Iska 37 hona chaiye..lag raha hai None of the above?? 
@sujamait said:2(2a + 3d) = 1002a+3d=50a(1+r+r^2+r^3)=99 = 3.3.11D ?
iim should be in G.p and should have scored 100 points. not 99.
Edit
Let E = e^(sinx*ln4) + e^(cosx*ln4)dE/dx = e^(sinx*ln4) * (cosx * ln4) + e^(cosx*ln4) * (-sinx*ln4)
Putting dE/dx= 0, we get,
4^sinx *cosx=4^cosx * sinx
=>tanx=4^(sinx-cosx)
So, max occurs at x=45. and min similarly occurs at 225. (with the condition d2E/dx2 0).
@sauravd2001 said:@karl bhai dekh sin or cos dono fourth quadrant mein negative hote hain toh mi. value wahin ayegi aur cos and sin sirf 1st mein positive hote hain toh max value wahin ayegi
lo ek dum soln
remember (sinx + cosx) max = _/2 and (sinx+cosx) min = -_/2
then,
AM>=GM
4^sinx+4^cosx >= 2. 4^(sinx+cosx)/2
=> (4^sinx+4^cosx) min = 2^(1-_/2)
=> (4^sinx+4^cox) max = 2^(1+_/2)
remember (sinx + cosx) max = _/2 and (sinx+cosx) min = -_/2
then,
AM>=GM
4^sinx+4^cosx >= 2. 4^(sinx+cosx)/2
=> (4^sinx+4^cosx) min = 2^(1-_/2)
=> (4^sinx+4^cox) max = 2^(1+_/2)
@pyashraj ya i think 37 was given in the option i forgot that option. hence used none of the above. please share the approach..
@karl said:@catter2011Let E = e^(sinx*ln4) + e^(cosx*ln4) dE/dx = e^(sinx*ln4) * (cosx * ln4) + e^(cosx*ln4) * (-sinx*ln4) Putting dE/dx= 0, we get, 4^sinx *cosx=4^cosx * sinx =>tanx=4^(sinx-cosx) So, min occurs at x=45. and max similarly occurs at 225. (with the condition d2E/dx2 0).
check my previous post.. bhai max at 45 hoga not min
@sauravd2001 said:@karl bhai dekh sin or cos dono fourth quadrant mein negative hote hain toh mi. value wahin ayegi aur cos and sin sirf 1st mein positive hote hain toh max value wahin ayegi
4th quadrant me cos -ve..??
i have a doubt in this statement.
@freebull yesh 4th quadrant mein cos negative hota hai
its like 1st all are positive
2nd sin is positive
3rd tangent is positive
4th cos is positive
u can remeber by "after school to college"
@sauravd2001 said:@freebull yesh 4th quadrant mein cos negative hota hai its like 1st all are positive 2nd sin is positive 3rd tangent is positive 4th cos is positive u can remeber by "after school to college"
it was though as "All silver tea cups" for us 
@catter2011 said:check my previous post.. bhai max at 45 hoga not min
@sujamait said:diff karoge toh fans jaoge isme!!
Differentiation tedious hai, but same nikal raha hai ans udhar se, bas min and max exchange kar diya maine, long office hours
@sauravd2001 said:@freebull yesh 4th quadrant mein cos negative hota hai its like 1st all are positive 2nd sin is positive 3rd tangent is positive 4th cos is positive u can remeber by "after school to college"
dude jus look at this statement "after school to college" last quadrant i.e. 4th belongs to cos.
so it must be +ve.
draw the graph and u wud know.
@catter2011 said:yeh wilson theorem se rem(4!/6) = 1 ana chahiye.. lekin basic calc karo tho.. 0 agya. ?
bhai n is prime
@sauravd2001 said:@freebull yesh 4th quadrant mein cos negative hota hai its like 1st all are positive 2nd sin is positive 3rd tangent is positive 4th cos is positive u can remeber by "after school to college"
As far as my knowledge goes, 4th quadrant mein cos is +ve..please correct me if i am wrong
@catter2011 haha teachers too believ in shortcut method of learning but mine is easy u have to admit that with all due respect to ur teacher 😛 😛 nywasy tune woh remainder wala padha usmein de rakhi hai williamson theorem
@catter2011
@freebull said:dude jus look at this statement "after school to college" last quadrant i.e. 4th belongs to cos.so it must be +ve.draw the graph and u wud know.
@catter2011 said:it was though as "All silver tea cups" for us
@catter2011 said:it was though as "All silver tea cups" for us
Add Sugar to Cofee (:mg:)
@soumitrabengeri @freebull bhai woh slip of text ho gaya woh galti se maine fourth likh diya waise maine niche wale post mein concept toh sahi bta diya hai ruk j awahan jake edit kar deta hun
@albiesriram said:iim should be in G.p and should have scored 100 points. not 99.
is question ka soln post karo pls..
@albiesriram