@Ashmukh said:what is the min value of 48cos x-20 sin x
-root(48^2+20^2)
A solid cube just gets completely immersed in water when a 0.2 kg mass is placed on it. If the mass is removed, the cube is 2 cm above the water level. What is the length of each side of the cube?
1)10cm
2)8cm
3)6cm
4)NOT
with approach please??
@Ashmukh said:@sujamait plzz explain
48cos x-20 sin x
48 = r cos p
20 = r sin p
r^2 = 48^2 + 20^2 [ sq above eqns and add them to get this]
so,
r(cos(p+x))
now min val of cos theta is -1,as it varies between [-1,1]
so,
-r is answer , that is , - root (48^2 + 20^2)
@kansihktew said:A solid cube just gets completely immersed in water when a 0.2 kg mass is placed on it. If the mass is removed, the cube is 2 cm above the water level. What is the length of each side of the cube?1)10cm2)8cm3)6cm4)NOTwith approach please??
seems like physics Q 
cube ki density ? let x be side of cube
let x be side of cubem*g = density of water * g * (x-2) .... here h= cube inside water when the 0.2kg thing is not placed over it,m= mass = volume of the part of cube inside water * density of cube = x.x.(x-2) * D
we can get D from here..density of water is 1000 kg/m^3 ..convert m^3 to cm^3 ..10^-3 aayega
also,
(m'+0.2)g = density of water * g * (x)
yahan se x nikal aayegi..
............................................
@kansihktew said:
@sujamait did the calculations, x is getting cancelled out.
aisa kya ,then i dunno how to do it..
waise second eqn ka m is not same as 1st ka m..
2nd wala m mein volme poore cube ka lena hoga...
@kansihktew said:A solid cube just gets completely immersed in water when a 0.2 kg mass is placed on it. If the mass is removed, the cube is 2 cm above the water level. What is the length of each side of the cube?1)10cm2)8cm3)6cm4)NOTwith approach please??
is it 10 ???
@sujamait said:aisa kya ,then i dunno how to do it..waise second eqn ka m is not same as 1st ka m..2nd wala m mein volme poore cube ka lena hoga...
@kansihktew said:@sujamait did the calculations, x is getting cancelled out.
my logic : lets convert everything in g and cm
so let side of cube =x
now
vol of water displaced when no mass on it =x^2*(x-2)
(soo this + 0.2Kg )*density of water =vol of cube
so since were takin everything in g/cm^3, denstiy of water =1
we get:
x^3=200+x^3-2x^2
solve u get x=10
@Brooklyn i would like to ask why density of water and not that of cube but that would be digressing from the whole point of this thread so lets leave it at this.
@sujamait said:The total number of two digit numbers in which the ten €™s digit is either identical, double, triple, quadruple, five times, six times, seven times or eight times the units digit is:OPTIONS1) 43 2) 21 3) 45 4) 22
4) 22
units digit = 1 -> 8 values
2 -> 4
3 -> 3
4 -> 2
5 -> 1
6,7,8,9 -> 1
Total = 8 + 4 + 3 + 2 + 5 = 22
units digit = 1 -> 8 values
2 -> 4
3 -> 3
4 -> 2
5 -> 1
6,7,8,9 -> 1
Total = 8 + 4 + 3 + 2 + 5 = 22
@kansihktew said:@Brooklyn i would like to ask why density of water and not that of cube but that would be digressing from the whole point of this thread so lets leave it at this.
i took density of water coz its universally known simple, i dont knw the density of cube. So i cant solve problem by introducing a new variable
In a regular tetrahedron the centers of the four faces are the vertices of a smaller tetrahedron. The ratio of the volume of the smaller tetrahedron to that of the larger is m/n, where m and n are relatively prime positive integers. Find m + n.
Three business entities X Ltd, Y Ltd. and Z Ltd,
with 4, 3 and 5 employees respectively, merged
into XYZ Ltd in order to jointly raise the capital for
setting up a new modern production plant in Jaipur.
After two years, on the question of management
decisions on the new venture at Jaipur, the
employees started adopting differing viewpoints and
began to quarrel among themselves. Given the fact
that there is no quarrel among the employees of
the erstwhile X Ltd, Y Ltd and Z Ltd, what could be
the maximum number of quarrels that can take place
within XYZ Ltd?
{IIFT 2007}
with 4, 3 and 5 employees respectively, merged
into XYZ Ltd in order to jointly raise the capital for
setting up a new modern production plant in Jaipur.
After two years, on the question of management
decisions on the new venture at Jaipur, the
employees started adopting differing viewpoints and
began to quarrel among themselves. Given the fact
that there is no quarrel among the employees of
the erstwhile X Ltd, Y Ltd and Z Ltd, what could be
the maximum number of quarrels that can take place
within XYZ Ltd?
{IIFT 2007}
@gs4890 said:Three business entities X Ltd, Y Ltd. and Z Ltd,with 4, 3 and 5 employees respectively, mergedinto XYZ Ltd in order to jointly raise the capital forsetting up a new modern production plant in Jaipur.After two years, on the question of managementdecisions on the new venture at Jaipur, theemployees started adopting differing viewpoints andbegan to quarrel among themselves. Given the factthat there is no quarrel among the employees ofthe erstwhile X Ltd, Y Ltd and Z Ltd, what could bethe maximum number of quarrels that can take placewithin XYZ Ltd?{IIFT 2007}
47?
(3 + 5) * 4 + (5) * 3 = 47
(3 + 5) * 4 + (5) * 3 = 47
@gs4890 said:Three business entities X Ltd, Y Ltd. and Z Ltd,with 4, 3 and 5 employees respectively, mergedinto XYZ Ltd in order to jointly raise the capital forsetting up a new modern production plant in Jaipur.After two years, on the question of managementdecisions on the new venture at Jaipur, theemployees started adopting differing viewpoints andbegan to quarrel among themselves. Given the factthat there is no quarrel among the employees ofthe erstwhile X Ltd, Y Ltd and Z Ltd, what could bethe maximum number of quarrels that can take placewithin XYZ Ltd?{IIFT 2007}
3^9 + 4^5 IMO :splat:
3C1*5C1 + 5C1*4C1 + 4C1*3C1 = 47??
@gs4890 said:Three business entities X Ltd, Y Ltd. and Z Ltd,with 4, 3 and 5 employees respectively, mergedinto XYZ Ltd in order to jointly raise the capital forsetting up a new modern production plant in Jaipur.After two years, on the question of managementdecisions on the new venture at Jaipur, theemployees started adopting differing viewpoints andbegan to quarrel among themselves. Given the factthat there is no quarrel among the employees ofthe erstwhile X Ltd, Y Ltd and Z Ltd, what could bethe maximum number of quarrels that can take placewithin XYZ Ltd?{IIFT 2007}