a1 + golu + a3....a11 = 1122
10*a11 + a11 = 1122
a11 = 102
a1+ golu + ...a10 = 1020
a10 = 102
and so on
a1 + golu = 204
a1 is given 22
golu = 182 kg
@ani4588 said:Golu's family consists of 12 persons, each having a different age. Golu is the second youngest family member. The youngest member weighs 22 kg and is also the lightest in weight. Also the eldest member's weight is 102 kg. From the third youngest member onwards, every member's weight is average of weights of all the members younger to him. What is Golu's weight?Choose one answer.a. 162 kgb. 102 kgc. 92 kgd. 62 kge. 182 kg
182 kg?
22+182/2 = 102
22+182+102/3 = 102
22+182+102+102/4 = 102
And so on till the 12th family member
@soumitrabengeri said:Seems to be correct and even i got the same answer but the OA has been given as (c)The explanation is given as follows..question is from Arun SharmaA and B can occupy 1st and 9th places..2nd and 10th...3rd and 11th places and so on..This can be done in 18 waysA and B can be arranged in 2 waysAll the other 24 alphabets can be arranged in 24! ways..how is this possible?Hence their answer comes out to be 2*18*24! = 36*24!Option (c)
i feel there is no flaw in r solution..Refer it to GODs
A locker at a famous bank can be opened by dialing a fixed 3 digit code(between 000 and 999). Dawood, a terrorist, only knows that the number is a 3 digit number and has only one six. Using this he tries to open the lock by dialing 3 digits at random. The probability that he succeeds in this is..
1) 1/243
2) 1/900
3) 1/216
4) 1/1000
@rkshtsurana said:i feel there is no flaw in r solution..Refer it to GODs
exactly..there is no flaw in the solution..thanks.
@soumitrabengeri said:2 women Katrina and Deepika are working on an embroidery design. If Deepika worked alone, she would need 8 hours more to complete the design than if they both worked together. Now, if Katrina worked alone, she would need 4.5 hours more to complete the design than if they were working together. What time would it take for Katrina alone to complete the design?1) 10.5 hours2) 12.5 hours3) 14.5 hours4) 18.5 hours
My take 10.5
Method same as grk bhai..
@ani4588 said:Amit, Sumit and Pramit go to a seaside town to spend a vacation there and on the first day everybody decides to visit different tourist locations. After breakfast, each of them boards a different tourist vehicle from the nearest bus-depot. After three hours, Sumit who had gone to a famous sea - beach, calls on the mobile of Pramit and claims that he has observed a shark in the waters. Pramit learns from the local guide that at that time of the year, only eight sea - creatures (including a shark) are observable and the probability of observing any creature is equal. However, Amit and Pramit later recall during their discussion that Sumit has a reputation for not telling the truth five out of six times. What is the probability that Sumit actually observed a shark in the waters?1/36 , 1/30 , 5/36 , 1/24
My take 1/36
Probability that shark was not der = 5/6*7/8 = 35/48
Probability that he told truth and found shark = 1/6*1/8 = 1/48
So 1/48/(1/48+35/48) = 1/36
@soumitrabengeri said:In how many ways can the letters of the English alphabet be arranged so that there are 7 letters between the letters A and B?1) 31!*2!2) 24P7*18!*23) 36*24!4) 26P7*20!*2
3?
36*24!
arrrange 24 memebers u have 18 positions for and b with 2! arrangemements between them.
36*24!
arrrange 24 memebers u have 18 positions for and b with 2! arrangemements between them.
@soumitrabengeri said:A locker at a famous bank can be opened by dialing a fixed 3 digit code(between 000 and 999). Dawood, a terrorist, only knows that the number is a 3 digit number and has only one six. Using this he tries to open the lock by dialing 3 digits at random. The probability that he succeeds in this is..1) 1/2432) 1/9003) 1/2164) 1/1000
Ans : 1/243?
Edit: 1/235 ara h waise :(
@soumitrabengeri said:A locker at a famous bank can be opened by dialing a fixed 3 digit code(between 000 and 999). Dawood, a terrorist, only knows that the number is a 3 digit number and has only one six. Using this he tries to open the lock by dialing 3 digits at random. The probability that he succeeds in this is..1) 1/2432) 1/9003) 1/2164) 1/1000
6xx = 9x 9 = 81
x 6 x = 9x9 = 81 ( 0 can come at hundrrd place)
xx6 = 9 x 9 = 81
total 243
prob of success = 1/243
x 6 x = 9x9 = 81 ( 0 can come at hundrrd place)
xx6 = 9 x 9 = 81
total 243
prob of success = 1/243
@Angadbir said:All no.s are of the form 2k+1So,(2a + 1) + (2b + 1) + (2c + 1) + (2d + 1) + (2e + 1) = 192(a + b + c + d + e) = 14a + b + c + d + e = 7 --> C(11,4) = 330 But if we are looking for unordered sets, we would have to eliminate the repeated cases as below:When all 5 of a,b,c,d,e are same = 0 waysWhen 4 are same -> These are repeated 5 times4x + y = 7 -> y=3,7 -> 2 waysWhen 3 are same and other 2 are same => These are repeated 5!/3!2! = 10 times3x + 2y = 7 -> y = 2 -> 1 wayWhen 3 are same and other 2 are distinct => These are repeated 5!/3! = 20 times3x + y + z = 7x = 0 -> 3 waysx = 1 -> 1 waysx = 2 -> 1 way2 same, 2 same, 1 distinct => These are repeated 5!/2!2! = 30 times2x + 2y + z = 7x = 0 -> 3 ways2 same, 3 distinct => These are repeated 60 times2x + y + z + t = 7 x = 0 -> 1 wayx = 1 -> 1 wayTotal unordered sets = 2 + 1 + 5 + 3 + 2 = 13So 13 ways to achieve this.
13 is the answer .. but that's a pretty much long way to answer the qs.
@soumitrabengeri said:A locker at a famous bank can be opened by dialing a fixed 3 digit code(between 000 and 999). Dawood, a terrorist, only knows that the number is a 3 digit number and has only one six. Using this he tries to open the lock by dialing 3 digits at random. The probability that he succeeds in this is..1) 1/2432) 1/9003) 1/2164) 1/1000
1/243
there are 243 3 digit numbers with a single 6 in them
there are 243 3 digit numbers with a single 6 in them
@rkshtsurana said:6xx = 9x 9 = 81x 6 x = 9x9 = 81 ( 0 can come at hundrrd place)xx6 = 9 x 9 = 81total 243prob of success = 1/243
But there is only 1 six na? 
it should be 9*8 = 72 ways
it should be 9*8 = 72 ways
log(10) 1234 = 3.0912 and
log (10) 769874 = 5.8864
then find ( 0.0769874)^8
1) (o.1234)^2
2) (0.1234)^ -10
3) ( 0.1234)^ -11
4) (0.1234)^ - 12
log (10) 769874 = 5.8864
then find ( 0.0769874)^8
1) (o.1234)^2
2) (0.1234)^ -10
3) ( 0.1234)^ -11
4) (0.1234)^ - 12
@ScareCrow28 ha toh digits can repeat na..6 x x second place ko fill krne k 9 ways ..0 to 9 except 6 and same for 3 place
as angadbir showed earlier..
a+b+c+d+e = 7
now no more of those long calculation he showed..
if u look at the above eqn. it is like 7 balls to be distributed to 5 children when anyone can get any no. of balls.
solutions are
(0,0,0,0,7)
(0,0,0,1,6)
(0,0,0,2,5)
(0,0,0,3,4)
(0,0,1,1,5)
(0,0,1,2,4)
(0,0,1,3,3)
(0,0,2,2,3)
(0,1,1,1,4)
(0,1,1,2,3)
(0,1,2,2,2)
(1,1,1,1,3)
(1,1,1,2,1)
@soumitrabengeri said:A locker at a famous bank can be opened by dialing a fixed 3 digit code(between 000 and 999). Dawood, a terrorist, only knows that the number is a 3 digit number and has only one six. Using this he tries to open the lock by dialing 3 digits at random. The probability that he succeeds in this is..1) 1/2432) 1/9003) 1/2164) 1/1000
My take = 1/243
Total numbers of that form abc with max 1 six
when a = 6 9*9 = 81
when b = 6 9*9 = 81.
when c = 6 9*9 = 81
SO 1/243
Wasted time in neglecting zero 
@rkshtsurana said:@ScareCrow28 ha toh digits can repeat na..6 x x second place ko fill krne k 9 ways ..0 to 9 except 6 and same for 3 place
Not for numbers not stating with 6 na?
x6x --> 8*9 = 72 ways??
@ScareCrow28 said:Not for numbers not stating with 6 na? x6x --> 8*9 = 72 ways??
no it can have zero..ques me padho...its 000 to 999
@rkshtsurana said:log(10) 1234 = 3.0912 andlog (10) 769874 = 5.8864then find ( 0.0769874)^81) (o.1234)^22) (0.1234)^ -103) ( 0.1234)^ -114) (0.1234)^ - 12
2?
@rkshtsurana said:no it can have zero..ques me padho...its 000 to 999
"Dawood, a terrorist, only knows that the number is a 3 digit number and has only one six."
If it starts with "0", then its not a 3 digit -no... Question language me JHOL 