@krum said:bhai main to latka hua tha, ibanez bhai ne Sk ko simplify kia 1/(k-1)! tab hua
Aapne itna acha solution nikala hai. Maine toh bevakufo ki tarah k-1 hi cancel kar dia 
min and max value of 4^(sinx)+4^(cosx)?? and plz process ke saath karna
A milkman has 16 lit container full of milk. At the first house, he sells 1 lit of milk and adds water to fill the container. At every subsequent house,he sells twice the volume of solution as he did in the previous house and adds water to fill the container.If he claims to sell at cost price, Find the overall profit percentage made by him by the time the container is empty?
78.25,84.25,87.25,93.75
with soln plz
@gautam22 said:sir inna karne di lod ni hai .....k ki upper value koi bhi daal do(,2,3.....) 3 hi aayega.....same format hota hai har kisi k ke liye....vaise tareeka to yahi hoga par jaldi karne ke liye
Question ke neeche likha tha IIT JEE paper...I enjoyed doing maths question during JEE time...CAT mein utna maza nahi aata...So poora solution deke respect deni banti thi 
@pankaj1988 said:A milkman has 16 lit container full of milk. At the first house, he sells 1 lit of milk and adds water to fill the container. At every subsequent house,he sells twice the volume of solution as he did in the previous house and adds water to fill the container.If he claims to sell at cost price, Find the overall profit percentage made by him by the time the container is empty?78.25,84.25,87.25,93.75with soln plz
Total Milk+Water solution sold = 1 + 2 + 4 + 8 + 16 = 31
So profit% = (31-16)/16 * 100 = 93.75% ?
So profit% = (31-16)/16 * 100 = 93.75% ?
@astute99 said:min and max value of 4^(sinx)+4^(cosx)?? and plz process ke saath karna
differentiate it..and the equate to 0
log4(4^sinx*cosx-4^cosx*sinx)=0
4^(sinx-cosx)=tanx
hence we get x=pi/4(at x=pi/4 could be maxima or minima)
since this a periodic function with a period 2pi...so maxima and minima will be at interval of pi.
other value will be 5pi/4
we will see that value of function is maximum at pi/4 and value is 2*4^(1/_/2)
and minimum value is at 5pi/4 and value is 2/4^(1/_/2)
@pankaj1988 said:
A milkman has 16 lit container full of milk. At the first house, he sells 1 lit of milk and adds water to fill the container. At every subsequent house,he sells twice the volume of solution as he did in the previous house and adds water to fill the container.If he claims to sell at cost price, Find the overall profit percentage made by him by the time the container is empty?78.25,84.25,87.25,93.75with soln plz
total water added is 1+2+4+8 and total milk is 16 litres so in total 31 litres.
So 15/16 =93.75%
@crazy_mn2002 said:Find the missing term in the series :(1). 64 128 92 220 148 404 ?(2). 5 ? 4 7.5 17 45
do u hv soln for 2nd series...???
If anyone able to crack...plz post soln
@crazy_mn2002 said:Find the missing term in the series :(1). 64 128 92 220 148 404 ?(2). 5 ? 4 7.5 17 45
1, 404-144=260.
Differentiat: 4^sinx
What is the sum of the series :
S = 1/(1.2.3) + 1/(3.4.5) + 1/(5.6.7) + .....
a> (e^2) -1
b> (log 2 base e) - 1
c> 2(log 2 base 10) -1
d> none of these
Thanks in advance.
@mohnish_khiani said:What is the sum of the series :S = 1/(1.2.3) + 1/(3.4.5) + 1/(5.6.7) + .....a> (e^2) -1 b> (log 2 base e) - 1c> 2(log 2 base 10) -1d> none of theseThanks in advance.
none?
@pankaj1988 said:differentiate it..and the equate to 0log4(4^sinx*cosx-4^cosx*sinx)=04^(sinx-cosx)=tanxhence we get x=pi/4(at x=pi/4 could be maxima or minima)since this a periodic function with a period 2pi...so maxima and minima will be at interval of pi.other value will be 5pi/4we will see that value of function is maximum at pi/4 and value is 2*4^(1/_/2)and minimum value is at 5pi/4 and value is 2/4^(1/_/2)
hw u get x=pi/4 and hw u know that it is a periodic function with a period 2pi???????
@mohnish_khiani said:1/(1.2.3) + 1/(3.4.5) + 1/(5.6.7)..What is the sum of the series :S = 1/(1.2.3) + 1/(3.4.5) + 1/(5.6.7) + .....a> (e^2) -1 b> (log 2 base e) - 1c> 2(log 2 base 10) -1d> none of theseThanks in advance.
=>1/2(2/2-2/3+1/12-1/20+1/30-1/42...)
=>1/2(1-2/3+1/3-1/4-1/4+1/5+1/5-1/6...)
=>1/2(2/3-2/4+2/5-2/6..)
=>(1-1/2+1/3-1/4+1/5+....) - 1/2
=>log 2 -1/2
@mohnish_khiani said:What is the sum of the series :S = 1/(1.2.3) + 1/(3.4.5) + 1/(5.6.7) + .....a> (e^2) -1 b> (log 2 base e) - 1c> 2(log 2 base 10) -1d> none of theseThanks in advance.
1/2( 1/2 - 1/(n+1)(n+2)
as n --> infinity
ans is 1/4
option D
@krum said:1/(1.2.3) + 1/(3.4.5) + 1/(5.6.7)..=>1/2(2/2-2/3+1/12-1/20+1/30-1/42...)=>1/2(1-2/3+1/3-1/4-1/4+1/5+1/5-1/6...)=>1/2(2/3-2/4+2/5-2/6..)=>(1-1/2+1/3-1/4+1/5+....) - 1/2=>log 2 -1/2
bhai yeh toh negative aa rhe he..locha he kuch dekh..