@chillfactor namaste ____/\____
P.S: this is not considered as spam 
@sujamait said:
The functionf(n) is defined on the set of integers.f(n) satisfies the given conditions;f(n) = n €“ 3 if n ‰Ľ 1000= f(f(n + 5)) if n Find f(84).OPTIONS1) 100 2) 84 3) 998 4) 997
option 4
typical Testfunda stuff ;)
typical Testfunda stuff ;)
@Messy_19 said:6 is correct.Nasik express travels to and fro between Nasik and Kanpur. The express halts at 10 other stations in its route. Find the number of types of tickets required so that it is possible to book a passenger from every station to every other station. 12!/2!12!/(10!*2!) 12!/10!12!/(2!) ˛(10!)None
12!/10! ?
@ScareCrow28 said:a, b and c are the sides of a triangle. Equations ax^2 + bx + c = 0 and 3x^2 + 4x + 5 = 0 have a common root. Then angle C is equal to(1) 600 (2) 900 (3) 1200 (4) None of these
common root be K so,
k^2/(5b - 4c) = k/3c-5a = 1/4a-3b ,aisa hee hota hai na kuch ?
isse kuch relation aayega..jo niche use karna hoga..pen nhn hai so.. ..
cos C = a^2 + b^2 - c^2/2ab
k^2/(5b - 4c) = k/3c-5a = 1/4a-3b ,aisa hee hota hai na kuch ?
isse kuch relation aayega..jo niche use karna hoga..pen nhn hai so.. ..
cos C = a^2 + b^2 - c^2/2ab
@Messy_19 said:6 is correct.Nasik express travels to and fro between Nasik and Kanpur. The express halts at 10 other stations in its route. Find the number of types of tickets required so that it is possible to book a passenger from every station to every other station. 12!/2!12!/(10!*2!) 12!/10!12!/(2!) ˛(10!)None
oops multiply kar diya tha..
12!/10! hoga..
chillfactor praman siji!!
@sujamait said:
The functionf(n) is defined on the set of integers.f(n) satisfies the given conditions;f(n) = n €“ 3 if n ‰Ľ 1000= f(f(n + 5)) if n Find f(84).OPTIONS1) 100 2) 84 3) 998 4) 997
f(1000) = 997
f(999) = f(f(1004)) = f(1001) = 998
f(998) = f(f(1003)) = f(1000) = 997
f(997) = 998
and so on
For n
f(even) = 997
f(odd) = 998
=> f(84) = 997
@Messy_19 said:6 is correct.Nasik express travels to and fro between Nasik and Kanpur. The express halts at 10 other stations in its route. Find the number of types of tickets required so that it is possible to book a passenger from every station to every other station. 12!/2!12!/(10!*2!) 12!/10!12!/(2!) ‚Ë›(10!)None
Nasik to every other station = 11 tickets
1st station to every other station = 11 tickets
.
.
.
kanpur to every other = 11 tickets
total = 11*12 = 12!/10!
@chillfactor gurudev \\_____O//
@Messy_19 said:6 is correct.Nasik express travels to and fro between Nasik and Kanpur. The express halts at 10 other stations in its route. Find the number of types of tickets required so that it is possible to book a passenger from every station to every other station. 12!/2!12!/(10!*2!) 12!/10!12!/(2!) ˛(10!)None
is it c?????
Nahi Suja bhai...12!/10! hai answer
Pranam Chill Sir!!
@Messy_19 said:6 is correct.Nasik express travels to and fro between Nasik and Kanpur. The express halts at 10 other stations in its route. Find the number of types of tickets required so that it is possible to book a passenger from every station to every other station. 12!/2!12!/(10!*2!) 12!/10!12!/(2!) ˛(10!)None
12!/10! ?
@Messy_19 said:Nahi Suja bhai...12!/10! hai answerPranam Chill Sir!!
han yar addition ki jagah multiplication kar betha tha mein..
@Messy_19 said:6 is correct.Nasik express travels to and fro between Nasik and Kanpur. The express halts at 10 other stations in its route. Find the number of types of tickets required so that it is possible to book a passenger from every station to every other station. 12!/2!12!/(10!*2!) 12!/10!12!/(2!) ˛(10!)None
Select the two stations = 12C2
Tickets can be bought in 2 ways (A to B / B to A)
Hence 12C2*2 = 12!/10!
Between two numbers whose sum is 6 ˝ an even number of arithmetic means is inserted;
the sum of these means exceeds their number by unity. How many means are there?
(1) 12 (2) 6 (3) 24 (4) None
the sum of these means exceeds their number by unity. How many means are there?
(1) 12 (2) 6 (3) 24 (4) None
The lenght of longest rod that can be kept in rectangular room is 2root17 m. The sum of the dimensions of the room all taken in m is 14. Find the total surface area of the room is sq. m
@sujamait said:hehe...sahi hai..XAT ko CAT samajh rakha hai inhone...XAT cat ke papa ban chuke hein ab..The functionf(n) is defined on the set of integers.f(n) satisfies the given conditions;f(n) = n €“ 3 if n ‰Ľ 1000= f(f(n + 5)) if n Find f(84).OPTIONS1) 100 2) 84 3) 998 4) 997
getting 998 !
@Messy_19 said:The lenght of longest rod that can be kept in rectangular room is 2root17 m. The sum of the dimensions of the room all taken in m is 14. Find the total surface area of the room is sq. m
128? 
@ScareCrow28 said:Between two numbers whose sum is 6 ˝ an even number of arithmetic means is inserted;the sum of these means exceeds their number by unity. How many means are there?(1) 12 (2) 6 (3) 24 (4) None
ohh bhari bhari Q daal rhe ho 
a .............. b
a+b=13/2
b=a+(n-1)d
d=b-a/n-1
let there be p (even) means,
p/2(2(a+d) + (p-1)*d) - p = 1
p nikal hee jayega isse..pen nhn hai yar..
a .............. b
a+b=13/2
b=a+(n-1)d
d=b-a/n-1
let there be p (even) means,
p/2(2(a+d) + (p-1)*d) - p = 1
p nikal hee jayega isse..pen nhn hai yar..
@Messy_19 said:The lenght of longest rod that can be kept in rectangular room is 2root17 m. The sum of the dimensions of the room all taken in m is 14. Find the total surface area of the room is sq. m
128 ?
@Messy_19 said:The lenght of longest rod that can be kept in rectangular room is 2root17 m. The sum of the dimensions of the room all taken in m is 14. Find the total surface area of the room is sq. m
a+b+c= 14
root(a^2+b^2+c^2) = 2 root 17
(a^2+b^2+c^2) = 68
so,
a+b+c^2 = (a^2+b^2+c^2) + 2(ab+bc+ca)
bold part nikalna hai yeh toh nikal hee jayega..
196 - 68 = 128
root(a^2+b^2+c^2) = 2 root 17
(a^2+b^2+c^2) = 68
so,
a+b+c^2 = (a^2+b^2+c^2) + 2(ab+bc+ca)
bold part nikalna hai yeh toh nikal hee jayega..
196 - 68 = 128
@Messy_19 said:The lenght of longest rod that can be kept in rectangular room is 2root17 m. The sum of the dimensions of the room all taken in m is 14. Find the total surface area of the room is sq. m
14^2-(4*17)=128?