Official Quant thread for CAT 2013

MBA CAT 2022
3321
@pankaj1988 said:
OA-option AQ.9 ATTACHMENT Plz.
None?
3322
@deedeedudu said:
sin^2a/cos^a=sinacosasina=cos^3asin^2a=cos^6aNow2-4sina^2+3sina^4-sina^62-4cos^6a+3sin^4a-sin^6a2-3cos^6a+3sin^4a-(sin^6a+cos^6a)2-3sin^acos^a-(sin^6a+cos^6a)2-[(sin^6a+cos^6a)+3sin^2acos^a(sin^2a+cos^2a)]2-(sin^2a+cos^a)^32-1=1
@maddy2807 said:
@gs4890tana= rt(sina * cosa)(sina /cosa)^2= sina * cosasina = cos^3a--------->1cosa= rt(1-sin^2a)put this in 1sina= (1-sin^2a)^3/2open powers and you will get the solution
thank you bhai logon
3323
@pankaj1988 said:
OA-option AQ.9 ATTACHMENT Plz.
10..q^2+5q-150=0
3324
@pankaj1988 said:
OA-option AQ.9 ATTACHMENT Plz.
tried with differentiation ; got stuck :(

would have marked 4 in exam
3325
@gs4890 said:
tried with differentiation ; got stuck would have marked 4 in exam

differentiate q(c term ) diiff will be q^2+5q-150 simply q=10
3326
@pankaj1988 said:
OA-option AQ.9 ATTACHMENT Plz.

@maddy2807 @soumitrabengeri @Torque024 @mailtoankit @lopagargg @rachit_28
OA-NONE

Q10 MY LAST:
CHK ATTACHMENT
@gs4890 over 2 u bhai...who's is nxt?...
3327

Who want to be next ? Plz volunteer

Flow is gr8 at the moment

@deedeedudu bhai 😉 wat say ?

3328
@pankaj1988 said:
@maddy2807@soumitrabengeri@Torque024@mailtoankit@lopagargg@rachit_28 OA-NONE Q10 MY LAST:CHK ATTACHMENT@gs4890 over 2 u bhai...who's is nxt?...
bhai cant see the question... do sumthin
3329
@pankaj1988 said:
@maddy2807@soumitrabengeri@Torque024@mailtoankit@lopagargg@rachit_28 OA-NONE Q10 MY LAST:CHK ATTACHMENT@gs4890 over 2 u bhai...who's is nxt?...
9hours 12minures ?
3330
@pankaj1988 said:
@maddy2807@soumitrabengeri@Torque024@mailtoankit@lopagargg@rachit_28 OA-NONE Q10 MY LAST:CHK ATTACHMENT@gs4890 over 2 u bhai...who's is nxt?...
9hrs12min
3331
@pankaj1988 said:
@maddy2807@soumitrabengeri@Torque024@mailtoankit@lopagargg@rachit_28 OA-NONE Q10 MY LAST:CHK ATTACHMENT@gs4890 over 2 u bhai...who's is nxt?...
9hr12min
3332
@pankaj1988 said:
@maddy2807@soumitrabengeri@Torque024@mailtoankit@lopagargg@rachit_28 OA-NONE Q10 MY LAST:CHK ATTACHMENT@gs4890 over 2 u bhai...who's is nxt?...
9 hrs 12 mins
PS: Bhai abhi dont have any quest will contribute from tmrw for sure
3333
@lopagargg said:
10..q^2+5q-150=0
how ?

p = 1/3q^2 + 5/2q -150 + 75/q

dp/dq = 2/3q + 5/2 - 75/q^2 hua na yaar

plz clarify
3334
@gs4890 said:
9hours 12minures ?
u can read that?? :wow:
i''l post the next set of question bt need 5 minutes
3335
@maddy2807
I have magnifies it little...Hope it works....

3336
@gs4890 said:
how ?p = 1/3q^2 + 5/2q -150 + 75/qdp/dq = 2/3q + 5/2 - 75/q^2 hua na yaarplz clarify
Gotta multiply by q first coz average is given
after that differentiate
3337
@lopagargg said:
u can read that?? i''l post the next set of question bt need 5 minutes
Download and zoom.
3338
@pankaj1988 said:
@maddy2807@soumitrabengeri@Torque024@mailtoankit@lopagargg@rachit_28 OA-NONE Q10 MY LAST:CHK ATTACHMENT@gs4890 over 2 u bhai...who's is nxt?...
still i managed to get an ans...
is shud be 9hrs 12 mins if i copied the values wrng...otherwise...i cant do anything...
3339
@Torque024
@lopagargg
@maddy2807

volunteer plz !
3340
@gs4890 said:
how ?p = 1/3q^2 + 5/2q -150 + 75/qdp/dq = 2/3q + 5/2 - 75/q^2 hua na yaarplz clarify
bhai yeh cost average cost hai..total cost ke liye q multiply karna padega eqn se..then diffrentiate