides a+11b.
Its a + b = 5, where a = -1, b = 6
@Brooklyn said:: 10c2 -1 walla explain karna !!!
-1 to restrict repeated groups, rest taking 2 out of 10
Q> If N be the number of consecutive zeros at the end of the decimal representation of the expression 1! × 2! × 3! × 4! ×............× 99! × 100!.
Find the remainder when N is divided by 1000?
Options: a) 123 b) 124 c) 125 d) None of these
@mbajamesbond said:-1 to restrict repeated groups, rest taking 2 out of 10
yar dekho u did 10c2 to get 2 ppl, but for 2 people u can only take 1 group naa
@mbajamesbond said:I have three kinds of boxes: large, standard and small. I place 11 large boxes on a table. Ileave some of these empty and in each of the others I place 8 standard boxes. Some of thestandard boxes are left empty and in each of the others I place 8 small boxes. All thesmall boxes are empty. Of all the boxes on the table, 102 are now empty. How manyboxes have I used all together?A) 64 B) 102 C) 115 D) 118 E) one cannot say
(11-x)+(8x-y)+8y=102
=>7y+7x=91
=>x+y=13
115
@soham2208 said:a, b are +ve numbers as per the question ?
oops I didn't see that..Let me do it again.. Thanks anyways
@staaalinnn said:Its a + b = 5, where a = -1, b = 6
bhai tume galat ques quote kiya hai
rest ans is correct
rest ans is correct
@mbajamesbond said:I have three kinds of boxes: large, standard and small. I place 11 large boxes on a table. Ileave some of these empty and in each of the others I place 8 standard boxes. Some of thestandard boxes are left empty and in each of the others I place 8 small boxes. All thesmall boxes are empty. Of all the boxes on the table, 102 are now empty. How manyboxes have I used all together?A) 64 B) 102 C) 115 D) 118 E) one cannot say
115 hai kya?
@Brooklyn said:yar dekho u did 10c2 to get 2 ppl, but for 2 people u can only take 1 group naa
correct i am just restricting the number of those 2 student in the 1st case
@mbajamesbond bhai dekh 11 large boxes le
phir 2 large boxes mein 8 aur 8 dalde
phir 8 standard mein 64 small boxes ho gaye phir 3 aur stadard mein 24 ho gaye
is tarah khali bane
9large +5 standard +96 small boxes =102 boxes
ab sabko add karle toh
11 l+16s+88s=115 box
@staaalinnn said:Q> If N be the number of consecutive zeros at the end of the decimal representation of the expression 1! × 2! × 3! × 4! ×............× 99! × 100!.Find the remainder when N is divided by 1000?Options: a) 123 b) 124 c) 125 d) None of these
1-4 => 0
5-9 -> 5
10-14 -> 10
and so on,
Need to care of multiples of 25, where the series jumps by 10 instead of 5
(5 + 10 + 15 + 20 + 30 + 35 + 40 + 45 + 50 + 60 + 65 + 70 + 75 + 80 + 90 + 95 + 100 + 105 + 110 + 24) = Last digit = 4 .. -> b) 124 ?
PS: None of these will be a bad answer .. courtesy: sixth sense :P