Official Quant thread for CAT 2013

@gs4890 :

Q.3

Mr. and Mrs. Gupta have three children - Pratik,
Writtik and Kajol, all of whom were born in different
cities. Pratik is 2 years elder to Writtik. Mr. Gupta
was 30 years of age when Kajol was born in
Hyderabad, while Mrs. Gupta was 28 years of age
when Writtik was born in Bangalore. If Kajol was 5
years of age when Pratik was born in Mumbai, then
what were the ages of Mr. and Mrs. Gupta
respectively at the time of Pratik's birth?

A. 35 years, 26 years B. 30 years, 21 years
C. 37 years, 28 years D. None of the above


option A IMO. bear wid me...ofce me hu :P

@pankaj1988 said:
Q.6 If a not equal to pi. and tan a is GM of sin a and cas a, determine the square of expression 2-4sina^2+3sina^4-sina^61,4,1/4, none@gs4890 @lopagargg @soumitrabengeri @Torque024 @rachit_28
Trigo
@pankaj1988 said:
Q.6 If a not equal to pi. and tan a is GM of sin a and cas a, determine the square of expression 2-4sina^2+3sina^4-sina^61,4,1/4, none@gs4890 @lopagargg @soumitrabengeri @Torque024 @rachit_28
none hai kya?
@gs4890 said:
Q.4

Mr. Sinha received a certain amount of money by
winning a lottery contest. He purchased a new
vehicle with 40 percent of the money received. He
then gave 20 percent of the remaining amount to
each of his two sons for investing in their business.
Thereafter, Mr. Sinha spent half of the remaining
amount for renovation of his house. One-fourth of
the remaining amount was then used for purchasing
a LCD TV and the remaining amount - Rs. 1,35,000/
- was deposited in a bank. What was the amount
of his cash prize?

A. Rs. 10,00,000/- B. Rs. 9,00,000/C.
Rs. 8,00,000/- D. None of the above


option A IMO.
@pankaj1988 said:
Q.6 If a not equal to pi. and tan a is GM of sin a and cas a, determine the square of expression 2-4sina^2+3sina^4-sina^61,4,1/4, none@gs4890 @lopagargg @soumitrabengeri @Torque024 @rachit_28
1?
@pankaj1988 said:
Q.6 If a not equal to pi. and tan a is GM of sin a and cas a, determine the square of expression 2-4sina^2+3sina^4-sina^61,4,1/4, none@gs4890 @lopagargg @soumitrabengeri @Torque024 @rachit_28
agla dalo bhai ; sabke liye bouncer tha it seems 😛 ..give all the explainations if needed later on ; will break the flow otherwise :)
@pankaj1988 said:
Q.6 If a not equal to pi. and tan a is GM of sin a and cas a, determine the square of expression 2-4sina^2+3sina^4-sina^61,4,1/4, none@gs4890 @lopagargg @soumitrabengeri @Torque024 @rachit_28
Is it 1?
@pankaj1988 said:
Q.6 If a not equal to pi. and tan a is GM of sin a and cas a, determine the square of expression 2-4sina^2+3sina^4-sina^61,4,1/4, none@gs4890 @lopagargg @soumitrabengeri @Torque024 @rachit_28@maddy2807

OA...1

Q.6
CHK THE ATTACHMENT

@maddy2807 said:
1?
yaar explain bhi kar do yahan to 2-3 steps ke baad samjh mein hi nahi aaya kya karna hai..
@maddy2807 said:
1?
post approach.
@gs4890 said:
agla dalo bhai ; sabke liye bouncer tha it seems ..give all the explainations if needed later on ; will break the flow otherwise
bhai yeh ques 4-5 din pehle quant thread par discuss hua tha...@maddy2807 @soumitrabengeri bhai ko yaad hoga sayad
@gs4890 said:
Q.5 (IIFT 11)

The ratio of number of male and female journalists
in a newspaper office is 5 : 4. The newspaper has
two sections, political and sports. If 30 percent of
the male journalists and 40 percent of the female
journalists are covering political news, what
percentage of the journalists (approx.) in the
newspaper is currently involved in sports reporting?

A. 65 percent B. 60 percent
C. 70 percent D. None of the above

Last Q from my side

Over to you
@pankaj1988


65 percent
@pankaj1988 said:
OA...1Q.6CHK THE ATTACHMENT
143?
@pankaj1988 said:
OA...1Q.6CHK THE ATTACHMENT
143 cms
@pankaj1988 said:
bhai yeh ques 4-5 din pehle quant thread par discuss hua tha...@maddy2807@soumitrabengeri bhai ko yaad hua tha sayad
Yeah.i remember..that's why i did not post the solution..wanted the others to try it
@pankaj1988 said:
OA...1Q.6CHK THE ATTACHMENT
143??
@mailtoankit said:
yaar bhi kar do yahan to 2-3 steps ke baad samjh mein hi nahi aaya kya karna hai..
@Torque024 said:
post approach.


sin^2a/cos^a=sinacosa
sina=cos^3a
sin^2a=cos^6a
Now
2-4sina^2+3sina^4-sina^6
2-4cos^6a+3sin^4a-sin^6a
2-3cos^6a+3sin^4a-(sin^6a+cos^6a)
2-3sin^acos^a-(sin^6a+cos^6a)
2-[(sin^6a+cos^6a)+3sin^2acos^a(sin^2a+cos^2a)]
2-(sin^2a+cos^a)^3
2-1=1

@pankaj1988 said:
OA...1Q.6CHK THE ATTACHMENT
143 ?
@Torque024 said:
post approach.
@mailtoankit said:
yaar bhi kar do yahan to 2-3 steps ke baad samjh mein hi nahi aaya kya karna hai..
@gs4890

tana= rt(sina * cosa)

(sina /cosa)^2= sina * cosa
sina = cos^3a--------->1
cosa= rt(1-sin^2a)

put this in 1
sina= (1-sin^2a)^3/2

open powers and you will get the solution

@pankaj1988 said:
OA...1Q.6CHK THE ATTACHMENT

@rachit_28 @gs4890 @soumitrabengeri @maddy2807 @lopagargg @Torque024 @mailtoankit @deedeedudu
OA-143


Q.8 CHK THE ATTACHMENT