bhai mera toh LAMBA hai......(method)...... multiplication method....thodi fast calculation chahiye....2^29=(2^30)/2=(1024^3)/2 =536870912.........4is missing.........not recommended if fast multiplication tricks r not known... bhai dont know any special tricky method for dis ques...... oder dan multiplication.....
bhai mera toh LAMBA hai......(method)......multiplication method....thodi fast calculation chahiye....2^29=(2^30)/2=(1024^3)/2=536870912.........4is missing.........not recommended if fast multiplication tricks r not known...bhai dont know any special tricky method for dis ques...... oder dan multiplication.....
trick is simple divide it by 9..remainder is 5 ..so 4 is missing ..
Recently smoking at public places is declared as an offence. Delhi Police has started imposinga penalty against smoking in public and has eight raid teams in place. In a surprise check, theraid team caught 40 people smoking in the Connaught Place area of Delhi. The standarddeviation and sum of squares of the amount found in their pockets were Rs. 10 and Rs. 40000,respectively. If the total fine imposed on these offenders is equal to the total amount found intheir pockets and the fine imposed is uniform, what is the amount that each offender will haveto pay as fine?(1) Rs. 90(2) Rs. 60(3) Rs. 30(4) Rs. 15OA is rs30....share ur approach also.....plz......
Edit : Let the ampunts be a1, a2, a3...a40
Avg = A = (a1+a2+...+a40)/40
and a1^2 + a2^2 +...+a40^2 = 40000
Standard deviation=10= root((A-a1)^2 + (A-a2)^2 +...+(A-a40)^2)/40)
Recently smoking at public places is declared as an offence. Delhi Police has started imposinga penalty against smoking in public and has eight raid teams in place. In a surprise check, theraid team caught 40 people smoking in the Connaught Place area of Delhi. The standarddeviation and sum of squares of the amount found in their pockets were Rs. 10 and Rs. 40000,respectively. If the total fine imposed on these offenders is equal to the total amount found intheir pockets and the fine imposed is uniform, what is the amount that each offender will haveto pay as fine?(1) Rs. 90(2) Rs. 60(3) Rs. 30(4) Rs. 15OA is rs30....share ur approach also.....plz......
Let the ampunts be a1, a2, a3...a8Avg = A = (a1+a2+...+a8)/40Standard deviation=10= root((A-a1)^2 + (A-a2)^2 +...+(A-a8)^2)/40)=> 40A^2 = 3600=> A = 30So each hhas to pay 30 Rs..
2^29 is a 9 digit number containing all distinct digits. Which number is missing ?
I proceeded this way 9 distinct digits sum =45(1+2+..9)= multiple of 3 so if the missing number will be multiple 3 then whole number wil be divisible by 3 so 0,3,6,9 can't be missing mod[2^29,10], mod[2^29,100] = 2,1 so 0,3,6,9,2,1 can't be missing
Now first digit will be 5
2^1 = 2 2^2 = 4 2^3 = 8 2^4 = 16 2^5 = 32 2^6 = 64 2^7 = 128 2^8 = 256 2^9 = 512 2^10 = 1024 ========= first digit starts repeating so first digit of 2^29=5 2^11 = 2048 2^ 12 = 4096 2^ 13 = 8192 so 0,3,6,9,2,1,5 can't be missing
Now we left with 4,7,8. Hope Koi ek hi option mai ho 😛
The total number of relations that can be defined from a Set A to set B is 4096. If m and n are the number of elements in set A and set B respectively, find the total number of values the ordered pair (m,n) can take?
