Official Quant thread for CAT 2013

I is a set of natural numbers

1) is a set of 3 digit numbers leaves remainder of 2 when divided by 4.
2) is divisible by 11 but not by 13.
Number of elements in I ?

@albiesriram how many solutions of 5

i am getting 72-4-4 =64 olutions

and solving them i am able to get at least 14 pairs

1,2

1,3

2,2

2,3

2,4

3,3

3,4

7 for positives aas above and 7 if i make them negative so mimimum 14

@pankaj1988 said:
I is a set of natural numbers1) is a set of 3 digit numbers leaves remainder of 2 when divided by 4.2) is divisible by 11 but not by 13.Number of elements in I ?
11x=4y+2
=>4y=8x+3x-2
=>x=2

22+44k=>110,154,198,..,990 - 21 terms

(22+44k)mod13
=>5k-4
=>k=6,19

19 terms

@pankaj1988 han yaar, k=2 se start hota hai

edited
@albiesriram said:
@vijay_chandola 10
20 only..
@albiesriram how did you get the rest 6 terms i missed :banghead:
@techsurge negatives ??

@albiesriram
Check again. OA given is 20
@vijay_chandola edited

i splitted for several values like -4,-3,-2 etc..

(-4,-3)(-4-2)
(-3,-4)(-3,-3)(-3,-2),(-3,-1),
(-2,-4)(-2,-3),(-2,-2)
(-1,-3)
(1,3)
(2,2)(2,3)
(3,1)(2,4)(3,2)(3,3)(3,4)
(4,2)(4,3)
@pankaj1988 said:
I is a set of natural numbers1) is a set of 3 digit numbers leaves remainder of 2 when divided by 4.2) is divisible by 11 but not by 13.Number of elements in I ?
20 ?
@krum said:
11x=4y+2=>4y=8x+3x-2=>x=222+44k=>110,154,198,..,990 - 22 terms(12+44k)mod13=>5k-1=>k=8,2120 terms?
Bhai 110.....990 has 21 terms...so ans will be 19.....
@gs4890 said:
20 ?


OA is 19 ... chk krum's approach

@pankaj1988 said:
Bhai 110.....990 has 21 terms...so ans will be 19.....
so there are two terms in the series which is divisible by 13 , rite ? one is 286 , can tfind the other one
@gs4890 said:
so there are two terms in the series which is divisible by 13 , rite ? one is 286 , can tfind the other one
858
@techsurge said:
area in cubic cm ???
sorry, that ws a typo..square cm
@gs4890 said:
so there are two terms in the series which is divisible by 13 , rite ? one is 286 , can tfind the other one
13*11*6=858
4n+2 condition chk kiya hai...
@invincible2910 said:
sorry, that ws a typo..square cm
u have some lr sets ? plz post here

the radius of the front tyre of a gypsy is 5/pie m long and that of the rear tyre is 7.5/pie m long. what is the distance travelled by the gypsy after the first tyre has undergone 6 more revolutions than the rear tyre?
150 m ; 100 m ; 144m ; 180 m

45 degree for 490 cm2 .for 419 @invincible2910

@invincible2910 144?