@milestogo3 said:10^ 5 numbers?total numbers possible 9.10^5, every 9th number would be divisible by 9so 10^5.9/9ps: what was the source of last question....base one?
Yes it's 10^5, I approached the same way. :)
@sujamait said:lengthy approach hai..koi choti nhn soch pa rha hu
choti hai. But doubt hai ans 10^5 hi hoga kya?
@pyashraj said:@Torque024Here, _ _ _ _ _ _5.. Thus, x1 + x2 + x3 + x4 + x5 + x6 + 5 has to be a multiple of 9..Thus, x1x2x3x4x5x6 is a 6-digit number which can be generalized as 9y + 4.., and x1>1..Hence, there are 9*10^5 numbers, and out if such numbers which are 9y+4 form=1/9*9*10^5=>10^5??
last but one is second last digit.
Waise thanx for the info..Mujhe yeh baat pata nahi thi..@pyashraj said:@milestogo3Hai..Tab toh galat hai..
tab bhi shi hai with the same logic. :P
divisible of nine means we need to check digital sum...
so _ _ _ _ _ 5_
keeping one digit constant, we need to find number of digits having sum 9a+4 , which will come after every ninth digit.
PG post 2009.
Q). The ticket office at a train station sells tickets to 200 destinations. One day, 3800 passengers buy tickets. Then minimum no of destinations receive the same number of passengers is
A.6 B.5 C.7 D.9
Q). The ticket office at a train station sells tickets to 200 destinations. One day, 3800 passengers buy tickets. Then minimum no of destinations receive the same number of passengers is
A.6 B.5 C.7 D.9
@Torque024
I think i am wrong..but still posting:
Destination1=1 person
Destination2=2 person
.
.
.
Destination200=200 person, Thus a total of 200*201/2=20,100 person can be distributed in such a fashion, that each destination can have a unique number of visitors. The given number of 3800 is very small. Hence no destination will have the same number of visitors.. Hence 0 hona chaiye but that's not in the Option only.. :(
Hi puys....here is a link to the thread, sentence correction for CAT 2013....ATB..
@Torque024 said:PG post 2009.Q). The ticket office at a train station sells tickets to 200 destinations. One day, 3800 passengers buy tickets. Then minimum no of destinations receive the same number of passengers is A.6 B.5 C.7 D.9
6
1,2,3,4...............38 tickets to 38 stations in a respective order, and making a group of 5 for further 38 stations ,
:: 741 + 741 + 741 +741 + 741 = 3705
95 tickets 10 remaining , five stations 0
the other five station 95/ 39+40+8,7,1.
so minimum station recieving the same passengers:: 6
ps: source kya hai [1]?
10% of salty sea water contained in a flask was poured out in a beaker.After this a part of water contained in beaker was
vaporized by heating and due to this,the percentage of salt in beaker increased "M" times.If it is known that after the
content of beaker was poured into the flask,the percentage of salt in the flask increased by x%.Find the original quantity
of sea water in the flask.
plz guys help karo...arun sharma ka hai ye ..plz.....
vaporized by heating and due to this,the percentage of salt in beaker increased "M" times.If it is known that after the
content of beaker was poured into the flask,the percentage of salt in the flask increased by x%.Find the original quantity
of sea water in the flask.
plz guys help karo...arun sharma ka hai ye ..plz.....
suppose three coins are lying on a table ,two of them with head facing up and one with tails lying up.One coin is chossen at random and flipped.What is probability that after flip the majority of the coins (at least 2 of them will have haeds facing up)
@naga25french said:Age old question answer is 9 .. bit lazy to type 6th season quant thread
sir you don't need to write all 1997 integers 
share thought process
@gnehagarg said:suppose three coins are lying on a table ,two of them with head facing up and one with tails lying up.One coin is chossen at random and flipped.What is probability that after flip the majority of the coins (at least 2 of them will have haeds facing up)
2/3?
Assuming the coins are fair:
probability of choosing the T coin = 1/3
probability of choosing the H coin = 2/3
probability that the H coin gives H after tossing = 1/2
total probability = 1/3 + 2/3 * 1/2 = 1/3 + 1/3 = 2/3
Assuming the coins are fair:
probability of choosing the T coin = 1/3
probability of choosing the H coin = 2/3
probability that the H coin gives H after tossing = 1/2
total probability = 1/3 + 2/3 * 1/2 = 1/3 + 1/3 = 2/3
@jain4444 said:sir you don't need to write all 1997 integers share thought process
naga25french
how as your CAT sirji ?
how as your CAT sirji ?
@grkkrg said:2/3?Assuming the coins are fair:probability of choosing the T coin = 1/3probability of choosing the H coin = 2/3probability that the H coin gives H after tossing = 1/2total probability = 1/3 + 2/3 * 1/2 = 1/3 + 1/3 = 2/3
Please correct me if i am wrong, here the coins are just being flipped, i suppose, you are assuming they are being tossed.
If they are being tossed, then shouldn't the total probability be = 1/3*1/2 + 2/3*1/2 = 1/2 ?
@gnehagarg said:suppose three coins are lying on a table ,two of them with head facing up and one with tails lying up.One coin is chossen at random and flipped.What is probability that after flip the majority of the coins (at least 2 of them will have haeds facing up)
1/3+ 2/3*1/2 =2/3.
@grkkrg sorry you were correct .. i misread the question
@rachit_28 its 1/3*1 coz u have majority heads irrespective of what it lands up as
@rachit_28 its 1/3*1 coz u have majority heads irrespective of what it lands up as
@gnehagarg said:suppose three coins are lying on a table ,two of them with head facing up and one with tails lying up.One coin is chossen at random and flipped.What is probability that after flip the majority of the coins (at least 2 of them will have haeds facing up)
H H T
when H is flipped - 2/3*1/2
when T is flipped - 1/3*1
so 1/3+1/3=2/3
when H is flipped - 2/3*1/2
when T is flipped - 1/3*1
so 1/3+1/3=2/3
@rachit_28 said:Please correct me if i am wrong, here the coins are just being flipped, i suppose, you are assuming they are being tossed. If they are being tossed, then shouldn't the total probability be = 1/3*1/2 + 2/3*1/2 = 1/2 ?
I guess you are right about flipping and not tossing. It should be 1/3 then. 
But if the coins were tossed, then the result of the T coin wouldn't matter.
So that part will be 1/3 * 1 + 2/3 * 1/2 = 2/3
But if the coins were tossed, then the result of the T coin wouldn't matter.
So that part will be 1/3 * 1 + 2/3 * 1/2 = 2/3